Runge Kutta 4th Order Method: Example Part 1 of 2

[arqi25]

Hi, do you always use i=0 first? what if your asked to estimate the y(0.4)..would you use i=0.4 after using the i=0 ? please if you could answer this as i have an exam today. Thanks

[numericalmethodsguy]

@arqi25 The variable i is the subscript, not the value of the independent variable. So if the ODE is of the form dy/dx=f(x,y), y(0)=y0, then x_sub_i+1=x_sub_i+h, x_sub_0=0; y_sub_0=y0. So if you want to estimate y(0.4), then what the value of i us at x=0.4 depends on the step size h. If h=0.2, it would be y_sub_2 that you will be seeking.

[jindenMUTD]

Macho pose at 8:16 by the way your brilliant

[ggdltttt]

Wow Mr. Numericalmethodsguy! You are the best! I would have failed my final exam without u! Thank you from Sydney Australia.

[greynight234]

The formula which You used for k1, k2 k 3 and k4 is change what is in wikipedia and ...i have seen this formula as k1=h f(xn,yn)

h is multiplying in all k values but in yours it is not.. Kindly tell me ASAP tomorrow is my paper.

[numericalmethodsguy]

@greynight234 h is multiplied separately. For more info go to numericalmethods(dot)eng(dot)u­sf(dot)edu and click on Keyword. Go to Ruge-Kutta 4th order method and read the textbook chapter!

[dvavorf]

@greynight234  He multiply it in the end instead. Here :y(n+1)= y(n) +1/6(k1+2k2+2k3+k4) since h is a constand which is in all k1,k2,k3,k4 it can be multiplied here instead.

[dvavorf]

Legg inn respons på denne videoen See 1:39

[GigiHickey]

genius..!!



[mielo101]

thank you! now i can solve ODE easily...

[warrior0345]

great work

[TimpBizkit]

I remember runga kutta. I may have had to write this method into a maths program to solve differential equations of planetary orbits. I think there was already an option to use the method though in the maths program Maple

[MechEngineering45]

You're videos are of great help to me. I got an A in numerical analysis I and will more than likely get an A in numerical analysis 2 as well.

[garyHTC]

Excelente, soy estudiante de la Escuela Superior politecnica, buen video.

[VannevarBush]

Thank you very much. Actually I try to solve an equation of the form

y(t)'' = - H(t)*y'(t) - c1 * y^4(t)*ln(y(t)²) - T(t) *y(t)

whereas c1 and c2 are constants, y(t) is the solution to be and H(t), T(t) are functions of the independent variable. Is this familiar to you by chance?

[AKSstudent]

This video helps a lot. Thank you very much for posting!

[kralle333]

Going to a test today

[homedogdigity]

k3= -.3181*

[louislryan]

Great links. I've been covering numerical methods this semester and this has been my number one source of information. If you still have the labs, Adam Bashforth's method could be simplified!

Great job USF

[presidentevil]

can't you use the linear ODE equation for this?

Can you solve any nonlinear ODE with this?

[numericalmethodsguy]

You can solve any linear or nonlinear ODE of the form dy/dx=f(x,y) with Runge-Kutta methods.

[footbagverde]

thanks so much! very good video you explain much better than my professor!!

[bardiche1989]

You Sir are PRO !

[LogInForPaper]

So my lecturer goes to us today, "So you should all be aware of the Ronge-Kutta and Euler methods". The whole class (first years) just looked at eachother with baffled faces. Thank you for uploading this, you have saved my Mathematical Physics GPA!!

[numericalmethodsguy]

Please tell all your classmates about the website.

[LogInForPaper]

@numericalmethodsguy

Yeah I will, already posted this on facebook.

[expert425]

really helpful video. thanks

[7i7Abil]

you are very helpful and i appreciate the time you put into this

[pikachu7]

you are my hero

[lovepandas411]

OMG!!! idk what this is but Runge is my last name!!! and he said in right!!

[adhemar4444]

Really helpful thanks so much

[numericalmethodsguy]

The correction for k3 has been posted