Another thing I noticed is that you mention that the wire diameter is 0.1mm, but it looks like you wrote 0.1m on the board. Pretty clear from your area calculation that you meant 0.1mm though.
ermmm....the expression of resistanceof the gauge should be R=(rho*l)/A, not R=(rho*A)/l.you make me confuse for a while.anyway,thanks for this video, I became more confident to overcomes my fear regarding my electronic instrumentation test next week =)
Oh by the way, I stumbled onto this vids because I am trying to make a straingauge for a microcantilever. In that case I think the piezoresistive effects will start to work, therefore the gauge factor can be as high as 50, instead of the usual 2.2 for gold. For doped silicon (semiconductor tech) the gauge factors can be as high as 150 I think. I liked your explanation of the factor 2 in the second video. But if you want a more accurate but still easy explanation, try:
@r00ntje John Bentley: Principles of Measurement systems. There the gauge factor is derived from DR/R = (1++2*nu)*epsilon +Drho/rho. The latter term is the piezoresistive effect contribution. But I guess that is not really relevant to your area of expertise. Anyways, just wanted to say thanks for the vids, you explained it nicely.
@r00ntje Thanks for noticing and passing that on. It is indeed a boo-boo. For now, I put a note in the description. I'll eventually need to re-shoot this one.
nice video..!!!! thanks to the uploader..
Thekingdonarun 5 months ago
Another thing I noticed is that you mention that the wire diameter is 0.1mm, but it looks like you wrote 0.1m on the board. Pretty clear from your area calculation that you meant 0.1mm though.
Thanks for the video.
ptuxbury 8 months ago
ermmm....the expression of resistanceof the gauge should be R=(rho*l)/A, not R=(rho*A)/l.you make me confuse for a while.anyway,thanks for this video, I became more confident to overcomes my fear regarding my electronic instrumentation test next week =)
kyuneecha90 11 months ago
Oh by the way, I stumbled onto this vids because I am trying to make a straingauge for a microcantilever. In that case I think the piezoresistive effects will start to work, therefore the gauge factor can be as high as 50, instead of the usual 2.2 for gold. For doped silicon (semiconductor tech) the gauge factors can be as high as 150 I think. I liked your explanation of the factor 2 in the second video. But if you want a more accurate but still easy explanation, try:
r00ntje 1 year ago
@r00ntje John Bentley: Principles of Measurement systems. There the gauge factor is derived from DR/R = (1++2*nu)*epsilon +Drho/rho. The latter term is the piezoresistive effect contribution. But I guess that is not really relevant to your area of expertise. Anyways, just wanted to say thanks for the vids, you explained it nicely.
r00ntje 1 year ago
jup, you made a boo-boo it should be R= rho*L/A
r00ntje 1 year ago
@r00ntje Thanks for noticing and passing that on. It is indeed a boo-boo. For now, I put a note in the description. I'll eventually need to re-shoot this one.
purdueMET 1 year ago
what about strain gauges set up in a "strain rosette" manner?
JVinci16 1 year ago
R=P*L/A
kosse66 1 year ago
@kosse66 You are right. I put a note in the description and will re-shoot the video when I have some time.
purdueMET 1 year ago