Integration by Substitution - (3a) : ExamSolutions

[saneeyarasheed]

ur work is awesome

[ExamSolutions]

@saneeyarasheed Thank you

[MrValzen]

Thanks, this cleared everything up in the lesson i had of it today.

[mabd]

hey man your tutorial rawks! =)

[Romeowasbleeding1]

Thank you for the "Eureka!" moment!

[ExamSolutions]

@Romeowasbleeding1 Cool - It's good to have a Eureka moment once inb a while.

[kami645464]

thank you so extremely much. I have un upcoming exam on Jan 15th with the hardest bit being integration by substitution and this tutorial is simply amazing! This explains it in a much simpler way than my sh*tty Maths book does. It is so complicated in my book.

Thanks for teaching this method. Thanks so much!!!

[ExamSolutions]

Thanks - glad it helped

[Cyxx08]

On another topic, what if the problem lists ln[square root of] 3x-1 dx

I find it difficult with that ln

Thx for the tutorials!

[ExamSolutions]

Let u = 3x-1 and use integration by parts.

[redders6600]

Think about where we get the x = (u + 1)/3 from.

It's the equation for our substitution rearranged.

Add 1 to both sides of u = 3x - 1 and you get u+1 = 3x, then divide both sides by three, and you get x = (u + 1)/3

That's where the equation comes from.