Added: 3 years ago
From: TTUchem1010
Views: 40,226
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  • Made no sense at all. I can ready the same thing in my old school book, I'm pretty sure you can get a pdf file online for 5 dollars, and it will teach you, while showing pictures to tell, what the heck is going on. I need to see an actual experiment to understand the theory, I don't need wild numbers, nor fancy big words. 765 joules, what does that mean in the real world, how to I achieve that number to get a reaction, do I call Obama, is that how?

  • Very helpful, thanks for taking the time to make this!

  • Your explaination is really good.Thanx a lot!

  • Thanks a ton! I'm being tested on this tmrw

  • bond fission

    homolytic fisson

    enthapy change of atomisation

    thanks

  • thankyou! :D <3

  • nice, i learned a lot from this video. I LIKE UR ACCENT.

  • 100000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000000000000000000­000000000000000...............­LIKES

    

  • I've earned more in the past 10 minutes than I have the past two weeks in lecture. Thank you.

  • This is a GREAT VIDEO!!!!!!

  • i'm going to pass my apchem test tomorrow thanks to you. so big thanks! <3

  • YOU ARE GENIUS! 

  • One problem. Why is it written as sodium gas? The boiling point of sodium is 1156 Kelvin.

  • Very clearly explained, much better than my teacher. Thanks a bunch.

  • 5:43 looks like an asian with big cheeks

  • @luvs2spooge00 lol everyone else comments about the chemistry involved, you commented on the drawing :D

  • this is great, thx a lot!

  • nice explanation. you sound young.

  • we need more teachers like you

  • this was of great help!u explain very well.

  • OMG!!!... In the first 1min 30 sec of your vid, you managed to explain the concept I've been searching for in my college books & useless mandated online vids for the last 6 hours. One of my online H.W. questions asked "Of the 2 compounds, which will result in higher lattice exothermic energy" or something like that (10 sets of compounds total)...But the material never taught how to predict the amount of energy released. Book only explained the basic idea of lattice energy. ..Thank you so much.

  • For some reason, my teacher gets paid for this and you don't. I'm not sure why this is, but it should be changed.

  • holly shit kid ...how old are you nice!

  • very well explained, thanks

  • Wait, I'm in 10th grade, and I'm trying to study lattice energy for chem, but this says "for majors." Should I not be watching this video, wait is this a totally different subject?

  • @WhatLocoCoco This is college chemistry

  • thanks so much! you sound like taylor swift

  • iiii fucking hate this stuff...

  • Uh, I'm trying to focus on the chemistry concepts presented here (And VERY well presented I should add!) but , TTUchem1010's voice is just sexy and makes me not concentrate :)

  • Helped me soo much on my homework. THANK YOU.

  • Homolytic cleavage, baby

  • this was really helpful! Thanks so much :)

  • omg i frikin luv u, u helped me sooo much on my chem hw!

  • Omg thank you SO much, I finally get it! :D

  • I thought lattice energy is always positive because it requires energy to separate solid to gaseous ions and not the other way around as you stated. The reverse is called energy of crystallization, no?

  • Lattice energy is always negative, and bond energy is always positive, because lattice energy relates to the forming of a lattice. Bond Enthalpy relates to breaking of a bond-which is why it's positive (exothermic).

  • I guess it depends on the textbook. Mine defines LE as "energy REQUIRED to separate ionic solid into gaseous ions" and so it is always positive since it takes energy to break something (endothermic). You're half right about BE though...it is the energy required to break a covalent bond, but since it's referring to breaking of a bond, it's endothermic (requires energy) and not exo. I think that's probably what you meant though.

  • @jetlex1 Lattice energy is always exothermic thus resulting in a negative number always

  • You are amazing. Thank you very much.

  • I love how you explain everything in every step. thanks!

  • repeate/delete.

  • Wow! really helps me understand the electrolysis of water and Potassium Hydroxide into hydrogen and oxygen atoms. We have to induce approximately 200 Watts to make 1 Liter of gas. Also makes heat. And we guess that the gas is somewhat ionized or picks up electrons from the Potassium. Need to do a lot more studying. Thanks

  • Thanks! Very clearly explained...you should be charging for this.

  • that a kid.. this is what we need more nerds like you....

  • u need to get paid.

  • Excellent voice. I hope my Brasilian students can understand you.

  • This helped me so much. I subscribed to you.

  • AWESOME! Thank-you

  • I teach high school chemistry. I found this video very helpful to my students. Your explanations is clear on all four terms. 3 of them are useful to my course. Well done.

  • You are awesome

  • Great job!!! Could not have been explained any better.

  • OMG, this video is awesome!!! I learned sooo much. Thank u! :)

  • helemaal goud

  • this was such a big help! thank you soo much

    keep up the good work!

  • heyy...i'm in d 11th grade....thnx a tonne for this video..i hv this test tomorrow n ur video has lyk helpd me alot!! thnx again!!!u r a really gud teacher...

  • yay I can now pass my year 11 half yearly exam for chemistry!!

  • I really like your way of working. I'm thinking about setting up a similair concept in Dutch. Greets from Holland ^_^

  • Never heard gaseous pronounced that way, but an excellent video none the less.

  • Thanks. I'm from the South, and I prefer ˈga-sē-əs  to ˈga-shəs. :) Either way, it's a gas!

  • Thank you very much for posting this video. It helped me so much. Please Keep up the good work =0) .

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