Added: 1 year ago
From: Coderisland
Views: 7,925
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  • Question: With the e-transition to the last state, doesn't it make the PDM's language = 0^n 1^m? Just as you ran 0^3 1^7 through and the machine accepted, shouldn't the machine accept any combination of 0's and 1's, where the 1's come after the 0's?

  • @KneckChop No I don't think it does. If you try to read more than 3 ones in the Pop state then you'll crash and go to the dead state since there are no arrows for more than 3 ones for 0^31^m. Once you hit the dead state you can't leave it.

  • I've really enjoyed this series, thank you

  • thank you good sir !

  • just awesome!!! thanx

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