Nice problem, very intuitive. The answer to the amount of water hitting the front of Peter and Mary is; a x h x(sin alpha) x (sqr root of Vpm2 +Vrain2) x (rho) x (the time) = Total Kg Rain caught by their front over the time. Adding this to the amount caught by theair heads gives the total amount of water caught over the time. I enjoyed that, next one !
there is an easier explanation... lets bring the rain to an extreme and not the velocities of objects... let the rain be a sunlight (rain of photons) in Qld, Aus in summer... it is obvious that walking will cause more sunburn than running :)
while discussing the least amount of rain that will pour on them 16:18, their feet will make different cosine and sine angles with respect to the velocity they would run.
@techin5official The real question is: why don't more people get excited about these things? Physics is amazingly cool, and I would love to have Walter Lewin as my professor!
And the AMAZING thing is that i've had this lecture in another langauge (since i'm Swedish), and I could understand every equation, variabel, absolute term etc. crisp clear. I did have a good teacher in physics when I learned this and among other things... But having Walter Lewin as an teacher would be best thing ever :D
what if there was a wind and its facing them as same as there speed thats mean that the rain will hit there heads - he forget to consider the wind's speed and it's angle / im not judge him or anything i just though what if there was a wind or a storm which will change the wind's angle every seconds for instant
but overall i wish i had a teacher like him i would love physics
In The High Speed Like the Speed Of Light, The Object Increase It's Mass, Then the Amount Of Rain Will Be Bigger Than That.
also the relative speed will be great, and then speed of the rain drop that will hit their body, will be like a bullet and kill them,
also because of that high speed, they push more air and that mean the air preasure behind them will be 0, and that will make the the degree of the rains change it's position and hit them in the end
traveling at a speed equivalent to the speed of the rain falling while tilting forward causes this type of void with your body, the top of your head essentially becomes the "broom" sweeping up the rain. the rain under your head will fall before your front can catch it, and the rain behind you will not fall fast enough to land on your back. this what @caramonspace is explaining.
The amount of water in front is always the same! Frontal area x Distance x rain density. Your speed does NOT change the volume of rain you have to sweep out of your way. Rain not swept up falls to ground replaced by new rain coming down. The only change is how fast you are travelling. Faster means less rain hitting your head and shorter time to get hit. Slower means more rain hitting your head and more time to get wet.
I think Prof Lewin got to carried away with his vectors.
@tidewv Close, but no cigar. If you are running at the speed the rain comes down at a 45 degree angle (and are in a cardboard refrigerator box for experiment's purposes), you will see minimal rain hit both the front and back of your body, and are thus 'sweeping up' none of the frontal rain you mentioned, since your frontal velocity, being the same as the downward velocity of the rain, is causing the rain you encounter to just glide past the front and back face. Just the head gets wet.
@tidewv (cont'd) The rate at which it apparently glides past your front and back as you run forward is equal to the square root term of the vector magnitude mentioned in the video.
@boomludacris why so agressive? what do you mean by limit? in school we learned that division by zero is not acceptable. so you tell me its ok to divide by zero because its infinite? maybe schools in germany teach other math rules as in usa?? :D
In case anyone is actually trying to calculate the mass of rain falling on P&M's head for a certain scenario using the eq shown at 14:20. Note there is a mistake. The Vrain in the square root term should also be squared since this represents the magnitude of the rain, or speed.
At 13:21( if I am not mistaken ) he didn't see than he should write below the square root Vpm ^ 2 + Vrain ^ 2 . But overall it is a great video and i would like more of this !
Keep up the good work and if I'm wrong write a comment telling that and explaining why I'm wrong .
I know this is off topic, but I've been reviewing Professor Lewin's presentations to try to find one that covers Earnshaw's Theormen but so far I haven't found one. Can any of you point me to the right one (assuming there is one). I also wondered if he has covered what I consider the "classic bicycle problem" where you push rearwards on a pedal that is at the bottom of stroke (standing off the bike) and ask which way the bike goes?
if the assumptions are 0m/s and a larger speed.to answer the question of who gets more wet is obvious.The person who stands without moving(0m/s) gets more wet as the rain keeps poring as opposed to the latter case where the rain pouring will end eventually. They are also not taking into consideration actual humans, whose area calculations are more tricky; Peter is wrong in saying that rain will hit only head when they walk slowly as the shoulders will also get wet and the raindrops trickle down.
