Added: 2 years ago
From: lasseviren1
Views: 12,203
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  • i just wasted 9:23 mins of my life

  • Cant you just use, acceleration (g=9.81) =V^2/r to make the last question much simpler? or is that essentially what you did?

  • @KKEEAANNUU1994 The acceleration due to gravity decreases the further you are from Earth. g=9.81 only applies if you are close to the surface of the Earth.

  • I was just writing down that formula for speed then u said it changes .....

  • thankyou so much for this video

  • You can substitute g=G(M_E/R_E^2) into the result to clean it up a bit

  • Thanks! This really helped me with my homework this morning. You're much better than my physics teacher, I'm a Senior in HS.

  • thanks! you made it really clear!

  • Why does the Fnet of the satellite = GMsMe/(2Re)^2? What is the G and why is it being divided by (2Re)^2 and not just Ms??

  • @ACslater11 He's using the formula for the gravitational force between two masses. G is the gravitational constant, which I don't remember from off the top of my head. As the satellite revolves around the earth, it is the gravitational force between the satellite and the earth that keeps the satellite in orbit.

  • @angelsassin G = 9.8

  • love ya!

  • Very good ! Thanks for sharing! I voted "like".

  • vey nice. thanks man

  • FANTASTIC explanation!!! Thanx, thanx, thanx...!

  • what exactly is "this guy" at 7:53? the GM1M2? how is that the force?

  • @MonsieurJ0oker

    that'll be the equation for gravity,Fnet=Gm1me/r^2 (in this case r=2Re). guess that's just the one of the core thing you'll have to remember about satellite problems.

  • I finally understand it! Thanks so much for putting these up here.

  • You are such a good teacher - very eloquent.

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