Added: 4 years ago
From: bannanaiscool
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  • I gotta' say, you are truly an excellent instructor!

    Unbelievably clear. :)

  • turn captions on for 1:53

  • Chemguy swag 2:06

  • Comment removed

  • Thank you so much! I appreciate the clarity and ease of communication in sharing your knowledge of Chemistry. I am currently enrolled in AP Chem2 in high school and watching your videos helps assure me that i can actually pass the class and the tests! Thank you!!! More videos???

  • Now why cant my chem teacher teach like this? I'd get it so much more!

  • my teacher made it seem way more difficult he had 90 min to explain NADA u had 6 min LIGHTBULB!!!!!!

  • hate that i don't know this 

  • i wish you were my chemistry teacher!!!!!!!

  • Thanks!! But why have you stopped making videos???

  • Thanks for the videos. It helps me remember what Ive learned in class each day.

  • this guy is freaking awesome.. :D

  • @NoellaQuesta Why thank you!

    Chemguy

  • do we really need to round off the numbers of our answers?

    or is it okay not to?

  • @valschuck61 It really isn't ok.

    Chemguy

  • if you have 1.138 mol H2 and you need 0.284 mol H2 wouldn't that mean that the H2 is in excess?

  • @rockguyjw Yep.

    Chemguy

  • too fast in balancing the equation...

    but good though!! :-)

  • This sis extremely helpful i have a chem final tomorrow thank god i found this

  • you are like 100% better then my chem teacher :D

  • Sweet I have a chem final tomorrow and this really helped!!!

  • my chem teacher is insane. He tried to light us with methane + liquid soap solution in water thing luckily the flame was not able to overcome the 4.18 KJ/mol NRG requirement :)

  • THANK YOU SOOOOO MUCHHHH!!!!! I was soooooo utterly confused before, but now I'm perfectly ready for my test! YOU ROCK!

  • So if we took the amount of moles of O2 instead of H2 would it still work?

  • @MrTollyferro No! You have to use the limiting reagent amount!

    Chemguy

  • I get it!! 

  • My chem teacher is very good, but still you help me understand things much faster!! thanks you have been very helpfull!!

  • If I started with oxygen instead of hydrogen, how would you know that it's the excess reactant? because you could basically do the same thing as you did with hydrogen..

  • I WISH HE WAS MY TEACHER!

  • Hey Chemguy!

    do you happen to have a video on long percent yields. i not getting it and my chem teacher does not like to review. if you dont have the video.... well thanks for helping me with Stoichiometry! :D

  • I wish you were my chemistry teacher! You're pretty awesome! :)

  • I don't think you realise how much this helped me. THANK YOU!

  • You're so animated ; I love it . x)

  • These stoich videos have been soo helpful, my exam tommorow is gonna be easy. THANK YOU!

  • THIS IS THE BEST TUTORIAL EVER!!!!!!!!!

  • Thanks Chemguy

  • Yess! Success! I'm taking this test tomorrow after a long winter break- Thank you so much!

  • "It only speaks Mo0lish!" lol

    ^_^

  • im going to have to watch it once again but i sorta know whats going on and with a little more time im sure i will understand. thanks for posting these. i go to a privacte school and my class is very smart and im a slow learner so this helps me a ton. thank you thank you thank you and God bless

  • you're just the happiest dude ever.

  • you should get a tv show !!!!:D

  • brilliant. please keep posting videos!!

  • my teacher babies us, she pretty much never lets us do things on our own. she does everything for us. when tests come around, everyone fails because no one is really getting the material. you help A LOT =D

  • THANLS ALOT. GREAT HELP FOR MY TESTS AND QUIZES. btw wheres part 2?

  • so is oxygen the limiting reagent ?

  • excellent communicator, easy to understand and follow and fun to watch...you should come to our uni and be our lecturer. !!!

  • Thank you, I'm reviewing highschool chemistry for the MCAT and that was a very clear explanation and mathematical setup!

  • heheeh molish...

  • I was having so many issues with Stoichiometry! My teacher doesn't explain new information well and our book doesnt help either. Bannanaiscool explained every step which allowed me to follow along and now feel alot more comfortable! Give this video 2 thumbs up and will pass the words onto classmates. WELL done!!