Watching a few of Professors Lewin's lectures brings back memories from when I was in University (~25 years ago). I don't recall any of my professors having such an eager and interesting teaching method though. Do all of the prof's at MIT perform lectures that are as interesting to watch as Professor Lewin's are?
You know you can also just learn something from just going outside in the rain, and seeing for yourself what happens when you do whatever in the rain.
In my opinion the conclusions he assembled are pretty inspirational and interesting but also too theoretical and too loaded with assumptions. However, he reached them with a vivid spirit which I found splendid and charming. :)
@ 13:55 wouldn't it be the Vrain^2 as well? Also @blomman , do you think understanding of the concept is more important or the prescriptive rules on symbols...? OOP! Spoke too soon! Sorry guys.
@ 13:55 wouldn't it be the Vrain^2 as well? Also @blomman , do you think understanding of the concept is more important or the prescriptive rules on symbols...?
At 12:00 I think this guy is wrong. You would catch the same amount of rain on your head per second no matter how fast you are going. The reason you catch less if you go faster is because you arrive in a shorter period of time.
Think about a moving sidewalk on the ground with one square region of the sidewalk painted white. If it is raining at the same rate everywhere, it wouldn't matter how fast the sidewalk went, it would catch the same amount of rain per second as everywhere else on earth.
@fluff125 Both you and prof Lewin are correct. Cos(alpha).sqrt(v1^2+v2^2) works out to the component of rain falling vertically on AB. In other words instead of looking at this from a vector point of view, if you break it down into x and y components you will see that the water on the head equals ABVrain*D/Vpm and the water on the front is always AHD. So, as long as standing vertical, the water on front always equals the volume in front and the water on head depends on time in rain.
@fluff125 Both you and prof Lewin are correct. Cos(alpha).sqrt(v1^2+v2^2) works out to the component of rain falling vertically on AB. In other words instead of looking at this from a vector point of view, if you break it down into x and y components you will see that the water on the head equals ABVrain*D/Vpm and the water on the front is always AHD. So, as long as standing vertical, the water on front always equals the volume in front and the water on head depends on time in rain.
@fluff125 I don't know what happened to my first attempt at replying to you (I'll try again...). Both you and professor Lewin are correct. Cos(alpha)*sqrt(Vpm^2+Vrain^2) equals the vertical rain velocity. Approaching this from an X,Y component point of view instead of vector you end up with rain volume on head=Vrain*AB*D/Vpm and rain volume on front=AHD. So as long as standing upright while walking, the rain on front is constant and rain on head depends on your walking speed.
@Slider68 No. The rain hits at a larger angle, it is true, but MORE rain is hitting you. Notice that when he draws the vectors (representing raindrops) slanted, the lines become closer together.
The way he tells it is misleading. No matter how fast you move, the same amount of rain hits the top of your head per second. If you move at 1/10 light speed, you will arrive very fast, so almost no rain will hit the top of your head.
This guy is good at math, but has very dim conceptual skills.
@fluff125 You are still both correct and that includes professor Lewin. If you look at my component equations below you will see the D/Vpm term which equals the time it takes to move at a constant velocity (Vpm) a distance D. The rate of rain volume falling on your head (not considering the density of the rain) is the rain velocity (Vrain) multiplied by area (AB). No matter how fast you move the same total volume of "rain" intersects with the body from the front and you get ADH.
@fluff125 Of course everything I came up with needs to be multpllied by the density of rain within a volume of air and again everything I calculated assumes the people are standing vertically. Note that since they are moving at a constant velocity and therefore it is difficult for them to be leaning forwards much so this is a reasonable assumption (yes the induced wind against them will cause them to lean forwards a little, but not much).
@fluff125 he never said you catch less rain, but rather he projected it so that he could be able to calcute the total amount of rain they would catch ! good eye though.. !
which lecture does this go with? I imagine it is the one with Robert the monkey?
eyeamon 1 month ago
This has been flagged as spam show
Nice problem, very intuitive. The answer to the amount of water hitting the front of Peter and Mary is; a x h x(sin alpha) x (sqr root of Vpm2 +Vrain2) x (rho) x (the time) = Total Kg Rain caught by their front over the time. Adding this to the amount caught by theair heads gives the total amount of water caught over the time. I enjoyed that, next one !
thecomanche1 2 months ago
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thecomanche1 2 months ago
na mein hintern ist geil
OdellYingbr519 2 months ago
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av733 3 months ago
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av733 3 months ago
most people are not interested in physics at all...though physics got a lot of help in our daily lives...
muhammadzahmad 3 months ago
Very organized way of titling the videos.
agapitoflores001 3 months ago
thanks for posting this one.
violetmoonster 3 months ago
great video
thebigfootme 3 months ago
Lewin is awesome!
