Added: 2 years ago
From: acmeschool
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  • I have a question...

    I just came across with this video about fuel injection...

    Isn't it the airplanes use fuel injection as well?

    I have flown Cessna172 P models that they have carburetor and what I learned from the flight manuals is if I don't apply the carburetor at the certain altitude, the ice crystals might form in the throttle area which will allow less fuel to airplane engines. Then the fuel injection came and that eliminated the carburetor. Am I right? I just want to verify my self.

  • @Shipocute add electro mechanical anything and it still outlives the retarded midget and his theorized hacked up pules width burn by a sunstorm bird fart injector. Try a resistor grounding to a top bolt at the carb. The last of carbs are lit up by a resistor choke, the choke does nothing but protect the barrel after shutdown. The original carb used a choke because the barrels were dead. non electrical primitive..The carb finished off teaching a market scandal what injection is.

  • Excellent! Video. Thanks.

  • lol, remember this programme

  • Very nice video, the best, simplest one I have ever seen on fuel injection. Well done!

  • Great video, one of the best tech videos I have seen.

  • Fucking great video.

  • OMG, talk about Old School. Was this like 1989? The guy sounds mad that Fuel Injection was invented. It's a good source of info, but it seems like the guy is saying that Carburation is better. Does it seem that way to anyone else? Of course he contradicts what he was saying at the end....

  • Comment removed

  • i finally learned exactly how and EFI works ! Keep it it

  • You Say, 14.7 % of Air and 1% of fuel, but in a cilinder of 163CC

    14.7% = 23,961cc of air

    1% = 1,63cc of Fuel

    What is the other 84.3% = 137,409 ??? Thanks

  • Hi arthus1971,

    Whoops. It's a RATIO of 14.7 to 1, so out of 15.7(as 100%), it's 14.7 over 15.7 times 100 air (93.63%) and 1 over 15.7 times 100 (6.36%) fuel.

    In simpler terms, 14.7 parts air to 1 part fuel. Clear as mud, right?

    David

  • @acmeschool Thanks David, Is Correct!

    This is the stoichiometry of the combustion

    1 Part of Fuel is 6.36% Of Fuel in the Cilinder (In gas state)

    14.7 Parts of Air is 93.63% Of Air in the Cilinder

    This 93.63% of Air have: 20.94% Oxigen - 78.08% Nitrogen

    0.035% Carbon Dioxide and 0.93% inert Gases

    Did you know how to convert or calculate, this Part of fuel from gas state to liquid state or viceversa, I just need to know , the equivalence between gas fuel and gas liquid, thanks again!

  • @acmeschool are you the guy in this program?

  • nice, well done up for you.

  • I've *heard* most of the content of the video before, but nobody's shown it as well.

    Explanations are excellent too. Thanks.

  • Great video, the explanation was quite clear. I am planning to run an EFI system on my old 78 carb car... basic understanding of the process is the 1st step... thanks mate!

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