  • you are the coolest chem teacher EVER!

    you explain it really basic and it helps alot, it's also nice that it's on youtube because we can just replay it if we don't understand, unlike being in class, where you can't rewind the lecture

  • YOU ARE AN AWESOME CHEM TEACHER!

  • You're videos have helped me walk into my chem exam with a 56/65%. My exam is worth 30% and there's an assignment still waiting to be handed back that accounts for the remaining 5%.

    I want you to know, you're videos were instrumental in my success. I can't think you enough sir, you do good work. You really know how to relate things to people just learning.

  • badass instructor i wish my professor could teach like u, thanx a lot for the vids

  • thank you so much chemguy, i know you get this alot but i have been stressed to the bone lately and just did not understand this stuff. THANK YOU MY HERO!!!! oh and love the pace you teach, its great! C:

  • when your given two numbers and told to find the excess you find that one is the limiting reagent and does this mean that the other number is going to be in excess. i would ask my chem teacher but she would just make me feel like an idiot :(

  • @JAespies  You're right!

    Chemguy

  • i got a 99

    I <3 Chemguy

  • I ONLY SPEAK MOLEISH lol! I wish you were my chem teacher :(

  • oh thnkz for this one of this question was on my exam worth of 6 marks n im preety sure i got 6/6 thnxss a lot :) now i can even take chem in college or uni cuz extra help is here thnxsss

  • EVERYTHING IS SO MUICH CLEARER NOW! :D

  • only speaks molish hahahaha

  • thank you so much my midterm is tomorrow and I could never quite grasp this. i think I've got it now!

    you're much easier (and less boring) to follow than khan academy

    well done :

  • any ways thanks alot because not even my other advanced courses are this hard

    thanks

  • cant belive i understand this...still in shock...i type chemisty under google and after clicking next for five times i had this crazy idea...ill youtube it...ive learned more than i have in the past week..what is really shocking is that i understand this...im in chem-PreAP but ive been struggling, my teacher treats it as an AP class along with our quizes which are worth 60% of our grade..we learn it one day and quiz the next..i realized that it would of been helpful if i was a junior taking this

  • THANKS! That was awesome! I thought your speed was good. I have test tomorrow, and thanks to you I think I am going to ace it!

  • i dont get how you got 0.284 ?????????

  • @blueyestlk You take the numbers on the top of the chart and multiply them (4.55 x 1 x 2) and divide them by the ones on the bottom (32 & 1). So you get 9.1 divided by 32 = 0.284375, rounded to 0.284. I hope that cleared it up for ya >.>

  • He multiplied accross the top (44.5 * 2), because the 44.5 is over 1 and divided his answer from the bottom. so 9.1/32 = 0.284

  • thanks for helping me study for my chem 11 exam tomorow :)

  • Khan academy compaired to this is a joke, you cant compare Chemguys instruction to that.

    A+ Chemguy!

  • i wish you taught at my school. my teacher has no idea if the kids understand it and she just moves on. thanks for the video it really helped

  • well excuse me for having an opinion...this guy is good, but i just think khan academy is better...

  • Chemguy what is your job ?are you a school teacher or a scientist or something like that or are you an average Joe who come home from a long day at the office and decides do relax by teaching chemistry on youtube?

  • Chemistry Teacher!

    Chemguy

  • @bannanaiscool

    haha, You seem into your work. That's kewool.

  • Awesome thank you!

  • Sorry that I go too fast for you. I guess the good thing is you can always watch it again! I'll keep trying, though!

    Sorry,

    Chemguy

  • Comment removed

  • I've watched all the parts to your video and i appreciate the short cut method you teach for finding the limiting reagent. I learned usuing the longer method of finding an EMR and a PDMR then compairing them to find which reactant is the limiting factor.

  • post this as a video response to the khan academy stochiometry films... he lengthens it out soo much and throws all this non topic information in. you make it simple and sweet.

    as for the khan academy guy... well, we digress.

  • my teacher is horrible.

    you are awesome. :)

  • so is mine... I got a D on my test so my grade went from an A- to a B-, but now I'm gonna ace the next one!

  • Wouldn't the limiting reagent be Oxygen in this example?