Dating99 5 months ago
they had this on mythbusters
divorce44 5 months ago
I love Professor Lewin
devihen 7 months ago
I thought I was the only person weird enough to actually ponder this question
theeyecreature 7 months ago
So if they go more than the speed of light the rain would be falling up... they'd be travelling back in time... awesome
IFE10M 7 months ago
I love Walter Lewin =)
EmoPikachu23 8 months ago
He is in the highly rarefied air in teaching skills at Richard P. Feynman..
Sparky5999 9 months ago
there is an easier explanation... lets bring the rain to an extreme and not the velocities of objects... let the rain be a sunlight (rain of photons) in Qld, Aus in summer... it is obvious that walking will cause more sunburn than running :)
lubos3s 9 months ago
@lubos3s and obvious that hypothetically you can run at the speed of light at a 45 degree angle would have even less sunburn
lemon48794879 3 months ago
while discussing the least amount of rain that will pour on them 16:18, their feet will make different cosine and sine angles with respect to the velocity they would run.
kurt05051987 9 months ago
Very interesting! I don't care what others say.
shadowC10ne 9 months ago
lol his enthusiasm is infectious, i couldn't help but chuckle watching him.
cake89 9 months ago 4
I just saw a myth buster episode, and based on experimental data, when walking they catch the least amount of fluids in their cloths.
pablo19852000 9 months ago
if 30 degrees, 3.5km/h.
matsubokkuri 9 months ago
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LittleFactoryBoy 9 months ago
"Physics", real natural science.
quablepy 9 months ago 2
Is he dutch?? :)
a3nebigby 9 months ago
@a3nebigby yes
juha3juha3 9 months ago
he is so fun to watch. great teacher.
Sshocker17 9 months ago 3
He could've made it easier and concluded that the rain you sweep in your way is always constant and has nothing to do with your speed
onlyinter88 10 months ago
Walter Lewin <2
FabianyJoann 10 months ago
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cosmic2castaway 10 months ago
I LOVE HIS HANDWRITING.
prettysaphire 10 months ago
TLDW: Run in the rain
Veto2090 10 months ago
Also, people always forget to factor in puddles in these sorts of experiments, splashes caused by running can drastically increase your wetness.
gaynorvader 10 months ago 2
Wow, magic rain! It's falling so slowly, must be in slow-mo ;P
gaynorvader 10 months ago
Physics = 0
Math = 1
Entertainment = 1
Educational = 0
Charm = 1
Overall score:
60%
oldskoolchopperboy 10 months ago
The sound of the pen on the paper gives me chills. :S
TheAutoSleep 10 months ago
Hmmm, why use Expo dry erase markers on paper?
pattcom 10 months ago
baller.
SiberianEskimo 10 months ago
Is is just me or does this guy have to be kin to Christopher Walken.
pratman2 10 months ago 3
@pratman2 I was thinking the same thing :)
tsami7 10 months ago
WHy is this guy so excited?
techin5official 10 months ago
@techin5official If you were a math geek you would be too.
Calgarylames 10 months ago
@techin5official The real question is: why don't more people get excited about these things? Physics is amazingly cool, and I would love to have Walter Lewin as my professor!
rsotbairnfire 10 months ago 16
@rsotbairnfire
Same here!
And the AMAZING thing is that i've had this lecture in another langauge (since i'm Swedish), and I could understand every equation, variabel, absolute term etc. crisp clear. I did have a good teacher in physics when I learned this and among other things... But having Walter Lewin as an teacher would be best thing ever :D
MrMaxen92 5 months ago
The answer: women are always right.
Conscars 10 months ago
TL;DW Version: walk at an approx. angle of 45 degrees or the same degree as the rain and as fast as the rain is coming down.
ninjaodeath30 10 months ago
the Professor has an uncanny resemblance to Christopher Walken....even sounds like him at certain points.
AchtungPakhtoon 10 months ago
Wooooowowwww .... So Idealistic!! Just run as fast as rain fall and then make yourself's angle 45 degree 55555+
NavalJanistor 10 months ago
Women are always right...proven by physics lol
parceritaz 10 months ago 2
Every time I see a great teacher I tell myself they are the best. Every time I find someone better. This guy is awesome.
