1 + 1 = 0: The Proof!

[vidiosyoutubi]

But, 1-1 = 0 Oo, On My Math Is...

[V0LvicC0CO]

1:30

sqrt1 = -2*i fail^^

[khrismarts24]

WHAT?? 1 + 1 = 0 ????

even my little brother knows the right answer cause I thought him,

the answer is 3 right??

[Hottygirl991]

MY brain hurts

[pandatrueno1]

@ MrAlexGTV

I'm personally aware of the fact that that particular assumption is wrong, as pertaining to -1's, but it is correct for EVERYTHING else as far as I'm aware, so if you then replace the "-1" with an A or whatever... it'll work... either which way, cool story bro, needs more ponies :D

[ACherriePie52]

I take it that you got a degree in Mathematics

[MrAlexGTV]

Your assumption is wrong. sqrt(-1)sqrt(-1) DOES NOT EQUAL sqrt[(-1)(-1)].

[RockComicsKid]

Yes, it's simple. For example, if you have one guitar, and buy another guitar, you have 0 guitars!

[kiltboy100]

can't have the sqrt of a negative number

[niel4234]

i dident get any of that

[roni45ul]

ok, if you have 1 apple in left hand and 1 apple in right hand, you put them on the table and you see here 0 apples???? NO there are 2 ,, so 1 + 1 = 2 you cant lie noone ;))

[MyVideoHubOnDell]

@roni45ul Dude, this isn't elementary arithmetic.

[roni45ul]

@MyVideoHubOnDell Who care, just im telling that 1 + 1 = 2 :))))

[warhero260]

omg to much math

[benitaann]

10x10-100

[TheCobraagent]

I am pretty sure this has been posted before but because people are asking... The mistake is at 1:41. sqrt(ab)=sqrt(a)xsqrt(b) only and only if a,b are both positive

[andresgoens]

@TheCobraagent not quite :) sqrt(0) = 0 = sqrt(0) sqrt(0), so it's if they're non-negative

[TheCobraagent]

@andresgoens True

[XvWBlink182WvX]

That's 1 plus the square root of 1-_-

[Boodriegon]

Yea, I have no idea what any of this means.

[samyrolla34]

what?

[glenjacobs423]

1 + 1 = 0

Can be true only when 1 = -1

ie a = -a

Now

a = sqrt(-a x -a) ≠ sqrt(a)i x sqrt(a)i

if it were equal to RHS then that would mean that a = -a

which is not true as the minus sign gets converted to plus inside the root sign.

[kodo690690]

lol 1+1=2 1+1=0 1+1= -2

[motonegros]

gary numan?

[spinky005]

Here's a solution to this DIFFICULT equation.

1+1=2

1-1=0

If you'd like a detailed explanation, ask your nursery teacher

[neeger123f]

actually 1 +1 = 1,because if you have 1 pile of sand and another pile of sand and you push them together you still get 1 pile of sand.

[ChristopherBPople]

The flaw is that sqrt(ab) != sqrt(a)*sqrt(b) if a or b < 0.

[Littlemanjan]

Lets refer back to kindergarten...1 apple plus 1 apple equals two apples

[123Magick123]

poor guy... READ THE DESCRIPTION!

[xAngeloftheDevilx]

bring your to index fingers together. ad those two fingers.

= 2 fingers

1 finger + 1 finger = 2 fingers

=D

[Virgin006]

@xAngeloftheDevilx but if the one finger fights with the other finger and both die, there are 0 left. so this proof is correct =D :D =D :D i'm drunk u know

[toleshaOG]

This video proofs only that your mother is a bitch!

[nk1218]

Good Job! I was tricked. But as many of you know, I finally found out that in complex mathematics, sqrt(a)xsqrt(b) is not sqrt(ab). That was interesting....

[thatVietnameaseGuy]

surely if you are assuming that 'i' is the square root of -1 then it is a non existent number? 

[YZB25]

@thatVietnameaseGuy when he said "I" he isn't talking about it in an algebraic term he's talking about imaginary numbers... look it up.........