    Like you said you only need .0284 mol of H to react w/ ALL the Oxygen. You have 1.138 mol of H to start w/. So, after the reaction you would technically be left w/ an EXCESS of 1.1096 mol of H while all the O is used up. This would mean H is in excess and O is actually the limiting reagent...

    I may be wrong though; if you're still reading comments can you please explain that to me?

  • I mean .284 mol of H leaving an excess of .854 H after the reaction. Still, the Oxygen would limit the reaction.

  • Right! I never said that hydrogen was the LR, the oxygen is! But the oxygen, being the LR, requires that only 0.284 mol of H be reacted. That's what I hope you pick up in the vid at around the 4 min mark.

    You're right!

    Chemguy

  • thank you thank you thank you!!!

  • thank you so much for these! my COLLEGE chem professor is horrible, and your AP level tutorials were just perfect.

  • ONly speaks molish !!!! Thanks man for the tutorial !

  • THANK YOU!! I missed a day of chemistry and was so far behind but your videos helped me catch up

  • you taught me in 30 minutes what my teacher failed to teach me in 2 weeks

  • Thank you chemguy. You are funny and smart!

  • Love you chemguy.

  • I just want to thank you for helping get through Chem class...I have to simply reiterate what these fine folks have already said...YOU ARE GREAT, wish I could keep you as my professor! God bless you Chem guy! LOL

  • God bless you my friend. very helpful

  • I LOVE U :D... EXCELENT VIDEO i've learned more than 70% of the course material from your videos,

  • okay, seriously? You rule. My chemistry teacher failed to teach me stoichiomitry and have it make sense in the past week, i watched all 3 of your videos and in the 15 or so minutes it took to watch them, yeah I get it. Thanks SOOO much!

  • You are amazing! You make chemistry exciting

  • Incredible job!! You just helped me grasp what I have had to read several times in vain. Wish I could keep you as my teacher!

  • Thanx for the answer. I did a type-o when I wrote H2, it should have been O2 of course, but I later found out how to do this. I just hope I remember it :-)

  • I got it :-)

  • I still don't understand why H2 is the LR. Can someone please explain??

  • This didn't make sense until 4:10 when he explains that the smaller amount of Hydrogen is the limiting reagent! Thanks chemguy!

  • I'm going to pass my exams tomorrow! yay! thank you chemguy!

  • dude can i have ur email so i can send u email ask you questions if i have got any problems

  • i hope so i am able to do at least somthng in this topic. well hope i'll pass in examz

  • god bless you.. you've helped out tremendously.

  • I hate chemistry

  • i have my chem final monday, and let me tell you. watching you explain it is the difference between a pass and..well...really low grade.

    my teacher is ok, but dude, you're a huge help. Thanks.

  • I'm sending your video's to my chemistry teacher

  • thank you!!!

  • Thanks chemguy. Got a chem final tomorrow and you really helped me review :)

  • you put my chem teacher to shame.

    final exam tomorrow, and i can only thank you because I'm going to pass!

  • IB Chemistry Exam, here I come!

    Hoping for atleast a 5 on the exam (out of 7).

    Thanks, so helpful for a topic that I really needed assistance in.

  • The oxygen is the LR isn't it?

  • yah thats what i thought too

    because you have more of the h2 than you need

  • MANN!! you rule! im gonna pass now :D !! i wish you were my teacher...

  • on the last part why did you do the mol ratio of H2O as 1? in the equation isnt it 2.

    such as 18.02gH2O/2mol H20

  • Comment removed

  • thanks man helped me pass my chem test tmew

  • You should make your own t.v. show.. like Bill Nye the Science Guy! You help so many people and are easy to understand!!

  • Molish!! Damn I wish you were my teacher.Your great.

  • thank you so much, I am a 30 something year old learning chemistry in college for the first time and your videos helped me tremendously!!! Even told other confused students where to find you! keep up the good work!!!

  • i love you so much right now!

  • OMG thanks so much it makes it a lot easier.

  • "Ya it makes sense." LOL oh man I love your teaching style. It's great to see people who love their jobs =)

  • i wish i had you as my chem teacher =/

  • Thank you a lot. watching this video like two times helps me understand everything about conversions.

