The time has come for Free energy to be revealed ,But a few ppl make too many billions from our energy needs to let this technology be known,Find a motor that needs no fuel or input at LT-MAGNET-MOTORdotCOM ,Be a part of the energy revolution!
I was also pondering using a darlington pair to reduce the switching time of the transistors, though I'm not sure if will work since the base current from T1 that activates teh transistor will also be flowing through the base of T2 at the same time, so though T1 may provide more base current to T2 after this, if the current is enought to trigger T1 then surely T2 will be triggered at the same speed as T1.
Though I will test it tonight ^_^ see if there is a difference in the spike... not so interested in the mechanical at the moment since this is for my solid state device.
Doesn't look good from my end I'm afraid :( I tried a darlington configuration on my solid state set up and at best the spike is equal, at worst, nonexistent.
When I tried it as shown in your schematic there was no spike at all. Then I tried adding a few different valued resistors on the collector of T1 and as resistance went up the spike increased until it was back to how it was without the darlington.
Has there been any verification that the spike can be increased using a darlington pair?
yes ... makes sense. I will do some testing. The relitive field strength and attraction to the mags in the rotor by the core may cause less drag, speeding up the rpms. However I expect to find less generating potential as the field around the coil is made less intense. I'll let you know........... scooterscottii
I have noticed an interesting effect with my bedidi circuit motor. If I stick some neo mags to the (outside facing) core of the bifoliar coil it will speed up the rpms by about 30%. inversely if I turn the mags around it slows the rpms. What do you think is happening? Scooterscottii
without doing it myself i can only take an educated guess (guestimate)...
The addition of a magnet on the back side of the drive coil will change the 'relitive' field strenght... So without a magnet you start from 'ZERO' and get a 'positive' field at one end and a 'negative' field at the other..
By placing the north side 'positive' of a magnet at the back of the drive coil you increase the relitive magnetic field to the strenght of the magnet, so when you energise the drive coil your actually creating a field thats goint to be N (normal field strenght) + the strenght of the magnet... and the inverse if you put the south side of the magnet to the coil...
THANKS for your input. I was planning to either turn the south around and do all the same or install all south. As it stands I fixed the south and I've put it behind me. It was heartbreaking to tear into the rotor to switch it but in the end it will be best. Thats interesting what you said about the norths often being stronger I have never heard of that. Again thanks, I hope I can help you sometime. scooterscottii ... Scott
Greetings from Oregon! I made a rotor for my SSG circuit with six mags around. Unfortunately the first mag I installed was S facing out toward the coil. Question ... Does it matter which magnetic pole faces the coil? I noticed several people use north. Should I change it? THANKS for any info! Scooterscottii
it does depend on your magnets, but ~80% of them have the north face more 'powerfull' than the south face...
Also... if the rest of them are north out then your bedini will not be pulsing on the south out magnet so you'll be loosing speed, torque and back emf...
It also depends on what your doing with your bedini... other people like me run a N - S - N - S alternating fields for generator coils... But if you've built a bedini just to charge another battery then North only is the way...
I will state that this adaptation can be considered a significant step forward. I was there at the conception of it's use and this is an excellent method. The rotor is faster, it uses less at speed. The pots now have some protection (no more blown pots) and have an increased tuning range requiring a much larger variable and base resistance on the base of the transistor. i run 400 ohm base resistors with 47k variables. 3 pole rotor 2 bifilar coils. Lots of torque. 3 or 4 'gears'.
Hey Kevin, your audio bitstream is back down to about 16 kbs! lol
Some basic concepts about energizing the coil. Your supply voltage over the resistance of the coil gives you your max current. Assuming your transistor supports that the trick is to figure out how much base current Q2 needs to be fully switched on. You can make a simple DC measurement of the base current while you measure the Q2 collector voltage. As you increase the base current the collector voltage drops.
You have the batt +ve through the ammeter through a trimpot + resistor to the base of Q1. You have your voltmeter on the Q1 collector which goes through the main coil to the batt +ve. When the collector is about 0.2-0.3 volts, the transistor is fully on. You take your base current measurement and add 10% to guarantee the transistor will be switched on. Now you know your minimum base current to fully switch on the transistor to fully energize the coil.
Careful about leaving the coil on too long when making measurements because it can heat up and literally become red hot.
Note with the base current measurement and the collector current measurement (just derive it) you have measured the transistor's large signal current amplification. You can check it against the spec sheet. lol
Knowing the base current, you can use that to tune your pickup coil emf and the proper base resistor.