[91fzn]

whatever is it , i agree with u

[Mrkmich85]

(ab)^1/2 not a^1/2*b^1/2 on complex numbers!

[PringDaddyPring]

1 +1 = 0 is perfectly valid if you are in the Prime Field F2, lol...

[setnoset]

since the assumptions are stated, the argument is valid, but not sound, since, as TheMuffinChef has pointed out, "√a×√b =√ab is only true for real numbers".

[RuneDillen]

the problem is that the complex number is not defined as sqrt(-1), since a square root of a negative number doesn't exist.

The complex number can only be defined as this: i² = -1

You can not replace it by sqrt(-1), only by -1/i

[ArkiveX]

You're using the fact that sqrt(1) = 1 OR -1

From there, to solve anything you use logic to deduce the correct answer

[buyneee]

1 + 1 = window

[shaider1982]

To multiply i and i, you get back to the definition where in you end up with sqrt(-1*-1). Which is sqrt(1). so 1+1 is still 2.

[esraretin]

1+i not = 1+sqrt (-1) it is =1+i...because if it is so we wouldnt use i to show its imaginary number.

1+i +-1-i=0

there is no imaginary number like 2+2.its 2+i.i always exists if u say imaginary. only u can erase i with i-i.nothing works except this

[aboctok]

@esraretin nice comment

[esraretin]

@aboctok thank u

[demiselol]

you cannot open the sqr(-1)(-1) to sqr(-1) * sqr(-1) , sqrs have to have possitive numbers. While (-1)(-1) is a possitive number, (-1) on its own isnt.

[gerardtong230796]

although theoremly this is right for complex number, but think about it. The big bang of the universe cant form from nothing,so you said 1+1=0,another way.0=1+1,0 equal to the source of universe nothing? and 1+1 is all the matter in the universe. so Univere cant form from nothing,and 1+1=0 is not so make sense

[X3BOOODYX2012]

1 + 1 = 2

WTF is wrong with you people? even apes can do it!

[ThePoshMaster]

@X3BOOODYX2012 U don't want to admit that you're bad at math and have no clue what this theory is.

[ThePoshMaster]

@ThePoshMaster Jk, no offense. However, this theory is pretty neat.

[rasmussaj]

i had 1 apple. then i got 1 more. now i dont have any apples for some reason...

[awsomeperson4eva999]

wait... what?!

[THExMIGHTYxMORA]

I'm sticking with what makes sense... 1+1=2

[SophieEpic]

1+1 is NOT 0!!!! 1 MINUS 1 is 0 but not plus 1

[nejtilsvampe]

@SophieEpic haha xD

[KuggeR23]

to people arguing with this, let I be 1 and II be 2... I and add I will be II, that means 1+1=2

moral lesson: don't make your life complicated.

[ICU2P]

obviously you've taken "sqrt(-1)" as something that is possible... 

[sliles69]

skip to 3:18 to miss three minutes of boring music and ridiculously slow maths

[ApostateOfTheDamned]

@sliles69 damn wish i read you're comment sooner

[gyinagal]

@pureexile

Very clever! Unfortunately, the square root property you cited only applies to positive numbers. So sqrt(1) does not equal sqrt(-1x-1). Also, unfortunately, that other guy is right. When you take the square root of any number x^2, the result is positive x and negative x. We write this as plus or minus x.

[suit1337]

@2:59: whatever you say is wrong 1 + (-1) = 1 - 1 = -1 + 1 = 0

"order of operations" and commutative property" - you drop around with square roots and exponents but don't even have a clue of fundamental basics

[kennyasierra]

dude you suck! try to be right before you make a stupid video

[TheVchunter]

The property of square roots says sqrt of a and b equals sqrt of a times sqrt of b if and only if both a and b are real numbers and positive. This means a and b must lie in the domain of R+.

[DaylightDigital]

You forgot the plus OR minus when taking the square root. This isn't amazing, it's just amateur mathematics.

[PureExile]

@DaylightDigital √1=1. There's no pluses or minuses involved. It's just amateur mathematics.

