I have a TOUGH question. Really tough for me at least. There are three games, each takes one token. You have 25 tokens. You play each game at least once. And you do not have to expend all of your tokens. How many different combinations are there?
a very useful video for an introduction into combinations, i'd like to say thanks very much for it. It would be quite useful if you covered some more fully worked examples of these types of problems. Seriously though, good job.
Though I didn't really sit down to take a good look. My best guess based off of this video's math would be the following:
You can have (6 choose 5)+(4 choose 0) is one set of the group's possible choices where men out number women. Another set would be (6 choose 4) + (4 choose 1). Finally, (6 choose 3 and 4 choose 2). Adding up all 3 equations would yield (as I understand) all ways of choosing 5 people where men out number women.
There is likely a more "elegant" way of doing this though.
Btw, if my answer doesn't make sense I can try to explain it fully. I would suggest watching the above video again for some more insight, but I have no problem explaining it further.
I have a TOUGH question. Really tough for me at least. There are three games, each takes one token. You have 25 tokens. You play each game at least once. And you do not have to expend all of your tokens. How many different combinations are there?
wutdaFU3K 2 years ago
well 3 of them are already choosen and after that each cud be 1 of three so im gessin the ans is 3^22?
jAcKfTtZ 1 year ago
a very useful video for an introduction into combinations, i'd like to say thanks very much for it. It would be quite useful if you covered some more fully worked examples of these types of problems. Seriously though, good job.
kristhetalen 3 years ago
Thanks, I try to keep the videos as short as possible, which limits my example choices, but I will keep that in mind.
Thanks for watching.
msj120 3 years ago
Thanks !!!
pdancegirl 3 years ago
can you plz help me with this question:
5 people chosen from 6 men and 4 women.
how do we calculate how many ways there can be more men than women?
thxx
pdancegirl 3 years ago
Though I didn't really sit down to take a good look. My best guess based off of this video's math would be the following:
You can have (6 choose 5)+(4 choose 0) is one set of the group's possible choices where men out number women. Another set would be (6 choose 4) + (4 choose 1). Finally, (6 choose 3 and 4 choose 2). Adding up all 3 equations would yield (as I understand) all ways of choosing 5 people where men out number women.
There is likely a more "elegant" way of doing this though.
msj120 3 years ago
Btw, if my answer doesn't make sense I can try to explain it fully. I would suggest watching the above video again for some more insight, but I have no problem explaining it further.
msj120 3 years ago
THXXXXXXXXXXXXX i finaly understood something from this chapter :)
pdancegirl 3 years ago
No problem, I am glad I could help. This is why I make the videos :). Thank you for letting me know it was helpful.
msj120 3 years ago
I think you have the correct flow of logic; however, that is not the correct answer.
msj120 3 years ago
And I am happy you enjoyed it.
msj120 3 years ago