Belive it or not Free energy is real,But there are very powerfull forces that want to supress the technology,Get the blueprints for a free energy motor at LT-MAGNET-MOTORdotCOM ,take part in the revolution!
LAW 5: Magnetic field produced per mass of conductor is proportional to [length of conductor * current] / [length of conductor * area cross-section of conductor], or simply current / cross-section of conductor.
LAW 4: The magnetic field energy divided by electrical power is proportional to [length of conductor*current]^2 / [current^2 * resistance] or length of conductor^2 / resistance. If length of conductor is proportional to resistance, then the magnetic field energy produced per electrical power is simply proportional to the length of that wire.
LAW 3: The magnetic field energy produced per copper mass is proportional to the [length of conductor * current]^2 / [length of conductor * area cross-section of conductor]. This can be simplified as current^2 * [length of conductor / area cross-section of conductor].
LAW 2: The magnetic field produced per electrical power is proportional to [length of conductor * current] / [current^2 * resistance], or simply [length of conductor] / [current * resistance].
Note I said product of current and resistance, not voltage, since doubling current can be done at the same resistance and voltage by putting two batteries in parallel.
You will be doubling the resistance of the circuit by connecting them in series. If you use the voltage sources from both machines and connect those in series, the current throughout the whole system will be the same. But then these machines will have to be synchronized, when the circuit is closed, both will have to kick. Newman machines do this by converting mass into energy. The thing being converted into energy is the mass of the coil. I don't know if the electrons loose mass too.
Not electrically in series, but mechanically in series--use the mechanical rotation of one to rotate the shaft of the other. If you apply mechanical work to the shaft of an electric motor, you will generate a current (like a turbine). So if you apply mechanical work to a Newman machine, won't you be generating new mass? What if the source of mechanic energy for generating new mass is another newman machine?
Newman machines are quite strange in this regard, since, according to jnaudin.free fr/html/NMac0709.htm, a cooling effect has been observed even with one machine by itself, implying the conversion of heat energy into mass. If this is true, then turning the rotor of one Newman machine by using another Newman machine would create a cooling effect as well.
Thanks for the info. Why does observation of a cooling effect imply the conversion of heat energy into mass? How do you decide which machine is the mass producer and which machine is the free electricity generator? It seems that this system would be symmetric in this regard.
If the machine becomes cooler and generates a gain in energy then what regulates the rotational velocity of the shaft? If the machine becomes cooler then we should expect an increase in efficiency over time. As efficiency increases then we should see dP/dt > 0. Or, the output power should increase and ACCELERATE the shaft. But in Newman's video the shaft rotates at constant velocity. Why is that?
The magnetic field strength of the coil regulates the speed of the shaft. If it is weak, there is little force, so it will rotate slowly. If it is strong, then there will be more force. According to the link I provided, the cooling effect reaches a limit (e.g. it does not attempt to go subzero or anything like that), so I would not expect an constant climb in efficiency.
The magnetic field produced per current is proportional to the volume of the conductor material used. The ratio of magnetic field produce per electrical power is therefore: volume of [conductor volume * current] / [current^2 * resistance] or [conductor] / [current * resistance]. The length of the conductor is proportional to its resistance, but then the current drops inversely. That's is how get more OOMPH our your power. Beef it up good!
Correction: Magnetic field produced per current is proportional to the length of the conductor used by all that current. Therefore, the ratio of the magnetic field produced per electrical power is: [length of conductor * current] / [current^2 * resistance], or simply: [length of conductor] / [current * resistance]. The length of the conductor is proportional to its resistance and increasing it drops current inversely.
This has been flagged as spam show
Belive it or not Free energy is real,But there are very powerfull forces that want to supress the technology,Get the blueprints for a free energy motor at LT-MAGNET-MOTORdotCOM ,take part in the revolution!
lavernedi 1 year ago
Nice english...
Ztuibyman 4 years ago
Suomesta näytät olevan. Niin olen minäkin! Katso minun moottori, se ei ole Newmanin mutta Bedinin moottori, nykyään tekemässä parempaa!