Of course with a Darlington pair setup, you could make the same measurement for the base current for Q1. The much smaller current implies that you can use a higher-value base resistor. If you add turns to your pick-up coil for higher emf and use a Darlington pair with a high value resistor, you would get faster on-off times because the higher voltage gives you a faster voltage slew rate, which is also amplified, hence faster transistor switching.
Suppose the emf from the pickup coil is 20 volts peak to peak. Here is an interesting design choice; at what emf voltage level do you want to fully switch on and by extension switch off the transistor? The hump starts at zero volts and looks like a sine wave at first, but on the down side it tails off. Perhaps at 3 volts, you get a snappy switch on and a snappy switch off, helped a lot by the Darlington pair. So your resistor is (3 - 0.6 -0.6)/min base current. Then TWEAK! lol
I apologize if this stream of consciousness is a bit too much, just a bit more. If you have a very good switching setup then it is almost like you are making a horizontal cut through the post-TDC "hump" from the pickup coil. By raising and lowering the switching voltage you are changing the coil total on time, and shifting the start and stop times. A hybrid could be done when the coil triggers some cascaded 555s giving you complete control over the firing. Call it a thought experiment! lol
ok, i did say right at the beginning that anyone that knows what a darlington pair is will allready know what i'm going to say...
On all my video's i purposly leave out the very technical stuff and put everything into laymans terms so that anyone can benefit from what i know / discover... hence why i have lots of pauses as i'm speaking...
However, if you want technical... i believe you for got to mention the lenz effect from the trigger coil caused by the curent through the single transister
with a darlington pair however, T1 (Q1 on diagram) only allows a small percent through from the trigger coil, ergo oneof the reasons why it spins faster...
I understand everything you said, but i wonder how many people will?
There is an issue related to the total on time and energy stored in the coil. The time constant for the main coil circuit is L/R, where R is the total impedance of the battery and the switched on transistor. You don't want to keep the coil switched on for more than 2 or 3 time constants. Switched on any longer and it acts mostly like a resistor, hence no adding to the back spike. That's gotta be one of the most important considerations for effeciency, avoid burning useless power in the coil.
"time constant's" are not constant nor are they the same from setup to setup...
The speed of the rotor alters the "time constant" even if you consider the "time constant" is per magnet... magnetic induction (within your core) takes time (miliseconds) in order to form a magnetic field, this time is a constant and is not effected by magnet speed...
Also, you use the pot to control how long to pulse is on for...
Hi Kevin, sorry for being a bit too technical the other day, perhaps some readers will get it or it will push the envelope for others. To respond to what you said the other day, yes the Lenz effect from the main coil switching on will affect trigger coil emf also. It can induce a DC voltage bias in either direction, depending on the way the two coils are coupled. The DC bias should soon decay as per the main coil circuit time constant.
In simpler terms the emf from the trigger coil consists of two affects added together, the induced emf from the magnet fly-by and the induced emf from the main coil being switched on by the transistor.
The quicker that you can make the transistor switch on and off, the less power you loose in the transistor. The transistor dissipates almost no power when it is fully off or fully on, but does dissipate power when it's partially conducting. Many people get hot transistors because of this.
Which leads to your comment that transistors are not digital. The two basic applications for transistors are signal amplification (analog) and switching (digital). You can literally construct logic gates with just transistors and resistors.
The "time constant" that I am discussing is again for the oversimplified case where you just look at the coil+transistor+battery. How many milliseconds does it take for the current to reach 63% of it's maximum value?
Again, a simple example: Suppose that when your motor is running at it's top speed, the transistor switches on for 10 milliseconds. Suppose that you also know that the coil+transistor+battery time constant is 2 milliseconds. Your objective is to turn the maximum amount of source batt energy into spikes that go into the charging batt. Therefore your transistor is on for too long. The first 5 mSec charges the coil to almost 100%, the second 5 mSec is lost as batt energy heating the coil.
I hope that you get a scope one day. It's fun to try to get the maximum effeciency, like tuning a Formula 1 race car! lol
A simple time constant example: You take a kettle of hot water and fill your cup. Sit the kettle and cup down and measure how long it takes each one to drop in temp by 63%. The kettle system will have a longer time constant than the cup system. These are "RC" time constants, the kettle has a thermal capacitance and there is a thermal resistance. Temp = voltage.
Exactly, the "R" of the "RC" in this case is the overall thermal resistance between the kettle and the environment. So a large kettle in good contact with a large metal table may have the same time constant as a small cup sitting on an insulating piece of Styrofoam. The analogy translates directly to a capacitor charging or discharging trough a resistor. Or in this case a the battery charging the coil through the circuit resistance.