[Crumbsm8]

@PureExile (-1)x(-1)=1, 1x1=1

√1= 1 OR -1

[redpillreality]

@PureExile sqrt 1= (1)(1) OR sqrt 1=(-1)(-1). you do need +or- because

sqrt 1=(-1)(-1) is a valid answer.

[UnitedHaxors]

@PureExile square root of 1 is 1 and -1

[JotesCreations]

@PureExile there is. -1*-1 is also 1, so √1 is -1 and 1.

[blazingsungt]

@PureExile Tell me then, what does (-1)^2 equal?

[PureExile]

@blazingsungt (-1)^2=1. Obviously all positive real numbers have two distinct square roots but the square root function √ only refers to the positive root.

[Xshado2]

@PureExile when you square root anything, it becomes ± that thing.

[TheDev142]

no number can be multiplied by itself to get -1 or -2 or -3 and so on :/ so the squareroot of -1 doesn't exist bitch

[clyrenternal]

@TheDev142 Read up on complex numbers and then come back and say what you just said.

[LamaPaj]

@TheDev142 Imaginary numbers. And do not let the name fool you. They are very real and are used in the real world.

[GuiihF]

não entendi porra alguma! AHUUAHAHUUHA

[00PurpleGirl00]

I have no idea what they're talkin about lol I hate math I have no ideea why i came to this Vid lol

[wavey61]

@00PurpleGirl00 This is just Algebra, if you've never taken it, then it's probably jibberish

[luedtke6]

the relation started as 2=2 and ended in 0=0.



[TheSorsastaja187]

how the hell did i get here from plane crash videos?

[vampyr0ck]

jamas habia desperdiciado mi tiempo  tan absurda mente

[RedRad1990]

@rstryker27 0:30 " Assumptions: i=sqrt(-1) "

[Rustyy444]

@rstryker27

the square root of -1 is i. he just subs them in

[camfunme]

the equation square root (1) = 1 is false its actually = + or - 1

[Nelsonjb20]

whoever made this video is clearly stupid

[rreejjaaii]

@Nelsonjb20 no its just to complex for you to comprehend

[miniben8]

witchcraft

[huepix]

Even better is my god equation. Infinity to the power of zero equals one. Of course its nonsense but hey, only nothing is infinite and all things are one. so meditate in that. I like to point this equation out to budhists then sit back and watch them ponder and then their heads explode. If 1x(a-a) = 2x(a-a) then we take a-a from each side of he equation we are left with 1=2. or if a cow eats 2 Kg of sawdust per day, how many days before it can deficate a peice of 4x2 three feet long. Peace out

[Milamberable]

The problem flaw is here:

sqrt(-1) is not defined because i^2=-1 but also (-i)^2=-1, therefore it would be impossible to decide if sqrt(-1)=i or sqrt(-1)=-i :)

[MrNekoSuzu]

But if I take one apple... and I take one more apple... and I put them side by side... I have two apples. You lose, sir.

[halfblood47]

@MrNekoSuzu root the apple! behind u ;) now u got an imaginary apple!

[A0710474]

man the trick is in sqrt[(-1)x(-1)].... it's simply sqrt[(-1)^2]... and by definition:

sqrt(x^2)= |x| so sqrt[(-1)^2] = |-1| = 1 and you'll have 1+1 = 1+1

actually this needs a further explanation... but man math isn't about mathematical symbols... it's about their meanings try say what you've written in words and you'll find the trick

[Mveliz3556]

Soo, 1 car + 1 car = 0 cars ? This is stupid!!

[TechnoJon96]

@sinojtjej Yes you can. It's called imaginary numbers and it's a fundamental aspect of complex math. Do your homework before posting, please.

[Rustyy444]

@sinojtjej

its called a complex number, i. do some research before you try to prove us wrong

[PensaC0L4]

@1FANICA

i^2 = i x i = sqroot(-1) x sqroot(-1) = sqroot[(-1)x(-1)] = sqroot [1] =1

This is a number on imaginary axis and he use the trick with distribution property of roots

That prove school is good...very good indeed.

