I thought this video was excellent, for people that don't understand. It doesn't get much easier than this, read a section on subnetting from a sybex book and this video will make sense.
Lamme es un excelente instructor, les invito a ver mi canal, y mis videos soy instructor certificado Cisco en mexico y estoy subiendo muchos videos interesantes en Español pero manteniendo la terminologia en ingles. gracias
I'm sorry,but I didn't learn squat diddly from this video.Thats not saying much bcause I haven't learned shiz from any of these videos.Subnetting for me is just some really difficult crap to learn. I'm not sure what type of help I need, but I defenetly need some........HELP!!!!!!!!!!!
@roybunch76 He took /26 as an example and said how to make a subnet chart. Instead of using the cheat sheet he used, maybe it would've been easier to tell the formulas? So here goes:
Block Size=256-b (where b is the subnet host #) ex: 255.255.255.192 (b = 192); so block size:256-192=64
# of subnets=2^n(where n is the number of 1s in binary in the host portion); 255 is 8 1s in binary; how much is 192? 192 is 2 1s:110000000 = 192; so 2^2 = 4; that is why there are 4 subnets
@roybunch76@roybunch76 continuing from my last post with "# of subnets"; there are other formulas:
# of hosts=2^(h-2) (where h is the number of 0s in the host portion) ex: in 255.255.255.192; there are 6 0s in the host portion when converted to binary; so take 2^(6-2)=62 hosts
# of networks=2^(n-2) (where n is the number of 1s in the network portion) in the video example it would be /26; so /26 = network bits; therefore = 2^(26-2) = 67,108,862 = networks
Now getting to the video: he just told us all how to make a subnet chart to make it much easier to subnet.
he used the 0 subnet: 192.168.1.0 (no host can be here); and then he added the block # (which in this case was 64 to each the 0 subnet: again no host can be here).
He tells you how to get the broadcast / first host range / last host range: the last octet he is talking about is the 0 subnet;
By default the first address of any subnet is reserved to SUBNETWORK ID In
your case 192.168.1.0 can not be used that also makes 192.168.1.63 not usable because of BROADCAST ID just like .64 .128. .192 for network id and .127 .191 etc
for broadcast id. only what's in between can be applied for host application e.g.
@Dark0Temptation there is a formula: 2^n (where n is # of 1s in the host portion when converted to binary); in the example: there are 2 1s in the host portion (255.255.255.192): 192 is the host portion so what is 192 in binary? 11000000; therefore use the formula: 2^n; and n = 2; so 2^2 = 4 so 4 subnets
So If i had for example 192.168.1.23 /27 255.255.255.224 Subnets = 8 192.168.1.0 192.168.1.32 192.168.1.64 192.168.1.96 192.168.1.128 192.168.1.160 192.168.1.192 192.168.1.224 So each router could have the subnet and each range of subnet a number of 30 hosts for each router?
The /26 is just 2 bits taken from the host. Normally a regular class C network is /24 (8 bits), so for the network the equation is 2^2 = 4. You take two bits and do the power of 2, gives you 4 networks. Because you're taking two bits. You start from the left (at 128). 128 + 64 = 192 and that's the highest subnet you can go to. To find out the number of hosts, you have 6 bits, so do 2^6 = 64 -2 for network and broadcast, you get 62 hosts for /26
This comment has received too many negative votesshow
One thing to remember too is this. Don't use anything other than titanium fitzgibbons pins to hold your subnet to your mask. The aluminum ones they use to use tend to break. Also be sure that no unique constraints are violated while jumping from primary to foreign keys.
where did the slash /26 come from? the address is 192.168.1.23, so if 4 octets are 32 bit, where does 26 bit come from and where and how does /26 come into all of it!??. I have spent the last 2 weeks wracking my brain over this and i think i am going mental!
26 means that 26 bits of the 32 bit address are the network, so that leaves 6 bits for the host. This is so-called CIDR (Classless Inter-Domain Routing) notation, or "slash notation". Try doing a search on CIDR and you should come up with comments that explain this notation.
This is not really clear. If you are trying to learn this then explain more. Like where did 26 come from? How did you end up with 192.168.1.0 ?? I guess this assumes too much.
You need to go back to the basic subnetting videos if you dont get it... however considering this messages was a year ago you probably know a whole lot more than I do.
I thought this video was excellent, for people that don't understand. It doesn't get much easier than this, read a section on subnetting from a sybex book and this video will make sense.
snoochmaster 2 months ago
nice
The1ndependent 6 months ago
Fantastic!
