@anujjuneja1 It is easier to realise that for a dy integral, the limits must be y=f(x) and similarly for a dx integral the limits must be x=g(y). That is how my maths professor taught me. Then just make sure you have the constants on the outer integral to ensure that the final value is a scalar, not a function of some other variable.
Thankyou Dony, you really demystify multiple integrals. I can see that the differentiating between Region types I & II will will largely be irrelevant when you understand the mechanics. I am now fearful on not constant regions in volumes!
Hmmm. Very good exposition indeed. Maybe you could do with a bigger board though lol. Do you cover the case when R is a triangle with no side parallel to the x or y axis?
Yup, good question. I see that you are thinking ahead.
A simple answer is that our regions or R are limited to type I and type II, when either the top and bottom, or left and right are bounded by straight lines. I did mention earlier is that plane regions can take a variety of forms and this is why FOR NOW, we will restrict ourselves to simple ones.
The most complicated region we'll deal with is a circle.
Hey Donny, excellent videos, you're a great instructor. However, I have a question over the example in this video. You give the answer to the inside integral as 2y^2 - 3y^3, but after several tries, I keep getting it as 2y^2 - 2y^3, and the final answer as -26/3. I'm giving you the benefit of the doubt, since you're much (much much much) better at math than I am, but I'm still unsure where the mistake could be. Would you be willing to do a quick re-check to make sure you had it right?
Yup, you are indeed right. The result of the inner integral is 2y^2 - 2y^3. However, the final answer is still -68/3 after integrating 2y^2 - 2y^3 wrt to y from 1 to 3.
I think you missed out either one of the coefficients from y^2 or y^3 term.
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browno26 1 month ago
hooray
browno26 1 month ago
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bebefore3 3 months ago
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bebefore3 3 months ago
Dude how to sketch the function and find the region? =( that's crucial before determining the limits...help me please =(
isam1335 1 year ago
thank you, that was such a help!! x
dosyjenks 1 year ago
Did he say high school? Holy shit!
Losuol 1 year ago
@Losuol yeah, western high school is so far behind Asian countries.
DeluxeWarPlaya 1 year ago
hello dony,
my concern is how to find whether it is a "type 1" or "type 2" integral ?
thankyou for your efforts...
:)
zayed123123 1 year ago
@zayed123123
Just check out for the limits...if limits are in term of x, it will be type 2, which i think he mention in 4th lecture if i m right...
Just simply see, if the variable in limits(limits are in terms of x or y), then integrate 1st wrt other variable...I hope its helpful...
anujjuneja1 1 year ago
@anujjuneja1 It is easier to realise that for a dy integral, the limits must be y=f(x) and similarly for a dx integral the limits must be x=g(y). That is how my maths professor taught me. Then just make sure you have the constants on the outer integral to ensure that the final value is a scalar, not a function of some other variable.
DeluxeWarPlaya 1 year ago
@DeluxeWarPlaya
Thats wt I means...:)
anujjuneja1 1 year ago
Thankyou Dony, you really demystify multiple integrals. I can see that the differentiating between Region types I & II will will largely be irrelevant when you understand the mechanics. I am now fearful on not constant regions in volumes!
wizsoft 2 years ago
shouldn't that be 2y^2-2y^3 and not 3y^3? subsequently i get to -36 rather than -68! am i the one who's wrong?
eleynasr 2 years ago
I keep thinking it shoudl be y=0 instead of 1 cause thats where they are equal to each other. I"m I wrong? If so how did u get y=1.
Joyfulkilla 3 years ago
Equations y=-x+1 and y=x+1 imply that both of them edge the y-axis. y=kx+m where the m is 1
Daljo681 3 years ago
Hmmm. Very good exposition indeed. Maybe you could do with a bigger board though lol. Do you cover the case when R is a triangle with no side parallel to the x or y axis?
I tend to move around a lot too :)
Vidrinskas 3 years ago 2
Nice video, but the intergration was wrong. However, its good that someone previously caught that error. Keep up the good work.
UntoldWisdom1 3 years ago 2
i wonder what happens when R hasnt got any flat sides... i'll have to keep watching...
jimmyshitbags 3 years ago 2
Yup, good question. I see that you are thinking ahead.
A simple answer is that our regions or R are limited to type I and type II, when either the top and bottom, or left and right are bounded by straight lines. I did mention earlier is that plane regions can take a variety of forms and this is why FOR NOW, we will restrict ourselves to simple ones.
The most complicated region we'll deal with is a circle.
donylee 3 years ago
Hey Donny, excellent videos, you're a great instructor. However, I have a question over the example in this video. You give the answer to the inside integral as 2y^2 - 3y^3, but after several tries, I keep getting it as 2y^2 - 2y^3, and the final answer as -26/3. I'm giving you the benefit of the doubt, since you're much (much much much) better at math than I am, but I'm still unsure where the mistake could be. Would you be willing to do a quick re-check to make sure you had it right?
imafknninja 3 years ago
Hello imafknninja,
Yup, you are indeed right. The result of the inner integral is 2y^2 - 2y^3. However, the final answer is still -68/3 after integrating 2y^2 - 2y^3 wrt to y from 1 to 3.
I think you missed out either one of the coefficients from y^2 or y^3 term.
donylee 3 years ago
So basically in the inner limits it all comes up to the g2 and g1 functions in terms of the var in the outer integral so it gets wiped.
a good explanation as always and you are probably the first on YT to give such a complete set of lessons , so big props to you yet again.
LongShlong125 3 years ago
wow, you sure like to move around a lot.
facevokk 3 years ago
Haha, I'll do whatever it takes to grab the viewer's attention!
donylee 3 years ago