Careica 4 years ago
LAW 5: Magnetic field produced per mass of conductor is proportional to [length of conductor * current] / [length of conductor * area cross-section of conductor], or simply current / cross-section of conductor.
kmarinas86 4 years ago
LAW 4: The magnetic field energy divided by electrical power is proportional to [length of conductor*current]^2 / [current^2 * resistance] or length of conductor^2 / resistance. If length of conductor is proportional to resistance, then the magnetic field energy produced per electrical power is simply proportional to the length of that wire.
kmarinas86 4 years ago
LAW 3: The magnetic field energy produced per copper mass is proportional to the [length of conductor * current]^2 / [length of conductor * area cross-section of conductor]. This can be simplified as current^2 * [length of conductor / area cross-section of conductor].
kmarinas86 4 years ago
LAW 2: The magnetic field produced per electrical power is proportional to [length of conductor * current] / [current^2 * resistance], or simply [length of conductor] / [current * resistance].
Note I said product of current and resistance, not voltage, since doubling current can be done at the same resistance and voltage by putting two batteries in parallel.
kmarinas86 4 years ago
LAW 1: Magnetic field produced per current is proportional to the length of the conductor used by all that current.
kmarinas86 4 years ago
So what happends if you connect two Newman motors in series? Will one convert mass into electricity while the other converts electricity into mass?
xxmrrickxx 4 years ago
You will be doubling the resistance of the circuit by connecting them in series. If you use the voltage sources from both machines and connect those in series, the current throughout the whole system will be the same. But then these machines will have to be synchronized, when the circuit is closed, both will have to kick. Newman machines do this by converting mass into energy. The thing being converted into energy is the mass of the coil. I don't know if the electrons loose mass too.
kmarinas86 4 years ago
Not electrically in series, but mechanically in series--use the mechanical rotation of one to rotate the shaft of the other. If you apply mechanical work to the shaft of an electric motor, you will generate a current (like a turbine). So if you apply mechanical work to a Newman machine, won't you be generating new mass? What if the source of mechanic energy for generating new mass is another newman machine?
xxmrrickxx 4 years ago
Newman machines are quite strange in this regard, since, according to jnaudin.free fr/html/NMac0709.htm, a cooling effect has been observed even with one machine by itself, implying the conversion of heat energy into mass. If this is true, then turning the rotor of one Newman machine by using another Newman machine would create a cooling effect as well.
kmarinas86 4 years ago
Thanks for the info. Why does observation of a cooling effect imply the conversion of heat energy into mass? How do you decide which machine is the mass producer and which machine is the free electricity generator? It seems that this system would be symmetric in this regard.
xxmrrickxx 4 years ago
If the machine becomes cooler and generates a gain in energy then what regulates the rotational velocity of the shaft? If the machine becomes cooler then we should expect an increase in efficiency over time. As efficiency increases then we should see dP/dt > 0. Or, the output power should increase and ACCELERATE the shaft. But in Newman's video the shaft rotates at constant velocity. Why is that?
xxmrrickxx 4 years ago
The magnetic field strength of the coil regulates the speed of the shaft. If it is weak, there is little force, so it will rotate slowly. If it is strong, then there will be more force. According to the link I provided, the cooling effect reaches a limit (e.g. it does not attempt to go subzero or anything like that), so I would not expect an constant climb in efficiency.
kmarinas86 4 years ago
The magnetic field produced per current is proportional to the volume of the conductor material used. The ratio of magnetic field produce per electrical power is therefore: volume of [conductor volume * current] / [current^2 * resistance] or [conductor] / [current * resistance]. The length of the conductor is proportional to its resistance, but then the current drops inversely. That's is how get more OOMPH our your power. Beef it up good!
kmarinas86 4 years ago
Correction: Magnetic field produced per current is proportional to the length of the conductor used by all that current. Therefore, the ratio of the magnetic field produced per electrical power is: [length of conductor * current] / [current^2 * resistance], or simply: [length of conductor] / [current * resistance]. The length of the conductor is proportional to its resistance and increasing it drops current inversely.
kmarinas86 4 years ago