HighWarlordJC 10 months ago
17:46 for the answer
aspiziri 10 months ago 24
need the tl;dw version of this.
babaozhou123 10 months ago
Can someone summarize the video in one sentence?
bcbird 10 months ago 3
@bcbird Run Forest Run
YTBIU 10 months ago
@bcbird one word: RUN!
fedetrabu 10 months ago
@bcbird Women are always right
Calgarylames 10 months ago
@bcbird run for your life ....lol
MrWhatdoyoucare 1 month ago
women are always right :)
aliabobalia 10 months ago
Funny! :-)
gerlosgm 10 months ago
He's Dutch! That explains the accent
Liface 10 months ago
Is that Larry King? ;)
brentyager 10 months ago
but OF COURSE we noticed a square was missing! hands up (or rather: thumbs up) those who did!
schenonef 10 months ago
but OF COURSE we noticed a square was missing! hands up (or better, thumbs up) those who didnt!
schenonef 10 months ago
educational and practical; very nice
Holyhellitsgregory 10 months ago
what if there was a wind and its facing them as same as there speed thats mean that the rain will hit there heads - he forget to consider the wind's speed and it's angle / im not judge him or anything i just though what if there was a wind or a storm which will change the wind's angle every seconds for instant
but overall i wish i had a teacher like him i would love physics
suska12 10 months ago
That old guy looks/sounds like he could be Christopher Walken's cousin.
SarahsAwesomeAccount 10 months ago
Buy an umbrella?
6059854623158 10 months ago
mistake!
he misses out a squared sign on Vrain at 13:40
loansharkify 10 months ago
@loansharkify ... and then he corrects it at around 15:30.
adman123 10 months ago
@loansharkify clearly u stopped watching because he corrects himself later
vidarpi 10 months ago
Best moment at 15:26. Amazing...
mgibso29 10 months ago
Nice ring.
Davgil1994 10 months ago
In The High Speed Like the Speed Of Light, The Object Increase It's Mass, Then the Amount Of Rain Will Be Bigger Than That.
also the relative speed will be great, and then speed of the rain drop that will hit their body, will be like a bullet and kill them,
also because of that high speed, they push more air and that mean the air preasure behind them will be 0, and that will make the the degree of the rains change it's position and hit them in the end
evanescentdevil 10 months ago
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traveling at a speed equivalent to the speed of the rain falling while tilting forward causes this type of void with your body, the top of your head essentially becomes the "broom" sweeping up the rain. the rain under your head will fall before your front can catch it, and the rain behind you will not fall fast enough to land on your back. this what @caramonspace is explaining.
steefs82 10 months ago
@steefs82 ugh, that did not turn out the way it looked in the comment box. hopefully my written description helps to make sense of this mess, lol.
steefs82 10 months ago
I want to go to his class....
siasabora 10 months ago
The amount of water in front is always the same! Frontal area x Distance x rain density. Your speed does NOT change the volume of rain you have to sweep out of your way. Rain not swept up falls to ground replaced by new rain coming down. The only change is how fast you are travelling. Faster means less rain hitting your head and shorter time to get hit. Slower means more rain hitting your head and more time to get wet.
I think Prof Lewin got to carried away with his vectors.
RUN!
tidewv 10 months ago
@tidewv Close, but no cigar. If you are running at the speed the rain comes down at a 45 degree angle (and are in a cardboard refrigerator box for experiment's purposes), you will see minimal rain hit both the front and back of your body, and are thus 'sweeping up' none of the frontal rain you mentioned, since your frontal velocity, being the same as the downward velocity of the rain, is causing the rain you encounter to just glide past the front and back face. Just the head gets wet.
caramonspace 10 months ago
@tidewv (cont'd) The rate at which it apparently glides past your front and back as you run forward is equal to the square root term of the vector magnitude mentioned in the video.
caramonspace 10 months ago
I think I'm going to hang out here more. Hopefully this is too erudite for the usual trolls that slime every comments section. Great site!
freethoughtmusic 10 months ago
what about the shoulders??
TheEventuaLDJMIKE 10 months ago
:D!
Zeykieee 10 months ago
05:24 This would resolve in devision by zero => error :D
TheRealBlackRefleX 10 months ago
@TheRealBlackRefleX no you stupid, do the fuckin limit ,something divided by 0 equals infinite dumass, go to school and take your calculus 1 class
boomludacris 10 months ago
@boomludacris why so agressive? what do you mean by limit? in school we learned that division by zero is not acceptable. so you tell me its ok to divide by zero because its infinite? maybe schools in germany teach other math rules as in usa?? :D
TheRealBlackRefleX 10 months ago
@boomludacris - i can't believe I'm correcting math on youtube!
x / 0 is undefined, so @TheRealBlackRefleX is technically right.
