Added: 5 months ago
From: iasedu
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  • 23:45 Ouch! Presumably not all of them made it to escape velocity. What's terminal velocity for a ball bearing falling through Earth's atmosphere?

  • @sbergman27 sqrt((2mg/pACd)) where p is the density of the air and Cd is the drag coefficient. If I remember it correctly, shouldn't be too hard to get some results. (If you are curious enough!)

  • @iasedu Thanks for the reply. :-)

    For a 0.5 cm radius ball bearing, that works out to 95 m/s (about 210 mph) assuming that it sheds excess velocity and hits with the Vₜ indicated for the lower atmosphere. Like I say: "Ouch!"

    r = 0.5 cm

    m = 4.2 g

    g = 980 cm/s²

    ρ = 0.0012 g/cm³

    Cd = 0.1

    A = 0.7554

    -Steve

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