I Love this Video and also I checked out your Channel. Very interesting! If you need any help getting this Video and your Channel exposed to were it is top in all the search I found this site called tubeviews.(net) that has took my breath away. I'm working on my 4th Channel now, this one I just made. My Videos are getting so many hits now. Check it out and keep in touch.
very nice... 1st 3 area of parallelogram is equal to 1, one can determine that a=1 regardless of it's area, to sum it up it should always be equal to 1 :p
Imagine a parallelogram WXYZ whose point W lies on the cartesian origin. Given the length WX, the length XY, and one interior angle θ, find a function which solves for 'a'. That find a function f(WX,XY,θ)= a, where 'a' is the total number of inscribed integral vertices.
This one kept me up till 3 in the morning yesterday. I see that the this funktion clearly works on every trial, but I can't anderstand why. In other words, I can't figure ou why it should apply to every parallelogram.
Your comment has been given a low rating (not by me). I guess that means you did not learn this in second grade. Don't you just hate democratic subjectivity?
ze dependance of ze aria on zi numba B.
lazimofo90 1 year ago
I wish I knew this when I was in school. would of helped me on many problems
jazzophis 2 years ago
omg math shit it burns it burns hahaha!!
Chrisoo9 2 years ago
thanks
speedproductions797 2 years ago
This has been flagged as spam show
I Love this Video and also I checked out your Channel. Very interesting! If you need any help getting this Video and your Channel exposed to were it is top in all the search I found this site called tubeviews.(net) that has took my breath away. I'm working on my 4th Channel now, this one I just made. My Videos are getting so many hits now. Check it out and keep in touch.
Thomas, Snellville, Ga
Shaynaxqz 2 years ago
Hi sergei,
what kind of software/hardware do you use to record these videos?
Kind regards!
jci 2 years ago
very nice... 1st 3 area of parallelogram is equal to 1, one can determine that a=1 regardless of it's area, to sum it up it should always be equal to 1 :p
koolyoh213 3 years ago
Imagine a parallelogram WXYZ whose point W lies on the cartesian origin. Given the length WX, the length XY, and one interior angle θ, find a function which solves for 'a'. That find a function f(WX,XY,θ)= a, where 'a' is the total number of inscribed integral vertices.
bluesrunthegame 3 years ago
i liked how you used the term cartesian origin (0,0) often times people call it rectangular...just saying.
dynamiz77 2 years ago
This one kept me up till 3 in the morning yesterday. I see that the this funktion clearly works on every trial, but I can't anderstand why. In other words, I can't figure ou why it should apply to every parallelogram.
Could you prove it? 'Cause I'm stuck...
Alhoshka 3 years ago
This comment has received too many negative votes show
i learned this in second grade:))
sikyrace 3 years ago
Your comment has been given a low rating (not by me). I guess that means you did not learn this in second grade. Don't you just hate democratic subjectivity?
bluesrunthegame 3 years ago 5
well i did...i am from romania and here , school is hard work ;)...
sikyrace 3 years ago