[race548]

If you work with Imaginari numbers it will lead up to 1=-1 which is a false proposition meaning your theory is not true, if you work with number from R then you can't have sqrt((-1)*(-1)) because although it ecuals 1 iti s equivalent with sqrt(-1)*sqrt(-1) which dose not exist.

[1Fanica]

Sqrt(-1) isn't possible, the number has to be positive

[moudyfouani]

nahhhhhh  your tottaly wrong ...

[CrazyMoDx]

you are changing the formula !!

[chrishitlicious]

Stupid theory. Just imagine, if there is 1 apple + another 1 apple, it would be 0 apple? NO, dumbass

[TechnoJon96]

@chrishitlicious FAIL You should READ THE DESCRIPTION

[Aterraadastra]

There should be reaction for "EPIC FAIL", that's what I would have chosen.

[pantysniffer99]

mod 2

[danny181997]

You basically summed up that 1 = -1. Fail.

[mydogrulz3]

What?

[sorakairi60]

@dethbypotato lmfao!!!!!

[multitacoman99]

i dont get it :(

[TheMuffinChef]

This is what they attempted:

1. The equation (eqt.) is true: 1+1 = 1+1

2. Since this eqt. is true: √1 = 1, then 1+1 = 1+√1

3. Since 1 = (-1)(-1), then 1+1 = 1+√(-1)(-1)

4. Since the eqt. is true: √a×√b = √ab, then 1+1 = 1+(i×i)

5. Since i² = -1, then 1+1 = 1-1, so 1+1=0

This is why it is false:

The eqt. √a×√b =√ab is only true for real numbers. Because √-1 or "i" is not a real number, √(-1)(-1) ≠ √(-1) × √(-1).

[MrGOTAMA420]

@TheMuffinChef imaginary numbers are fun but not real

[seventhmetro]

@TheMuffinChef Are you by any chance my math teacher?

[gmondrax]

@TheMuffinChef Thanks.. thas was fasst jaja :)

[Ldinos]

@TheMuffinChef what a comment, my god.....

[wwebiggestfanme]

1-1 = H

[dydedlinde]

2(a-1)=3(a-1) if a= -1 then you can say 2=3...

[AriArk2000]

1+1-? (counts on fingers XD) I have 2 fingers up

[jjashmor]

You forgot the absolute value signs...

[jetairways77]

the suqre root of -1 is i.

[hhaallehhaallee]

i just wasted 3:51 min of my life.. shit..

[ElectroMagneticWeak]

You were doing operation within the set of real numbers, then you started applying the operations of real numbers to complex numbers; how can this not be wrong?

[rubikmania98]

so when I have 1 apple, and then I buy 1 more apple.

I get none?

[epicKiipa]

1+-1=0 Ya stoopid

[Mynamesnigel]

why do people actually discount logic? I have 1 apple. I buy 1 more. I have 2 apples.

[marcieandbrooklyn15]

Woah now dude!! Wait a darn minute. If I buy 2 pieces of chocolate I get NONE!!?? O.o 1 Piece O + O 1 Piece = OO So I have 2!

[Slyzer1990]

popo9697 is right

sqrt(a*b) = sqrt(a)*sqrt(b) is only defined for positive a and b

you are not allowed to use them on complex numbers or negative a or b

[popo9697]

sqrt(-1)*sqrt(-1) doesn't equal sqrt[(-1)*(-1)]

[FlyWithCheese]

The dumbass who mad this needs to take a Grade 1 Math class

[dethbypotato]

oh i get it. cuz if i buy 1 cookie and then another ill eat them and have 0 :)

[VandeputteThomas]

The mistake is already made in the assumptions. i doesn't equal sqrt(-1). The only true assumption is i²=-1 so i=sqrt(-1) OR -sqrt(-1)!

[arit34]

sqrt = squirt...thats is your answer

[sorakairi60]

That was in response to ultrastatic100... My fail...

[sorakairi60]

First of all, sqrt (ab) DOES = sqrt(a) * sqrt(b). Think about it. Secondly, the square root of a negative number can be represented as i, a very basic algebra concept. It's not a real number, but still represents what's called a complex number

[flaviusclaudius7510]

@sorakairi60 That statement is only true if one of a or b are non-negative. If they're both negative, you derive a contradiction (as demonstrated in this video), and the subsequent video response.

