@sbergman27 sqrt((2mg/pACd)) where p is the density of the air and Cd is the drag coefficient. If I remember it correctly, shouldn't be too hard to get some results. (If you are curious enough!)
For a 0.5 cm radius ball bearing, that works out to 95 m/s (about 210 mph) assuming that it sheds excess velocity and hits with the Vₜ indicated for the lower atmosphere. Like I say: "Ouch!"
23:45 Ouch! Presumably not all of them made it to escape velocity. What's terminal velocity for a ball bearing falling through Earth's atmosphere?
sbergman27 4 months ago
@sbergman27 sqrt((2mg/pACd)) where p is the density of the air and Cd is the drag coefficient. If I remember it correctly, shouldn't be too hard to get some results. (If you are curious enough!)
iasedu 4 months ago
@iasedu Thanks for the reply. :-)
For a 0.5 cm radius ball bearing, that works out to 95 m/s (about 210 mph) assuming that it sheds excess velocity and hits with the Vₜ indicated for the lower atmosphere. Like I say: "Ouch!"
r = 0.5 cm
m = 4.2 g
g = 980 cm/s²
ρ = 0.0012 g/cm³
Cd = 0.1
A = 0.7554
-Steve
sbergman27 4 months ago