Can I download your chart? Do you have it available for download?
didancc 9 months ago
Lamme es un excelente instructor, les invito a ver mi canal, y mis videos soy instructor certificado Cisco en mexico y estoy subiendo muchos videos interesantes en Español pero manteniendo la terminologia en ingles. gracias
NetTrainingOnline 10 months ago
I'm sorry,but I didn't learn squat diddly from this video.Thats not saying much bcause I haven't learned shiz from any of these videos.Subnetting for me is just some really difficult crap to learn. I'm not sure what type of help I need, but I defenetly need some........HELP!!!!!!!!!!!
roybunch76 10 months ago
Comment removed
xanaphuis 4 months ago
@roybunch76 He took /26 as an example and said how to make a subnet chart. Instead of using the cheat sheet he used, maybe it would've been easier to tell the formulas? So here goes:
Block Size=256-b (where b is the subnet host #) ex: 255.255.255.192 (b = 192); so block size:256-192=64
# of subnets=2^n(where n is the number of 1s in binary in the host portion); 255 is 8 1s in binary; how much is 192? 192 is 2 1s:110000000 = 192; so 2^2 = 4; that is why there are 4 subnets
xanaphuis 4 months ago
Comment removed
xanaphuis 4 months ago
This has been flagged as spam show
@roybunch76 @roybunch76 continuing from my last post with "# of subnets"; there are other formulas:
# of hosts=2^(h-2) (where h is the number of 0s in the host portion) ex: in 255.255.255.192; there are 6 0s in the host portion when converted to binary; so take 2^(6-2)=62 hosts
# of networks=2^(n-2) (where n is the number of 1s in the network portion) in the video example it would be /26; so /26 = network bits; therefore = 2^(26-2) = 67,108,862 = networks
These should be the main formulas...
xanaphuis 4 months ago
Now getting to the video: he just told us all how to make a subnet chart to make it much easier to subnet.
he used the 0 subnet: 192.168.1.0 (no host can be here); and then he added the block # (which in this case was 64 to each the 0 subnet: again no host can be here).
He tells you how to get the broadcast / first host range / last host range: the last octet he is talking about is the 0 subnet;
I hope this explains some things...
xanaphuis 4 months ago
Man you didn't explain anything ! what you did was litterly just solve it and leave the people in blank..
salah2110 11 months ago
This guy just made my mind explode.
S1lv3rdo7 1 year ago
Hi Paul do you have examples on how to subnet class A and B? Your video on subnetting class C is very user friendly.
Thank You
DhavalTrupti 1 year ago
@christianh10 - I don't have a garden? Must be somebody elses house!
paulwbrowning 1 year ago 5
Hi
By default the first address of any subnet is reserved to SUBNETWORK ID In
your case 192.168.1.0 can not be used that also makes 192.168.1.63 not usable because of BROADCAST ID just like .64 .128. .192 for network id and .127 .191 etc
for broadcast id. only what's in between can be applied for host application e.g.
1-62 65-126 129-190 etc.
chimmyyammi 1 year ago
that is actually a class c..but what if the given will be a class a/b how will this work?
Jayricwalker 1 year ago
Subnetting in 2:34 minutes....This is good stuff...you explained it well in a short period of time.
DjAdam16 1 year ago
This has been flagged as spam show
Hey can u help me with this:
Needs 6 department and at lease 60host per subnet....
so which ip class and subnet mask should i use?
Pls Help Thanks
anura182 1 year ago
This has been flagged as spam show
Hey can u help me with this:
Needs 6 department and at lease 60host per subnet....
so which ip class and subnet mask should i use?
Pls Help Thanks
anura182 1 year ago
This has been flagged as spam show
Hey can u help me with this:
Needs 6 department and at lease 60host per subnet....
so which ip class and subnet mask should i use?
Pls Help Thanks
anura182 1 year ago
my teacher taught me this way. Too easy!!!!
psalmsyn 1 year ago
@christianh10 lol got mine tomorrow and hope my result is the same haha xD
sp00l 1 year ago
Oke.. when you see /26 you know it's 255......192
But how do you know how much subnets there are?
In this video there are 4 subnets with steps of 64... but why it ends by 192?
Who can explain that to me easy? thaaankss!
