Added: 2 years ago
From: RODALCO2007
Views: 11,100
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  • thanks

    but Resistors is heat up in 220V

    what i do

  • '

    nice show video about LEDs,,,

    but LEDs can be short time and easily burn out anytime if too long leave the light on all the time

  • how if 240 volt light the 3 - 5 white LED....how many Resistors and diodes need it ?can hv a drawing ?

  • @cktino For a 3 to 5 LED lamp it becomes less efficient with a resistor, so a capacitor would waste less energy, but it affects reliability too (spikes etc).

    But for 15 mA led current and 5 LED lamp ( white about 3 Volts drop per led )

    240 - ( 5 x 3 ) / 0.015 = R

    therefore R = 15000 ohms

    I x I x R makes 3.375 Watt resistor needed.

    Use two 7k5 or 8k2 Five Watt resistors in series.

  • @RODALCO2007 thx brother..with the project 4 schematic i can understand the conection led n resistors..... the therefore R = 15000 ohms, so the (I x I x R makes 3.375 Watt resistor ) part i dono the calculatioan I x I is what.... can explain the( I )...

    sorry i not a electronic engineer...

  • @cktino Power = (current)squared x resistance.

    You need to have a look in an electronics book.

    It is a standard formula.

    Led current max 20 mA = 0.02 Amps

    I used 15 mA in previous example.

    Then whatever the result is double the R value to have the resistor run under less stress.

  • @RODALCO2007 thx...now i know the formula to all find the right resitor , mA & watt..

    thx for ur explain.

  • @RODALCO2007 how to calculation the resitor watt need for the resitor ?

  • how do you make one for 110 electricity?

  • @Iseekoutthetruth For 110V and 19 leds (white) use 4 x 1000 ohm 1 Watt resistors in series before the bridge rectifier. (Instead of the 5 x 2k2 resistros used for 240V)

  • you don't need schematics for this.

  • Can you send me the schematic of this project? is very interesting your Idea.....

  • Watch Led project 4 which gives you a detailed schematic, with parts.

  • Hi, nice project...But you should use a 400V capacitor instead of your power resistor to avoid heat dissipation and to save power...470nF / 400V should be ok...(look for capacitor reactance...) ask me if you want some explanation about reactance. (in AC, a capacitor can be used to make a resistor that doesn't dissipate power...)

  • Thanks for your offer, I know the formula for reactance of a capacitor.

    My issue is reliability. In New Zealand we have a lot of overhead lines and occasional surges during storms. Hence the resistive option is choosen.

    A cap. can pass a spike through with no problem regardless if a 1 k.ohm series resistor is fitted and destroy the leds.

  • That's really a great idea! It sure saves a lot of money using these lights instead of the normal ones or the compact flourescent ones!

  • Just use the old base when the CFL fails.

    When the leds run below 20 mA they have an almost unlimited life.

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