In fact, the whole reason we need to use a limit there, is because the problem can't be answered using the real numbers.
You're probably thinking of the fact that the limit of x/n as n goes to 0, approaches infinity
the two are not the same, though they're related.
hawkinsst7 10 months ago
@boomludacris - i can't believe I'm correcting math on youtube!
x / 0 is undefined, so @TheRealBlackRefleX is technically right.
In fact, the whole reason we need to use a limit there, is because the problem can't be answered using the real numbers.
You're probably thinking of the fact that the limit of x/n as n goes to 0, approaches infinity
the two are not the same, though they're related.
hawkinsst7 10 months ago
@hawkinsst7 I sense you're missing the point.
renzyq19 10 months ago
only physicists can look baller with that hair
palaver87 10 months ago 3
What if rains stops?
Where's your science now!
Deicidead 10 months ago
In case anyone is actually trying to calculate the mass of rain falling on P&M's head for a certain scenario using the eq shown at 14:20. Note there is a mistake. The Vrain in the square root term should also be squared since this represents the magnitude of the rain, or speed.
sammyByou 10 months ago
@sammyByou he corrects it later..
dodoboy1212 10 months ago
A little bit long for such a simple problem, nevertheless it is great so most people can understand.
MultiBrados 10 months ago
I have a question:
Shouldn't one use the derivative of the whole (water on top and front) equation relative to Vpm to find for which vpm the wet-ness becames minimum?
angel13061987 10 months ago
Two words: Christopher Walken.
Pensador 10 months ago 2
This is the best video on youtube.
novicatalasic 10 months ago
Lol, my math says the result at 06:40 is 1/3 * 10^(-4) rather than 3 * 10^(-5).
shnako 11 months ago 4
At 13:21( if I am not mistaken ) he didn't see than he should write below the square root Vpm ^ 2 + Vrain ^ 2 . But overall it is a great video and i would like more of this !
Keep up the good work and if I'm wrong write a comment telling that and explaining why I'm wrong .
PK34646009 11 months ago
I know this is off topic, but I've been reviewing Professor Lewin's presentations to try to find one that covers Earnshaw's Theormen but so far I haven't found one. Can any of you point me to the right one (assuming there is one). I also wondered if he has covered what I consider the "classic bicycle problem" where you push rearwards on a pedal that is at the bottom of stroke (standing off the bike) and ask which way the bike goes?
Slider68 11 months ago
So next time when it rains instead of an umbrella i should calculate the speed of the raindrops and get a hat :) and run.... without stopping....
player1vladimir 11 months ago
if the assumptions are 0m/s and a larger speed.to answer the question of who gets more wet is obvious.The person who stands without moving(0m/s) gets more wet as the rain keeps poring as opposed to the latter case where the rain pouring will end eventually. They are also not taking into consideration actual humans, whose area calculations are more tricky; Peter is wrong in saying that rain will hit only head when they walk slowly as the shoulders will also get wet and the raindrops trickle down.
arunk279 11 months ago
Cool ring, what is it?
scorpionboy3 11 months ago
Watching a few of Professors Lewin's lectures brings back memories from when I was in University (~25 years ago). I don't recall any of my professors having such an eager and interesting teaching method though. Do all of the prof's at MIT perform lectures that are as interesting to watch as Professor Lewin's are?
Slider68 11 months ago
THIS GUY!!!! SO AMAZING!
But have fun running at a constant speed with a 45 degree forward angle.... hehe
I love teaching
z50king29 11 months ago 2
You know you can also just learn something from just going outside in the rain, and seeing for yourself what happens when you do whatever in the rain.
