Learn to Subnet the Easy Way

[snoochmaster]

I thought this video was excellent, for people that don't understand. It doesn't get much easier than this, read a section on subnetting from a sybex book and this video will make sense.

[The1ndependent]

nice

[didancc]

Fantastic!

Can I download your chart? Do you have it available for download?

[NetTrainingOnline]

Lamme es un excelente instructor, les invito a ver mi canal, y mis videos soy instructor certificado Cisco en mexico y estoy subiendo muchos videos interesantes en Español pero manteniendo la terminologia en ingles. gracias

[roybunch76]

I'm sorry,but I didn't learn squat diddly from this video.Thats not saying much bcause I haven't learned shiz from any of these videos.Subnetting for me is just some really difficult crap to learn. I'm not sure what type of help I need, but I defenetly need some........HELP!!!!!!!!!!!

[xanaphuis]

@roybunch76 He took /26 as an example and said how to make a subnet chart. Instead of using the cheat sheet he used, maybe it would've been easier to tell the formulas? So here goes:

Block Size=256-b (where b is the subnet host #) ex: 255.255.255.192 (b = 192); so block size:256-192=64

# of subnets=2^n(where n is the number of 1s in binary in the host portion); 255 is 8 1s in binary; how much is 192? 192 is 2 1s:110000000 = 192; so 2^2 = 4; that is why there are 4 subnets

[xanaphuis]

Now getting to the video: he just told us all how to make a subnet chart to make it much easier to subnet.

he used the 0 subnet: 192.168.1.0 (no host can be here); and then he added the block # (which in this case was 64 to each the 0 subnet: again no host can be here).

He tells you how to get the broadcast / first host range / last host range: the last octet he is talking about is the 0 subnet;

I hope this explains some things...

[salah2110]

Man you didn't explain anything ! what you did was litterly just solve it and leave the people in blank..

[S1lv3rdo7]

This guy just made my mind explode.

[DhavalTrupti]

Hi Paul do you have examples on how to subnet class A and B? Your video on subnetting class C is very user friendly.

Thank You

[chimmyyammi]

Hi

By default the first address of any subnet is reserved to SUBNETWORK ID In

your case 192.168.1.0 can not be used that also makes 192.168.1.63 not usable because of BROADCAST ID just like .64 .128. .192 for network id and .127 .191 etc

for broadcast id. only what's in between can be applied for host application e.g.

1-62 65-126 129-190 etc.

[Jayricwalker]

that is actually a class c..but what if the given will be a class a/b how will this work?

[DjAdam16]

Subnetting in 2:34 minutes....This is good stuff...you explained it well in a short period of time.

[psalmsyn]

my teacher taught me this way. Too easy!!!!

[Dark0Temptation]

Oke.. when you see /26 you know it's 255......192

But how do you know how much subnets there are?

In this video there are 4 subnets with steps of 64... but why it ends by 192?

Who can explain that to me easy? thaaankss!

[xanaphuis]

@Dark0Temptation there is a formula: 2^n (where n is # of 1s in the host portion when converted to binary); in the example: there are 2 1s in the host portion (255.255.255.192): 192 is the host portion so what is 192 in binary? 11000000; therefore use the formula: 2^n; and n = 2; so 2^2 = 4 so 4 subnets

[0071rajesh1]

it is the best demonstration on subnetting

go ahead

[teresa3383]

That was very very easy

[0n1nrap3]

simply... /27 is the slash notation example given...

remember that in every subnetting we have 8 octets for 0 and 1.

therefore you must remeber for every octetcs given it corresponds the default 1's of 128, 192, 224, 240, 248, 252, 254, 255..

[kingbobtellem]

very good!

[ganmanG]

u explain stuff really easy!!!!!!!THANKS!!!!!!!

[0n1nrap3]

if u have an ip add 192.168.1.23/27

look for subnet mask?

1. see /27, u count to ur finger starting from 25 = 128 , 26 = 192 , and 27 = 224

2. therefore the subnet mask is 255.255.255.224.

[ITStudent01]

Very good way of putting. Thank you Paul for sharing your subnetting knowledge. You should make one for VLSM.

[ijakeii]

THANK YOU.

