Added: 4 years ago
From: chychochycho
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  • Wait an minute...so now if i wanted i could use the 30 degree angle to solve x by using Cos once again...7 being hyp and x being adj?

  • Yup :)

  • @chychochycho Now i'm getting somewhere : )

    Seriously though dude...i'm 40 years of age and have never understood the jumbled signs and symbols i knew as math but due in large part to your vids and some other books i'm studying i'm really getting a handle on material that mystified me in the past...i'm still waiting for that "Eureka" moment that happened to you in the library but i'm a keep on keeping on....

    PEACE

    MAJESTIC

  • Comment removed

  • Ok so...if i were to use the 60 degree angle to solve for x i would use Sin?

    MAJESTIC

  • yup :) 

  • @chychochycho Nice!!!And in the same vein...if i were to chose the 30 degree angle to solve for y i would use the.....Tan?

  • you could use sin with 7, or, now that you have x, you could use tan with x.

  • @chychochycho Ok...i got ya...i guess with enough practice which function to use'll become 2nd nature.

  • It will :)

  • @chychochycho So if i'm understanding it right you can use the sides as well as the angles with the fuctions of Sin,Cosine and Tangent?

  • Remember, you can only take the sin, cos, and tan of an angle.

  • you really needed the calculator to know that cos 60 is 1/2? come on. You are teaching maths and don't know your trig?

  • I just wanted to know how to do, "x^2+(x+2)^2=100".

  • @Austin101123 the answers are 6 and -8, just use foil and the quadratic formula, but it probably doesn't matter anymore :p

  • @Drummaboyy13 true i found out how to do that the next day in class lol

  • epic got a100 on my last test in college . THESE LESSON ARE EPIC XXXXXXXXX10

  • I like EPIC :)

    and congrads on the 100. Job well done :)

  • i dont get how you get the 0.5, i wanna know how to do it without the calculator

  • i dont get what the sino, coso and tano is.. is it like a formula?

  • They're functions that relate the sides of a triangle (right triangle) to it's angles. It's a ratio really. There is a lot more to it and it will take a whole series to cover it in detail, which i do plan on doing, but again, it will be quite some time before i get to it... sorry :(

  • you should do word problems of this also after you are done with the basics like you said..

  • I keep trying and struggling with one of your exercise problems on website and cannot figure out why answer is not same as yours. It refers to solving using the Pythagorean theorem on problem 2a. where a=5, b=5 and c or x is the unknown. Your answer was 5 time square root of 2. I came up with (on calculator) 7.071. The very next problem 2b. comes up with a similar result of 19.21. Why is 7.071 incorrect?

  • 7.071 is not incorrect. It's the correct answer. 7.071... is equal to 5 times square root of 2. The only difference is that 5 times the square root of 2 is an exact answer while 7.071... is approximate since the square root of 2 is an irrational number (see series II for solving radicals).

  • @Ezekiel160 WTF lol, that was so fuckin rude he's a math magician, terrorist doesn't even have internet so I'd suggest you shut up.

  • Thank you!!!!!

  • you're welcome :)

  • another solution to this problem.

    THEOREM, (proved in the elements of euklid)

    ->when in a right angle triange there is a 30 degree angle then the opposite side of this angle is equal to the half of the hypotenuse of this triangle.

    As far as your example......

    ABC->right angle triangle

    B=30, so x=hyp/2  x=7/2 x=3,5 (where,x=b)

  • my pleasure :)

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