Added: 3 years ago
From: mikleran
Views: 19,682
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  • A Rubic's cube can be solved from any legal position with maximum of 20 moves :P

  • @Mostwantedo 26 moves

  • it is proved that at most 20 turns is needed only

  • @yip924 26

  • @mdwael No, it's actually 20. Check out cube20 dot org.

  • Nice choice in songs

  • i can solve a rubiks cube way faster

  • @MonsterBuddy10 if this was realy fast how would you be able to tell what its doing?

  • @ustube27 i move the cube way faster because i use finger tricks so this is slow to me

  • @MonsterBuddy10 Actually, the program solves the cube in a few hundredths of a second. I've just made it output at this speed so that you can actually see what it's doing!

  • Let the thoughts of Meatspin begin!

  • Jesus, that's a lot of moves!

  • very nice i like it howed you make it

  • when are you publishing it??? will you release he code as well, i would like to see it

  • whats the software

  • hi, it's my own software which i created myself, but i haven't released it publicly (yet)

    oh btw, yes! it is the old colour scheme, it's based on a cube from about 20 years ago

  • Weird colour scheme. I want this. Just for the 3D part.

  • its the old color scheme. blue and yellow is switched.

  • brilliant

  • how many moves are there?

  • Comment removed

  • have you been thinking about publishing it?

  • Very nicely done Mikleran!

  • Comment removed

  • Nice. What does the solver do if it's impossible to solve? (Since you're allowing setting of the colours, it could be impossible).

    Could I have the .x file or whatever for a cube? I don't know how to create cubes with rounded edges like that. Did you see my 11X11 XNA animation? Haven't worked on that in a while...

  • Ha, there's no validation checks on whether the cube's solvable, so the program just crashes. I really should sort that out...

    Yeah, sure- each since "cublet" (or each single 1x1 face) is made of two .fbx files (one for the coloured part, and one for the charcoal/black edge). What's the easiest way to get them to you? And yeah, your animation is rather cool!

  • Awesome. Thanks... (See PM)

  • braap braap. Good stuff my scots friend.

  • is that for mac ?

  • Nope, sorry- this is Windows only for now (it requires DirectX to render the cube).

    However, there's a PHP/Javascript (i.e. viewable in any internet browser) port in the works which will output a list of commands that will solve your cube (if followed!)- but it lacks any of the 3D graphics (for now!).

  • oh wells i can solve my cube in a minute now but i found something called rubik's repair its just as good or better

  • Comment removed

  • ill freakin pay you!. well not really but PLEASE TELL ME

  • Gees... I wrote this solver myself and I haven't distributed the program anywhere. Sorry.

  • can you send it spesificly to me? me ...... can you please get it for me. no matter what??? sorta desperate

  • Why are you so desperate?! I'm not particularly keen to spread it around to be honest...

  • i dont know how to send it to anyone anyways. xD but you see: i have a rubiks cube 3x3x3 i have two sides done. i dont know any triks or methods. sooooo....... one exeption? i know i seem crazy... i am

  • Comment removed

  • were do you get that?!

  • kool where can i get this solver?

  • :O meatspin?

  • lol

  • you spin me right round baby right round like a record baby round round right round

  • Ok yes that makes sense.

    But still if I were to give you the cube at the end of my video to your solver (so it is a legitimate Rubik's cube as this cube was obtained from a solved cube and only legitimate turns) would it be able to solve it?

    I've already thought of a fix, but I don't know if it's efficient: when a cube is flipped perform either algorithm on the correct side to get it to the bottom layer of the cube and then use the correct version of the algorithm to get it on the correct place.

  • Im just curious... what does your solver do when you give it the following input:

    An entirely solved Rubik's cube, but one of the middle sides is flipped. So each side gets a unique color, say the left most (when assigning colors) side is color blue and the right most side is color red. Then in the blue side make the left middle cube red and in the red side make the right middle cube blue. Then try to solve it. This should be a case Dan Brown didn't mention could happen.

  • lol if u make it all one color it wont be able to solve it

  • Hey that looks pretty good!

    Funny thing is that I'm working on the same thing! Except then in C++/OpenGL. It's less fancy. But in solving the second layer the algorithm gets stuck... I was wondering if you had the same problem? (using Dan Brown's "method") I posted a video about it. Maybe you can check it out?

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