The interesting thing that you learn in engineering is how similar systems and circuits can operate in different "dimensions" yet all work exactly the same way. You can look at an electrical circuit and imagine mechanical or thermal or gas or fluid analogy to help you visualize how it works.
The one I like for circuits is mechanical. Voltage = velocity, and current = force, capacitance = mass, and inductance = spring stiffness.
The interesting thing that you learn in engineering is how similar systems and circuits can operate in different "dimensions" yet all work exactly the same way. You can look at an electrical circuit and imagine mechanical or thermal or gas or fluid analogy to help you visualize how it works.
The one I like for circuits is mechanical. Voltage = velocity, and current = force, capacitance = mass, and inductance = spring stiffness.
Oops, something weird happened and I lost two more examples... and my last posting appeared twice. A server glitched or my brain glitched, not sure which one.
The time has come for Free energy to be revealed ,But a few ppl make too many billions from our energy needs to let this technology be known,Find a motor that needs no fuel or input at LT-MAGNET-MOTORdotCOM ,Be a part of the energy revolution!
jjerkings2890 1 year ago
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Free Energy is real but the coverup is strong, if you are interested in a REAL free energy machine then
just search for the LT MAGNET MOTOR in the youtube video search , it is probably the ONLY working magnet
motor out there. Join the free energy revolution!!
cloudburstlenepmhq 1 year ago
Testing testing... having trouble posting comments!
introvertebrate 2 years ago
ok... comments seem to be working now...
I was also pondering using a darlington pair to reduce the switching time of the transistors, though I'm not sure if will work since the base current from T1 that activates teh transistor will also be flowing through the base of T2 at the same time, so though T1 may provide more base current to T2 after this, if the current is enought to trigger T1 then surely T2 will be triggered at the same speed as T1.
introvertebrate 2 years ago
Though I will test it tonight ^_^ see if there is a difference in the spike... not so interested in the mechanical at the moment since this is for my solid state device.
Will let you know the results!
introvertebrate 2 years ago
Doesn't look good from my end I'm afraid :( I tried a darlington configuration on my solid state set up and at best the spike is equal, at worst, nonexistent.
When I tried it as shown in your schematic there was no spike at all. Then I tried adding a few different valued resistors on the collector of T1 and as resistance went up the spike increased until it was back to how it was without the darlington.
Has there been any verification that the spike can be increased using a darlington pair?
introvertebrate 2 years ago
Comment removed
LeedsPetShop 2 years ago
Ok, any problems feel free to email me...
comwarrior69 2 years ago
yes ... makes sense. I will do some testing. The relitive field strength and attraction to the mags in the rotor by the core may cause less drag, speeding up the rpms. However I expect to find less generating potential as the field around the coil is made less intense. I'll let you know........... scooterscottii
scooterscottii 2 years ago
Actually, it shouldn't make much diference... but that does depend on which way around you have the magnet...
comwarrior69 2 years ago
I have noticed an interesting effect with my bedidi circuit motor. If I stick some neo mags to the (outside facing) core of the bifoliar coil it will speed up the rpms by about 30%. inversely if I turn the mags around it slows the rpms. What do you think is happening? Scooterscottii
scooterscottii 2 years ago
without doing it myself i can only take an educated guess (guestimate)...
The addition of a magnet on the back side of the drive coil will change the 'relitive' field strenght... So without a magnet you start from 'ZERO' and get a 'positive' field at one end and a 'negative' field at the other..
comwarrior69 2 years ago
By placing the north side 'positive' of a magnet at the back of the drive coil you increase the relitive magnetic field to the strenght of the magnet, so when you energise the drive coil your actually creating a field thats goint to be N (normal field strenght) + the strenght of the magnet... and the inverse if you put the south side of the magnet to the coil...
I hope that makes sence...
comwarrior69 2 years ago
Cool videos....
TommeyReed 2 years ago
THANKS for your input. I was planning to either turn the south around and do all the same or install all south. As it stands I fixed the south and I've put it behind me. It was heartbreaking to tear into the rotor to switch it but in the end it will be best. Thats interesting what you said about the norths often being stronger I have never heard of that. Again thanks, I hope I can help you sometime. scooterscottii ... Scott
scooterscottii 2 years ago
Greetings from Oregon! I made a rotor for my SSG circuit with six mags around. Unfortunately the first mag I installed was S facing out toward the coil. Question ... Does it matter which magnetic pole faces the coil? I noticed several people use north. Should I change it? THANKS for any info! Scooterscottii
scooterscottii 2 years ago
it does depend on your magnets, but ~80% of them have the north face more 'powerfull' than the south face...
