@EvgenijM86 Sal is applying the projection to the first column of the identity matrix (the "x" basis vector [1 0]). The projection formula was already defined to be (vector_to_project "dot" unit_vector) * unit_vector. In this case vector_to_project is the "x" basis vector.
I've come to think of the dot product also as the projection of a onto b, as if b was a unit vector, but with that projection scaled to times the length of b
Gracias.
s0m0c 2 months ago
@EvgenijM86 Sal is applying the projection to the first column of the identity matrix (the "x" basis vector [1 0]). The projection formula was already defined to be (vector_to_project "dot" unit_vector) * unit_vector. In this case vector_to_project is the "x" basis vector.
LAnonHubbard 8 months ago
Great lectures.
V2PRC 1 year ago
excellent
97021840 2 years ago
I've come to think of the dot product also as the projection of a onto b, as if b was a unit vector, but with that projection scaled to times the length of b
alkalait 2 years ago
I think I understand your thinking, but the dot product give us a scalar, so it can't be a projection, right?
gekorio 2 years ago
yes, apologies. the projection is a vector, my mistake. replace the word "projection" with "length of projection", to what I said before.
alkalait 1 year ago
(y) 5 stars
joeyjoey1122 2 years ago