[Drift88king]

THAAAANKS

[rahungry]

So If i had for example 192.168.1.23 /27 255.255.255.224 Subnets = 8 192.168.1.0 192.168.1.32 192.168.1.64 192.168.1.96 192.168.1.128 192.168.1.160 192.168.1.192 192.168.1.224 So each router could have the subnet and each range of subnet a number of 30 hosts for each router?

[bnelms22]

that looks good to me.

[Ubon94]

how do u know which number of last octet to pick? between 0 and 224..is there a formula?

[fair7deal]

23 is between 0 and 32

192.168.1.0 - 192.168.1.32

Therefore,

host 192.168.1.23 is within:

192.168.1.1 - 192.168.1.30 subnet,

where,

192.168.1.0= network address

192.168.1.31=broadcast address [11111]

[Elmeighty]

stumbled and i rlly like how this guy teaches it...my other instructors suck at it lol. thx for sharing it. :)

[itsfuzzy]

Very good tutorial. Very easy to follow. Cheat sheets. Need one of them :)

[SMGslimg00dy]

I think I get this. Correct me if I'm wrong.

The /26 is just 2 bits taken from the host. Normally a regular class C network is /24 (8 bits), so for the network the equation is 2^2 = 4. You take two bits and do the power of 2, gives you 4 networks. Because you're taking two bits. You start from the left (at 128). 128 + 64 = 192 and that's the highest subnet you can go to. To find out the number of hosts, you have 6 bits, so do 2^6 = 64 -2 for network and broadcast, you get 62 hosts for /26

[gerreth]

correct =)

[christianh10]

i passed my CCNA by just watching this video, thanks.

ps i am in your backgarden.

[prepsicola]

pls. explain describe this backgarden? :-)

[sp00l]

@christianh10 lol got mine tomorrow and hope my result is the same haha xD

[paulwbrowning]

@christianh10 - I don't have a garden? Must be somebody elses house!

[imistahbooi]

THANKS! This really helps a lot! You rock!

[kurizzos]

Here is CIDR masking: (/26 bit mask example used in this vid): BINARY: 11111111.11111111.11111111.110­00000 (Notice 26 "1s": 2 bits borrowed from host side for network bits). Class C networks use 24 bits. 24 network bits + 2 borrowed host bits = 26 bit mask to hosts. CIDR just borrows bits from host side for network bits. IP version 4 standard. This is really simple. Just wait for IP version 6. Then admins are gonna start converting from hexadecimal instead of binary. :)

[jamescaptainfarrell]

One thing to remember too is this. Don't use anything other than titanium fitzgibbons pins to hold your subnet to your mask. The aluminum ones they use to use tend to break. Also be sure that no unique constraints are violated while jumping from primary to foreign keys.

[blade004]

where did the slash /26 come from? the address is 192.168.1.23, so if 4 octets are 32 bit, where does 26 bit come from and where and how does /26 come into all of it!??. I have spent the last 2 weeks wracking my brain over this and i think i am going mental!

[charles1967]

26 means that 26 bits of the 32 bit address are the network, so that leaves 6 bits for the host. This is so-called CIDR (Classless Inter-Domain Routing) notation, or "slash notation". Try doing a search on CIDR and you should come up with comments that explain this notation.

[kurizzos]

23 exists in 26 bit mask.

Using CIDR, the host address is:

11111111.11111111.11111111.110­10111

CIDR:

Masked Network: 11111111.11111111.11111111.11

Actual Host: 010111

Hope this helps.

[NewZealandBoi11]

you own i sub lol

[87655788]

the /26 represent subnetmask i know this just suck vide this dude need take some class about subnet

[rototiller78]

@87655788 dude, you need to take a class on how to type English.

[87655788]

@rototiller78 i need take a class on how to type English ? break down what did i miss Mr English professor

[87655788]

and so on

[hattsternz]

thanks, easiest way yet.

[fubar2511]

nice one paul

[Cosmopoet]

This is not really clear. If you are trying to learn this then explain more. Like where did 26 come from? How did you end up with 192.168.1.0 ?? I guess this assumes too much.

[blade004]

I just realised you posted this because this also has me confused as to how /26 came into all of it?

[prepsicola]

You need to go back to the basic subnetting videos if you dont get it... however considering this messages was a year ago you probably know a whole lot more than I do.

[diehard2006]

mediocre

[tenchi77]

That was easy.

[moersenice]

Wow, thanks man. This is great, very easy this way.

[dishcandanty]

THANKS!!! TAKING EXAM!!