Dark0Temptation 1 year ago
@Dark0Temptation there is a formula: 2^n (where n is # of 1s in the host portion when converted to binary); in the example: there are 2 1s in the host portion (255.255.255.192): 192 is the host portion so what is 192 in binary? 11000000; therefore use the formula: 2^n; and n = 2; so 2^2 = 4 so 4 subnets
xanaphuis 4 months ago
it is the best demonstration on subnetting
go ahead
0071rajesh1 1 year ago
That was very very easy
teresa3383 2 years ago
simply... /27 is the slash notation example given...
remember that in every subnetting we have 8 octets for 0 and 1.
therefore you must remeber for every octetcs given it corresponds the default 1's of 128, 192, 224, 240, 248, 252, 254, 255..
0n1nrap3 2 years ago
very good!
kingbobtellem 2 years ago
u explain stuff really easy!!!!!!!THANKS!!!!!!!
ganmanG 2 years ago
if u have an ip add 192.168.1.23/27
look for subnet mask?
1. see /27, u count to ur finger starting from 25 = 128 , 26 = 192 , and 27 = 224
2. therefore the subnet mask is 255.255.255.224.
0n1nrap3 2 years ago
Very good way of putting. Thank you Paul for sharing your subnetting knowledge. You should make one for VLSM.
ITStudent01 2 years ago
THANK YOU.
ijakeii 2 years ago
THAAAANKS
Drift88king 2 years ago
rahungry 2 years ago 8
that looks good to me.
bnelms22 2 years ago
how do u know which number of last octet to pick? between 0 and 224..is there a formula?
Ubon94 2 years ago
23 is between 0 and 32
192.168.1.0 - 192.168.1.32
Therefore,
host 192.168.1.23 is within:
192.168.1.1 - 192.168.1.30 subnet,
where,
192.168.1.0= network address
192.168.1.31=broadcast address [11111]
fair7deal 2 years ago
pls. explain describe this backgarden? :-)
prepsicola 2 years ago
Very good tutorial. Very easy to follow. Cheat sheets. Need one of them :)
itsfuzzy 3 years ago
I think I get this. Correct me if I'm wrong.
The /26 is just 2 bits taken from the host. Normally a regular class C network is /24 (8 bits), so for the network the equation is 2^2 = 4. You take two bits and do the power of 2, gives you 4 networks. Because you're taking two bits. You start from the left (at 128). 128 + 64 = 192 and that's the highest subnet you can go to. To find out the number of hosts, you have 6 bits, so do 2^6 = 64 -2 for network and broadcast, you get 62 hosts for /26
SMGslimg00dy 3 years ago
correct =)
gerreth 2 years ago
THANKS! This really helps a lot! You rock!
imistahbooi 3 years ago
This comment has received too many negative votes show
One thing to remember too is this. Don't use anything other than titanium fitzgibbons pins to hold your subnet to your mask. The aluminum ones they use to use tend to break. Also be sure that no unique constraints are violated while jumping from primary to foreign keys.
jamescaptainfarrell 3 years ago
where did the slash /26 come from? the address is 192.168.1.23, so if 4 octets are 32 bit, where does 26 bit come from and where and how does /26 come into all of it!??. I have spent the last 2 weeks wracking my brain over this and i think i am going mental!
blade004 3 years ago
26 means that 26 bits of the 32 bit address are the network, so that leaves 6 bits for the host. This is so-called CIDR (Classless Inter-Domain Routing) notation, or "slash notation". Try doing a search on CIDR and you should come up with comments that explain this notation.
charles1967 3 years ago
you own i sub lol
NewZealandBoi11 3 years ago
the /26 represent subnetmask i know this just suck vide this dude need take some class about subnet
87655788 3 years ago
@87655788 dude, you need to take a class on how to type English.
rototiller78 5 months ago
@rototiller78 i need take a class on how to type English ? break down what did i miss Mr English professor
87655788 5 months ago
and so on
87655788 3 years ago
thanks, easiest way yet.
hattsternz 3 years ago
nice one paul
fubar2511 3 years ago
This is not really clear. If you are trying to learn this then explain more. Like where did 26 come from? How did you end up with 192.168.1.0 ?? I guess this assumes too much.
Cosmopoet 3 years ago
I just realised you posted this because this also has me confused as to how /26 came into all of it?
blade004 3 years ago
You need to go back to the basic subnetting videos if you dont get it... however considering this messages was a year ago you probably know a whole lot more than I do.
prepsicola 2 years ago 2
mediocre
diehard2006 3 years ago
That was easy.
tenchi77 4 years ago
Wow, thanks man. This is great, very easy this way.
moersenice 4 years ago