Also... if the rest of them are north out then your bedini will not be pulsing on the south out magnet so you'll be loosing speed, torque and back emf...
It also depends on what your doing with your bedini... other people like me run a N - S - N - S alternating fields for generator coils... But if you've built a bedini just to charge another battery then North only is the way...
comwarrior69 2 years ago
theirs only me and pwordchernoir that have tried this...
Anyone else done it yet?
comwarrior69 2 years ago
I will state that this adaptation can be considered a significant step forward. I was there at the conception of it's use and this is an excellent method. The rotor is faster, it uses less at speed. The pots now have some protection (no more blown pots) and have an increased tuning range requiring a much larger variable and base resistance on the base of the transistor. i run 400 ohm base resistors with 47k variables. 3 pole rotor 2 bifilar coils. Lots of torque. 3 or 4 'gears'.
REPLICATE!!!!
Pwordchernoir 2 years ago
Your videos are great! I have learned a lot from them. Thank you. I am working on my Bedini powered by a joule thief circuit.
Bill
Pirate88179 2 years ago
Hey Kevin, your audio bitstream is back down to about 16 kbs! lol
Some basic concepts about energizing the coil. Your supply voltage over the resistance of the coil gives you your max current. Assuming your transistor supports that the trick is to figure out how much base current Q2 needs to be fully switched on. You can make a simple DC measurement of the base current while you measure the Q2 collector voltage. As you increase the base current the collector voltage drops.
Drevtoobe 2 years ago
You have the batt +ve through the ammeter through a trimpot + resistor to the base of Q1. You have your voltmeter on the Q1 collector which goes through the main coil to the batt +ve. When the collector is about 0.2-0.3 volts, the transistor is fully on. You take your base current measurement and add 10% to guarantee the transistor will be switched on. Now you know your minimum base current to fully switch on the transistor to fully energize the coil.
Drevtoobe 2 years ago
Careful about leaving the coil on too long when making measurements because it can heat up and literally become red hot.
Note with the base current measurement and the collector current measurement (just derive it) you have measured the transistor's large signal current amplification. You can check it against the spec sheet. lol
Knowing the base current, you can use that to tune your pickup coil emf and the proper base resistor.
Drevtoobe 2 years ago
Of course with a Darlington pair setup, you could make the same measurement for the base current for Q1. The much smaller current implies that you can use a higher-value base resistor. If you add turns to your pick-up coil for higher emf and use a Darlington pair with a high value resistor, you would get faster on-off times because the higher voltage gives you a faster voltage slew rate, which is also amplified, hence faster transistor switching.
Drevtoobe 2 years ago
Suppose the emf from the pickup coil is 20 volts peak to peak. Here is an interesting design choice; at what emf voltage level do you want to fully switch on and by extension switch off the transistor? The hump starts at zero volts and looks like a sine wave at first, but on the down side it tails off. Perhaps at 3 volts, you get a snappy switch on and a snappy switch off, helped a lot by the Darlington pair. So your resistor is (3 - 0.6 -0.6)/min base current. Then TWEAK! lol
Drevtoobe 2 years ago
I apologize if this stream of consciousness is a bit too much, just a bit more. If you have a very good switching setup then it is almost like you are making a horizontal cut through the post-TDC "hump" from the pickup coil. By raising and lowering the switching voltage you are changing the coil total on time, and shifting the start and stop times. A hybrid could be done when the coil triggers some cascaded 555s giving you complete control over the firing. Call it a thought experiment! lol
Drevtoobe 2 years ago
ok, i did say right at the beginning that anyone that knows what a darlington pair is will allready know what i'm going to say...
On all my video's i purposly leave out the very technical stuff and put everything into laymans terms so that anyone can benefit from what i know / discover... hence why i have lots of pauses as i'm speaking...
However, if you want technical... i believe you for got to mention the lenz effect from the trigger coil caused by the curent through the single transister
comwarrior69 2 years ago
with a darlington pair however, T1 (Q1 on diagram) only allows a small percent through from the trigger coil, ergo oneof the reasons why it spins faster...
I understand everything you said, but i wonder how many people will?
ever herd of KISS?
Keep It Simple Stupid
comwarrior69 2 years ago
There is an issue related to the total on time and energy stored in the coil. The time constant for the main coil circuit is L/R, where R is the total impedance of the battery and the switched on transistor. You don't want to keep the coil switched on for more than 2 or 3 time constants. Switched on any longer and it acts mostly like a resistor, hence no adding to the back spike. That's gotta be one of the most important considerations for effeciency, avoid burning useless power in the coil.