TheeDelibird13 11 months ago
this is awesome, but he can do more to prove his conclusion.
mywtfmp3 11 months ago
That guy is a genius! I love you man!
andresdambrosio 11 months ago
why would the direction (angle) of th rain matter?
junior1984able 11 months ago
In my opinion the conclusions he assembled are pretty inspirational and interesting but also too theoretical and too loaded with assumptions. However, he reached them with a vivid spirit which I found splendid and charming. :)
AA10Megaviv 11 months ago
had a similar prof that got his BS from MIT, was an amazing class
anilsenturk 11 months ago
What a fantastic teacher.
somethingesoteric 11 months ago
@ 13:55 wouldn't it be the Vrain^2 as well? Also @blomman , do you think understanding of the concept is more important or the prescriptive rules on symbols...? OOP! Spoke too soon! Sorry guys.
ctiebs 11 months ago
@ 13:55 wouldn't it be the Vrain^2 as well? Also @blomman , do you think understanding of the concept is more important or the prescriptive rules on symbols...?
ctiebs 11 months ago
At 12:00 I think this guy is wrong. You would catch the same amount of rain on your head per second no matter how fast you are going. The reason you catch less if you go faster is because you arrive in a shorter period of time.
Think about a moving sidewalk on the ground with one square region of the sidewalk painted white. If it is raining at the same rate everywhere, it wouldn't matter how fast the sidewalk went, it would catch the same amount of rain per second as everywhere else on earth.
fluff125 11 months ago
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Slider68 11 months ago
Comment removed
Slider68 11 months ago
This has been flagged as spam show
@fluff125 Both you and prof Lewin are correct. Cos(alpha).sqrt(v1^2+v2^2) works out to the component of rain falling vertically on AB. In other words instead of looking at this from a vector point of view, if you break it down into x and y components you will see that the water on the head equals ABVrain*D/Vpm and the water on the front is always AHD. So, as long as standing vertical, the water on front always equals the volume in front and the water on head depends on time in rain.
Slider68 11 months ago
This has been flagged as spam show
@fluff125 Both you and prof Lewin are correct. Cos(alpha).sqrt(v1^2+v2^2) works out to the component of rain falling vertically on AB. In other words instead of looking at this from a vector point of view, if you break it down into x and y components you will see that the water on the head equals ABVrain*D/Vpm and the water on the front is always AHD. So, as long as standing vertical, the water on front always equals the volume in front and the water on head depends on time in rain.
Slider68 11 months ago
@fluff125 I don't know what happened to my first attempt at replying to you (I'll try again...). Both you and professor Lewin are correct. Cos(alpha)*sqrt(Vpm^2+Vrain^2) equals the vertical rain velocity. Approaching this from an X,Y component point of view instead of vector you end up with rain volume on head=Vrain*AB*D/Vpm and rain volume on front=AHD. So as long as standing upright while walking, the rain on front is constant and rain on head depends on your walking speed.
Slider68 11 months ago
@Slider68 No. The rain hits at a larger angle, it is true, but MORE rain is hitting you. Notice that when he draws the vectors (representing raindrops) slanted, the lines become closer together.
The way he tells it is misleading. No matter how fast you move, the same amount of rain hits the top of your head per second. If you move at 1/10 light speed, you will arrive very fast, so almost no rain will hit the top of your head.
This guy is good at math, but has very dim conceptual skills.
fluff125 11 months ago
@fluff125 You are still both correct and that includes professor Lewin. If you look at my component equations below you will see the D/Vpm term which equals the time it takes to move at a constant velocity (Vpm) a distance D. The rate of rain volume falling on your head (not considering the density of the rain) is the rain velocity (Vrain) multiplied by area (AB). No matter how fast you move the same total volume of "rain" intersects with the body from the front and you get ADH.
Slider68 11 months ago
@fluff125 Of course everything I came up with needs to be multpllied by the density of rain within a volume of air and again everything I calculated assumes the people are standing vertically. Note that since they are moving at a constant velocity and therefore it is difficult for them to be leaning forwards much so this is a reasonable assumption (yes the induced wind against them will cause them to lean forwards a little, but not much).
Slider68 11 months ago
@fluff125 he never said you catch less rain, but rather he projected it so that he could be able to calcute the total amount of rain they would catch ! good eye though.. !
MrWhatdoyoucare 1 month ago
Remarkable that an "expert" in physics does not know that the correct unit designation for seconds is "s" NOT "sec".
blomman43 11 months ago
WOW! this is one of those problems you understand when shown but asked to do it yourself you have no clue where to start.
TheUFOeffect 11 months ago
Thank you I really appreciate the visual demo, great video.
fullmetaljason 11 months ago
@fullmetaljason Get them til fall?
dowling1981 11 months ago
You can really see that he loves what he does. More teachers like this please!
sperrepolken 11 months ago 65
LOL, great ending line!
Cifrocco 1 year ago 30
Hey when was this video shot? Looks like a younger Professor Lewin than the famous MIT lectures. Cool!
Cifrocco 1 year ago 2