@savvy22dew Nearest I can tell, you have mistake the "p" in this equation as a regular variable. It is actually the short hand for -log(). Thus p(Ka) = -log(Ka) and p(HA/A) = - log(HA/A). Log functions have a few unique properties, one of which is that log(X*Y) = Log(X) + Log(Y), which explains why
p(K * [HA]/[A-]) = pK - log [HA]/[A].
Sal has a proof of this concept on his website in the algebra section if you are interested in why this is so. Hoped that helped!
@rinwhr He makes a comment in a previous video that he makes some wrong assumptions in the last 3-4 min. So he made this video that just cut the last few minutes off.
For the dissociation equation of the conjugate base of the weak acid(A‾), wouldn't it be more appropriate to write it like this: A‾(aq)+H2O(l)↔AH(aq)+OH‾(aq) in order to balance the equation?
Nice buffers Anderson!
bigtopbollocks 4 days ago
Have to remember the name! I keep calling it the Anderson and Hasselhoff!
bigtopbollocks 4 days ago
thanks for the conceptual idea of hendersen hasselbalch but can you teach us ICE tables???
namanphoto 3 months ago
I have done HH a dozen times never even though it was derrived from the original equation
tks
jsmcrawler 4 months ago
as always thank you kindly for your great instructions. i was wondering, are you left handed? thanx
RISEofTIBET 4 months ago
ur awesome!!!!!!!!!
FarrahGreye 8 months ago
I love you Sal
hahs4 9 months ago
Did you distribute wrong?
for calculating the hendersen-hasselbalch eq.-
p(K * [HA]/[A-]) = pK k * [HA]/[A-] NOT pK - log [HA]/[A]
you can only distribute if the things inside parenthesis are added or subtracted:
6(3+2) = 6*3 + 6*2 = 18 + 12 = 30 and 6(3+2) = 6 * 5 = 30 so it checks out
you did 6(3*2) = 6*3 + 6*2 = 30 but 6*6 = 36. Not Equal!!
so i am confused. i think i explained why well enough, would someone clarify for me?
savvy22dew 9 months ago
@savvy22dew Nearest I can tell, you have mistake the "p" in this equation as a regular variable. It is actually the short hand for -log(). Thus p(Ka) = -log(Ka) and p(HA/A) = - log(HA/A). Log functions have a few unique properties, one of which is that log(X*Y) = Log(X) + Log(Y), which explains why
p(K * [HA]/[A-]) = pK - log [HA]/[A].
Sal has a proof of this concept on his website in the algebra section if you are interested in why this is so. Hoped that helped!
UnclePorkflaps 8 months ago
Did it get cut off at the end...?
rinwhr 10 months ago
@rinwhr He makes a comment in a previous video that he makes some wrong assumptions in the last 3-4 min. So he made this video that just cut the last few minutes off.
BF1 1 month ago
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fowlerfleming 1 year ago
I LOVE YOU!!! you are a great teacher, thank you thank you thankkk youu!
111000may 1 year ago
Comment removed
cylurian 1 year ago
Is this kinna old school paint or what?
baburo101 1 year ago
Nooooooooooooooo~~ It's too late.
I took the exam on this on the previous Monday...And I've done it wrong T_T.
But anyway, Thanks Sal
HutchaZ 1 year ago
For the dissociation equation of the conjugate base of the weak acid(A‾), wouldn't it be more appropriate to write it like this: A‾(aq)+H2O(l)↔AH(aq)+OH‾(aq) in order to balance the equation?
mrmagnetoman88 1 year ago
Remake? No, it's the same video.
norwayte 1 year ago
@norwayte He cut off the end since he said that volume doesn't matter.
Transpacity 10 months ago
hmm ive seen this before. still good tho
zackboomer 1 year ago 2
Thank You!
xpstkxps 1 year ago
Re-making your video?
Taowhr 1 year ago
Thank you Sal :)
Waranle 1 year ago
Thanks for the great videos
C00LBananas 1 year ago