  • I'm gonna watch this whenever I need to study Stoichiometry

  • thank you sooo much thank you

  • Haha i wanna learn Molish too

  • i love chemistry i understand it but i know some people don't but you are doing a great job explaining things in simple ways congrats chemguy you rock

  • LIFE SAVER! thanks a ton! i bet your students love you!

  • thank you so much! i have final tomorrow and i think i get it!

  • That is really a very nice explanations thank you so much.

    BTW i liked that part it only speaks molish lol

    thanks again

  • You should get paid for this lol.

  • Well, the way I do it really helps for all types of these odd ratio problems. Just try a 3:2 problem with the way you want to do it. Yikes!

    Chemguy

  • good explanation but you should have just found how many moles of O2 there were instead of multiypling by the 2 to 1 ratio which got me lost

  • it only speaks molish!

  • POOF! There's the answer. Fantastic.

    Uhm, I'm just a student, but I have to teach Stoichiometry when school starts back up. So I seriously need help.

    It only speaks molish. XD I love it!

  • P.S. don't forget your sig figs =]

  • Thank you so much!!! I've got a test on this stuff on Thursday. You're my hero. Thanks to you, I may just get an A =]

  • seriously, why can't my teacher explain stuff like you can?

  • i just dont get it, i got help from my teacher and no tried this, it seems easy enough when someones explaining it but it doesnt stick in my mind

  • my comment is the same as morben23's, you helped me understand this so much more, thanks a lot prof

  • I've got a Stoichiometry test coming up tomorrow..and you have no idea how much you've helped me!  Seriously, you're awesome.

    Thank you, Thank you, THANK YOU!

  • Zomg, you saved my life XD

  • are you aware how awesome you are? seriously!

  • helpful video.keep it up chem guy..thanks for making me understand the stoich now..im taking a test next week.."lets exchange brains for that day".hahaha.thanks once again for the video.

  • Haha!! You're my hero!

    Everything makes perfect sense the way you explain it!

    Thank you so much for doing this!

  • all hail chemguy!

  • i think i finally understand it!!! thanks :)

  • Thanks for the series of video on Stoichiometry, it was really helpful.

  • wow.

    you're really good.

    my teacher does it a very different way.

    :)

    thanks man (Y)

  • If, for every 4.55 g of O you only need .281 moles of H2, and you have 1.138 moles of H2, then don't you have plenty of H2? So why is it the limiting reactant?

  • No, no! The H2 is not the LR; the oxygen is. Watch carefully...I show how to arrive at the LR by making a comparison with how much hydrogen there actually is, versus how much you need. The oxygen present requires an amount of hydrogen that is readily present, so the oxygen is the LR.

    You'll see...

    Chemguy

  • haha that was kind of confusing as you put the LR under the H2 required, but still very good explanation.

  • yea im confused...is the 4.55g of O2 the limting reagent or is the H2? plaese reply

  • After 5:00, isn't it supposed to be 0.284 mol of Oxygen instead of H2 as H2 is the excess?

  • Ah nevermind, did you you just continue on the equation with the h2 instead of converting the grams of Oxygen into mol to be quicker?

  • thank you thank you!!!! this video is very comprehensable than my proof's discussion!!!!

  • finally i understand stoich.. i got an exam abwt this tomorow! thnx chem guy! haha

  • Thank you thank you so much!!!

  • woot

  • I got an exam coming up Monday on stoichiometry, and I feel much better after watching this guy's videos than listening to my professor. I hope he'll be covering the rest of my course as well.

  • holy moley you are an excellent teacher!

    you know how to grab the attention of the viewer and really connect too!

    great job explaining everything and being so thorough!

    you're the type of teacher i want to become like one day! thanks for the inspiration!

  • Thank you so much! i'm taking AP Chem Next year, and ive struggled with stoichemetry the whole year in my gen chem class. This really took care of the problem, in a refreshing way!. Your fantastic! keep up the great work!!!

  • great video thanks alot it help me understand better what im doing

  • MOLY MOLY MOLY MOLY MOLISH!!! Amazing explanation. =)

  • This was a great tutorial! It really helped me out a lot. Thanks for taking your time and putting this up! I really appreciate it!