Summary of Curve Sketching - Example 2, Part 1 of 4

[AmyStarx3]

You should really write a book on AP CAL!! I would defiantly buy it!

[Fun2BJinny]

@MrBladeSlayer Technically, if you were testing symmetry, when you put it (-x)^2, and it turns out to be a positive x, you can just put it back into the equation as x^2 since you're not trying to solve the equation, but more just testing if the x will become negative or stay positive. For example, f(x)=x^2-x, so f(-x)=(-x)^2-(-x), which becomes f(-x)=x^2+x, and there is no symmetry because f(-x) doesn't equal -f(x) or f(x).

[againanotherone]

i'm on a video binge. this is literally the seventh one today. tackling midterms just got a whooooole lot easier <3 thank you very much! (also was so tired that read "parts" as "pants" which was sort of sexy/creepy)

[ermitz90]

SIr Patrick..may I know how about a curve symmetry to x-axis rather than y-axis and origin...is there anyway to demonstrate that??

[ltsmash09]

dude, you're the duke nukem of calculus

[steve15sanchez]

your so fucking hot

[jonasHOESx3]

how would you find the intercepts and asymptotes of the equation:

y = 1 + (1/x) + (1/x^2)

y equals one plus one over x plus one over x squared

thanksss

[zsozsokel]

@jonasHOESx3 first of all make it one single fraction, and then:

Equal it to zero -> x intercept

Substitute zero for x -> y intercept

find the limit at infinity -> asymptote.

good luck

[ZR666]

Can't I just use my calculator ;)

[Arcillica1]

@ZR666 I wish we could

[khalid97899789]

wow thanx patrick . you are a king ... but i think this calculus 1

we need more example of calculus 3 ((vector integral))