Added: 5 years ago
From: mathproblems
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  • How do you go about DECREASING compound interest please?

  • b) compounded continuously

    A = Pe^(rt)

    = 12000 * e^(0.09*5)

    = 18819.75 to 2 decimal places

  • a) compounded quarterly:

    A = P(1 + r/n)^(nt) where:

    P = principal = 12000

    r = yearly rate = 0.09

    n = compoundings per year = 4

    t = term in years = 5

    A = P(1 + r/n)^(nt) = 12000*(1+0.09/4)^(4*5)

    = 12000*1.0225^20

    = 18726.11 to 2 decimal places

  • a) The balance after five years compounded quarterly is $33,600.

    (PxR=Interest; 12,000x.09=1080;

    compounded quarterly over five years is $21,600.

    P + I = Amount.

    12000 + 21,600 = 33,600.)

    b) is undefined or not sufficient information. By continuously do you mean compounded daily, monthly, etc.?

  • See http://www.youtube*com/watch?v­=LGcem9A0qbo for the definitions and formulae to use.

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