For problem 19, A is the only correct answer as C cannot be correct since SSA, in the general case, does not prove similarity or congruence. See my comment to the previous video for an explanation.
Side CB and EF would not be sufficient enough to prove that the 2 triangles are equal because you were told that angle A and angle D was congruent as well as side AC and DF. So, if "side B is congruent to side FE" was the right answer, the reasoning behind the response would be AS?S (you're missing an angle, so the triangles can't be congruent and the rule is broken). Thus, AB = DE is the correct answer (A).
That problem that you suspected had 2 correct answers has only one.
If CB is congruent to FE then you could draw 2 triangles. If FE is slightly shorter than FD the circle with center F and radius FE would intersect the horizontal-looking ray from F in two places.
Of course, I am a geometry math teacher so I have "SSA is not a triangle congruence rule" rattling around offensively in my brain.
Absolutely love all your videos. Qn19. though... "There is no ASS in Congruency."
BC~EF does not give us enough proof that the triangles are congruent.
shardakar 6 months ago
at 6:01 can't you make it non-congruent by extending <DE???
ilikesonyps2 8 months ago
For problem 19, A is the only correct answer as C cannot be correct since SSA, in the general case, does not prove similarity or congruence. See my comment to the previous video for an explanation.
konopong 8 months ago
i totally agree about the education that you are talking about
paulceltics 9 months ago
thanks
paulceltics 9 months ago
Side CB and EF would not be sufficient enough to prove that the 2 triangles are equal because you were told that angle A and angle D was congruent as well as side AC and DF. So, if "side B is congruent to side FE" was the right answer, the reasoning behind the response would be AS?S (you're missing an angle, so the triangles can't be congruent and the rule is broken). Thus, AB = DE is the correct answer (A).
hannuka149 10 months ago
This has been flagged as spam show
You were spot on with the rant.
MixesAndStuff 1 year ago
Thank you very much
lildude8210 1 year ago
That problem that you suspected had 2 correct answers has only one.
If CB is congruent to FE then you could draw 2 triangles. If FE is slightly shorter than FD the circle with center F and radius FE would intersect the horizontal-looking ray from F in two places.
Of course, I am a geometry math teacher so I have "SSA is not a triangle congruence rule" rattling around offensively in my brain.
mossheadstone 2 years ago
you spelled congruent wrong had trouble finding it. But you are seriously good teacher.
tabmejojo 2 years ago
lol I actually like the rants
kiaracm 2 years ago