Added: 1 year ago
From: khanacademy
Views: 17,938
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  • One question: How were you able to determine that the moles of CO₂ are equivalent to the moles of C? Wouldn't O₂ add more to the moles of C in the compound?

  • Thank you sooooooooooooooooooooooooooooo­ooooo much sooooooooooooooooooooooooooooo­ooo much you saved my midterm

  • great video, i used to think of chemistry as a mystery, but not anymore :P

  • thank you soooo much. my final is in 5 hours and your videos are a gift from the heavens. plz replace my chem teacher. 

  • thanks

  • Thank you. So so much.

  • Very fun. ^__^

  • your're the best chemistry teacher known in youtube sir...=)

    I thank you a lot for your effort of posting these videos just to help others in their school problems,not only in chemistry but i've seen your other videos on math subjects.Thank you=) God bless you.

  • thanks so much for these vids! Just wanted to let you know I was really struggling with chem and because I live on Guam everything is so limited and teachers arent that helpful when it comes to breaking it down because they are all off island hires but your work has really helped me these last couple of exams keep up the great work and thanks to you everyone of my class mates comes flocking over me to look at your work! thanks a million!

  • Thank you, I've been learning Chemistry out of books and It's much easier to understand when a human is trying to explain it.

  • wow that was hard lol im confuseddd but makess more sense then it did before :) thanks

  • Hi can you tell me what materials I need to achieve same blackboard with access to tools (such as calculator, and writing tool etc ) as what you have. We teach language online and would like to switch to the set up that you have.

  • @spanishbahamas he is a writing in a writing pad like bamboo in a software like paint or photoshop and recording it with a sreen recorder like hypercam.....and you can take the calcullator which will be there in all the computer...

  • not trying to be an arse of anykind, but just by looking at the molecular Formula you can calculate the formala of CxHy to be CxHx+2 , resulting in x=6 = C6H14 = 86.2 g/mol (:

    but your steps are important for the people who dont immediately see the direct link

    keep up the good work, cheers

  • I did find it fun...

  • if only this vid came out a little eariler...thanks!

  • @akbarthegreat03 ....lol...same here I just finished my CHEm finals today...Sal you have not done anything on Beer's law plot.

  • great video.... thank you thank you.....keep up a good work.

  • ξ(^ω^)

  • Thanks for these videos, really helpful.

  • Comment removed

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