THANK U SOOOO MUCH!!!! A few weeks back, we got an integral- intgrl((e^x)/(sqrt(e^(2x)+(e^x)+1)dx), a miswritten integral ((e^x)/(sqrt(e^(2x)+2(e^x)+1)dx)- which is simple. The former one was considered impossible, but I figured out it equals: ln|(2sqrt(e^(2x)+(e^x)+1)+2(e^x)+1)/(sqrt(3))|+C, by using that tan substitution (v*sqrt(3)/2=tan(theta), in my case) as the third substitution, which allowed everything to work. Can't wait to show my math teacher my success. Oh and btw SUBSCRIBED
@amn2o I believe that the correct form is "You're." I think that a nark tells the police about the drugs. In order to finish quickly, I have to skip steps. The teaching aspect is to get the viewer to fill in the details. I don't know how British people pronounce "theta." I almost certainly do not pronounce it correctly since I grew up in the southern United States. I am not sure what the native tongue is in that part of the world, but I have been know to use that dialect.
o.k., but how should i know in to what trigonometrical variables i need to transform x? How should i know that for this integral x must be equal to 3sin() instead of (for example) 9sin(2)?
shit that was so difficult
BelieveDon 2 months ago
THANK U SOOOO MUCH!!!! A few weeks back, we got an integral- intgrl((e^x)/(sqrt(e^(2x)+(e^x)+1)dx), a miswritten integral ((e^x)/(sqrt(e^(2x)+2(e^x)+1)dx)- which is simple. The former one was considered impossible, but I figured out it equals: ln|(2sqrt(e^(2x)+(e^x)+1)+2(e^x)+1)/(sqrt(3))|+C, by using that tan substitution (v*sqrt(3)/2=tan(theta), in my case) as the third substitution, which allowed everything to work. Can't wait to show my math teacher my success. Oh and btw SUBSCRIBED
teranz0 2 months ago
your just a nark whos trying to show off. why you going so fast you dick your spose to be teaching. and please pronounce theta correctly you yank
amn2o 3 months ago
@amn2o I believe that the correct form is "You're." I think that a nark tells the police about the drugs. In order to finish quickly, I have to skip steps. The teaching aspect is to get the viewer to fill in the details. I don't know how British people pronounce "theta." I almost certainly do not pronounce it correctly since I grew up in the southern United States. I am not sure what the native tongue is in that part of the world, but I have been know to use that dialect.
ProfessorElvisZap 2 months ago
o.k., but how should i know in to what trigonometrical variables i need to transform x? How should i know that for this integral x must be equal to 3sin() instead of (for example) 9sin(2)?
TadyZaZ 11 months ago
@TadyZaZ That issue is addressed in my video entitled Inverse Trig Functions: The three main triangles
ProfessorElvisZap 11 months ago