Drevtoobe 2 years ago
i have two issues with what you just said...
"time constant's" are not constant nor are they the same from setup to setup...
The speed of the rotor alters the "time constant" even if you consider the "time constant" is per magnet... magnetic induction (within your core) takes time (miliseconds) in order to form a magnetic field, this time is a constant and is not effected by magnet speed...
Also, you use the pot to control how long to pulse is on for...
Transisters are not digital...
comwarrior69 2 years ago
Hi Kevin, sorry for being a bit too technical the other day, perhaps some readers will get it or it will push the envelope for others. To respond to what you said the other day, yes the Lenz effect from the main coil switching on will affect trigger coil emf also. It can induce a DC voltage bias in either direction, depending on the way the two coils are coupled. The DC bias should soon decay as per the main coil circuit time constant.
Drevtoobe 2 years ago
In simpler terms the emf from the trigger coil consists of two affects added together, the induced emf from the magnet fly-by and the induced emf from the main coil being switched on by the transistor.
The quicker that you can make the transistor switch on and off, the less power you loose in the transistor. The transistor dissipates almost no power when it is fully off or fully on, but does dissipate power when it's partially conducting. Many people get hot transistors because of this.
Drevtoobe 2 years ago
Which leads to your comment that transistors are not digital. The two basic applications for transistors are signal amplification (analog) and switching (digital). You can literally construct logic gates with just transistors and resistors.
The "time constant" that I am discussing is again for the oversimplified case where you just look at the coil+transistor+battery. How many milliseconds does it take for the current to reach 63% of it's maximum value?
Drevtoobe 2 years ago
Again, a simple example: Suppose that when your motor is running at it's top speed, the transistor switches on for 10 milliseconds. Suppose that you also know that the coil+transistor+battery time constant is 2 milliseconds. Your objective is to turn the maximum amount of source batt energy into spikes that go into the charging batt. Therefore your transistor is on for too long. The first 5 mSec charges the coil to almost 100%, the second 5 mSec is lost as batt energy heating the coil.
Drevtoobe 2 years ago
I hope that you get a scope one day. It's fun to try to get the maximum effeciency, like tuning a Formula 1 race car! lol
A simple time constant example: You take a kettle of hot water and fill your cup. Sit the kettle and cup down and measure how long it takes each one to drop in temp by 63%. The kettle system will have a longer time constant than the cup system. These are "RC" time constants, the kettle has a thermal capacitance and there is a thermal resistance. Temp = voltage.
Drevtoobe 2 years ago
going with the kettle analogy...
But the rate with which the kettle heats or cools depends on the environmental temp....
So, your time constant has to encorporate environmental temp and it's cooling effect on the kettle....
comwarrior69 2 years ago
Exactly, the "R" of the "RC" in this case is the overall thermal resistance between the kettle and the environment. So a large kettle in good contact with a large metal table may have the same time constant as a small cup sitting on an insulating piece of Styrofoam. The analogy translates directly to a capacitor charging or discharging trough a resistor. Or in this case a the battery charging the coil through the circuit resistance.
Drevtoobe 2 years ago
The interesting thing that you learn in engineering is how similar systems and circuits can operate in different "dimensions" yet all work exactly the same way. You can look at an electrical circuit and imagine mechanical or thermal or gas or fluid analogy to help you visualize how it works.
The one I like for circuits is mechanical. Voltage = velocity, and current = force, capacitance = mass, and inductance = spring stiffness.
An LC resonator = a mass on a spring.
Drevtoobe 2 years ago
The interesting thing that you learn in engineering is how similar systems and circuits can operate in different "dimensions" yet all work exactly the same way. You can look at an electrical circuit and imagine mechanical or thermal or gas or fluid analogy to help you visualize how it works.
The one I like for circuits is mechanical. Voltage = velocity, and current = force, capacitance = mass, and inductance = spring stiffness.
An LC resonator = a mass on a spring.
Drevtoobe 2 years ago
Oops, something weird happened and I lost two more examples... and my last posting appeared twice. A server glitched or my brain glitched, not sure which one.
Drevtoobe 2 years ago
Charge rate would be interesting to test.
marthale7 2 years ago
Marthale, please do so and post back with the two results and also tell me what transisters your using...
And yes, if your using disimilar transisters it does matter which way around they are...
comwarrior69 2 years ago