Electric Field at the Center of a Semicircular Ring of Charge

[Pisceean]

awesome... just awesome

[solijoli123]

can you do for a quarter circle?

[9526772]

isn't it the dy/dx of sin is cos ???

[ltethan649]

@9526772 its the integral not the derivative

[jtrexr2]

What if we want the electric field not in the center of the semicircular ring of charge, but below the x-axis. Say, y = -2?

[DanieleGiorgino]

@jtrexr2

Then the x fields do not cancel and your summation would probably include an angle of some sort.

[darsheffect]

Hi and thanks a lot helped me a ton. I could not do it at the part of taking the derivative w.r.t the angle (I used to do it w.r.t length or radius. Thanks again.