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  • Entertaining

  • the odds of a burn after successive use where x is the number of turns.

    1 - (7^x)/(10^x)

    after 4 uses the odds of a burn are 75.99%

  • A battle between the 2 guys i lost too due to hax...this shall be interesting

  • When he took out your Darmanitan, he should've used V-Create instead.

  • 0.7*0.7 = 0.49 -> 49% of not burning either one of two scalds

  • i thought it was an elo battle cause of the background haha

  • Finally, a battle where I know both people. XD

    Nice battle. 4 thumbs up.

  • its not a 60 percent chance to get a burn if you go for 2 scalds, its a 30 percent chance each time you use scald.

  • @Rematch727 I know, I just added up the percentage for both hits.

  • @Rematch727 Technically it is 60%. It's not 60% for the second scald, of course, but because it's 30 each team and this is a spread of two turns, it's 30% OR 30%, and with "or's", you add the percentage. So you have a 60% chance of getting the burn on one of the two scalds.

  • @CompulsiveOrigami Technically.... It would be 60% of 200%. Divide the two...

  • @Blazicune No, it would be 60% because you're adding 3/10 and 3/10 (or 30/100 and 30/100). You wouldn't add the denominator, therefore there is a 60% chance for scald to be used twice and get at least one burn.

  • @CompulsiveOrigami That logic states that it would be impossible to not get a burn in 4 scalds, which is obviously false.

  • Really enjoyed this, subbed man.

  • That ended quite awesomely :O

  • well finally someone battled im bored to death thanks solosoloblackdude :D

  • @MegaAwesomeVictini You're welcome!

  • i would like more battles from this guy :)

  • I apologize for this battle for being almost 13 minutes, oh hell. But if you guys enjoyed it then that's all that really matters.

  • Good battle :)

  • finally

    

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