[xCTFx]

2:53 Good job dumbfuck, 1-1=1-1

[TheApostolis1996]

that's true only with the usage of "i" which is a Complex number

[TheApostolis1996]

2:26 ixi= 1 not -1 :(

[MacWonk]

i don't get it. What did you prove? That 1-1=0?

[Zzasr]

1 + 1 is not the same as 1 + √1. It will give you the same answer but it aint the same.

[wotchadave]

You have to keep the same roots in the √1. If you're saying √1 = -1 for one side, you must keep the same root for the other.

[shabalakaboka2]

dude... go to school

[Musikfabrik]

i dont know what this shall be , in my mind only crap, if i cut one of your fingers i got ONE, if i cut another finger of you i got TWO ...lol or you think u got all fingers still ? then let me cutt of 2 of your fingers ^^

[ultrastatic100]

there is no sqrt(negative) in math !

[gedizzs]

you cant do sqrt(-1)

[cmaddex]

@gedizzs actually you can, sqrt(-1) = i, the imaginary number. the flaw is in doing the exponent before parentheses pemdas = parentheses,exponent,multiplic­ation/division,addition/subtra­ction, and so

(-1*-1)^(1/2) != (-1)^(1/2)*(-1)^(1/2)

[ProfessionalDummy]

You lost me after sqrt [(-1) (-1)]

[TheDaKSn]

you are stupid 1+1 is not 1+sqrt(1)

[colejohnson66]

You can't manipulate pemdas like that. Parentheses before square rooting!

[colejohnson66]

You changed sqrt(-1*-1) to i^2. You can't do that. That is sqrt(1) which is not i^2. Take that from college

[lavabone]

You misspelled the title. You meant to put 1- 1 = 0.

[zicalser]

Quem ta aqui pelo broundouglas e pensou que poderia ser algo relacionado com o protagonista da joinha!

[poslol]

@zicalser

sim HAUHAUHA

[SarahFreshiieTSweetz]

@zicalser huh ?

[BludnmunyProductions]

3:11 - Yes, 1 - 1 = 0. Good for you.

[Priesty77]

Wrong! That's a F-

[TheGSPFilms1]

your making mathematicians look like idiots

[arismagica]

can you put a -1 in a sqrt .....i think that the number must me >or equal to 0

[skoockum]

the glaring flaw is that sqrt[(-1)(-1)] -- which is sqrt 1, which is 1 -- does not equal sqrt(-1)xsqrt(-1) -- which is [sqrt(-1)]^2, which is -1.

[elzoog]

@skoockum

Basically, the flaw in the entire proof is that actually the sqrt(x) always has two different values. The sqrt(1) can be either 1 or -1. You can check (-1)^2 = 1 for verification of that. So, sqrt(ab) = sqrt(a) * sqrt(b) is true, but you have to be careful. Since the sqrt(ab) = sqrt(a) * sqrt(b) this means that sqrt((-1)*(-1)) = sqrt(-1) * sqrt(-1) This equation is actually true when you consider that -1 is a sqrt(1). The sqrt(-1) is also -i so sqrt((-1)(-1))= -i * i = 1

[tpchuckles]

the issue is in the fact that the square root of something can be either positive or negative.

[iswmfastr]

2:56 dude You just proved 0 = 0

[MrBigEnchilada]

@Illessaa actually sqrt(-1) is defined as i, because there are many applications where you can use the negative root. this proof is wrong though because 1 + 1 cant equal 0 ....

[narutoshippudenclara]

lmfao literally just learned about complex number system, yet somehow the teacher went on a rant and finished with how humans are equivalent to crows...

[skoockum]

@narutoshippudenclara tell me that your instructor wasn't Rich Bigler

[narutoshippudenclara]

@skoockum no

[yoshijjb]

well there are a few, one is that 1+1 is not 1 + sqrt(1), it's 1 + the positive sqrt(1) or |sqrt(1)|, there are more after this but I'm far too cool to go into it ;) :)