Calculus II - Integrate by Trigonometric Substitution-VideoMathTeacher.com

[TheSingerwannabe1]

Would it not be easier to take the form of 1/a arctan(u/a). Just identify u and a. If u=x then du=dx, which you have already. a=1. Therefore, 1/1arctan(x/1) + C(if indefinite) which then turns to arctan(x) +C. Now just plug in the numbers from the integrand and recall that arctan(x) has a domain of pi/2 to -pi/2.

[rykburch]

on the unit circle cos and sin of pi/4 is sqrt(2)/2 therefor tan^-1(1) is pi/4

[zonesthesia]

wow. some of the peeps leaving comments here need a lesson on the unit cirlce before they try to perform the integral calculus!

[Yu2Kal]

i got 0.25 , 1/4, fuck knows what this geeza is going some next level thing

[aldofrios]

where are you getting pi/4?

[kicker2666]

@aldofrios he got it from the unit circle. tan = sin/cos, and at the point of pi/4 on the unit cirlce, both sin and cos are sqr2/2, so it equals 1

[mprochazka1]

I have been looking for a bare bones example so I could understand the technique without all the mess of a bunch of numbers. This is the best one to learn from!