Lec 23 | MIT 18.06 Linear Algebra, Spring 2005

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[Ondelendo]

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[willamricard]

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[thesameidiot]

why does nice have more likes than Awesome?

[RoxanaCarlajw490]

najo einzige deutsche hier

[Saudi00Style]

I wish I had professors like him... I would have been greater mind!!

[akhil089]

thanks professor gilbert

[bud389]

if i had this class........ i would fail it.

[RippedWookie]

@bud389 lol

[zanngoc]

@bud389 i am about to do that! :S

[hypnoticpoisons]

36:21 how can sum(x^n) be 1/(1-x), that is obviously too small

[pelemanov]

@hypnoticpoisons I think x is limited to numbers between 0 and 1

[hypnoticpoisons]

why is |e^(6it)|=1?

[Yakeyglee]

@hypnoticpoisons Because e^(6it) = cos(6t)+i sin(6t), which always has a modulus of 1.

[TheDareDevil2510]

These lectures are awsome. Strang makes Linear Algebra seem so easy - completely oppisite of his "colleagues" at my university. I've stopped attending their lectures in favour of these. Thanks MIT (W. Gilbert Strang)!

[TheTurkosem]

@TheDareDevil2510

+1

[Chrisfathead]

this man singlehandedly made me pass linear algebra from youtube

[Chrisfathead]

i want to have Dr. strang's babies. and I am a man

[1904home]

very cool.

[thedeathofbirth]

I watch his lectures with the same interest when my favourite movies are on !!! That's how capable this man is, in clear explanation w/o any assumption of the initial knowledge of his global students, he lectures for all, and everyone takes something special from his lectures! way to go Dr.Strang!!!

[Johnnymatics]

Great! What a gifted Professor, thank you Dr. Strang!

[alquiora]

Thank you for explaining the "unit circle stability region". I had been puzzled by the reason behind the "stability" for a long time before I watched this!

[sbhdgr8]

I have a question if someone could answer it;

right at the end of the lecture where a second order diff. eqn is converted into a 2x2 matrix called A;

while defining the matrix A, shouldn't element A22 be= -k/b since on rearranging the given eqn and solving for y' we get y'= - (1/b) *y"/b - (k/b)* y; so since the coefficient of y is -k/b ; shouldn't this coefficient correspond to element A22 of the 2x2 Matrix A?

[Weightlifeter]

@sbhdgr8 you substitute z=x^2 so the higher power "quadratic" equation can be written as a actual quadratic equation az^2+bz+c.

[Weightlifeter]

@sbhdgr8 No. He's trying to write the second order differential equation as a system of first order linear equations, or basically you are just substituting y'=some variable, basically just manipulating the expressions so the 2nd order equation is "transformed" into equations of first order. The matirx of coeffiecients represents the coefficients of the "transformed" resulting system of 1ST order linear equations. It is the same idea as substitution in quadratic equations like ax^4+bx^2+c, and

[JacobSimms]

Anyone else have a little trouble with the sound?

[rammps1982]

Awesome

[mushfiq951]

nice