Added: 2 years ago
From: davidodud
Views: 7,498
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  • I only use two parity cases and it works every time

  • You speak quite fast. Could you write the algorithm here, please?

  • bhenchod!!!

    

  • you only need to know two algs if you know one look oll and pll

  • pretty annoying! (not your problem) but the way i learned this cube is actually i looked for the first 2 steps > all center + pairing. After that i've learned my self to solve it all the way to this. but i have no freakin idea what u mean with parity 4 and 5

  • @VisualDesignFX yeah what i mean by parity 4 and 5, is cause i made this video as a direct response to another video that i posted in the descripition, and the person in that video assings a number to each parity case. And i made this video a long time ago so even i dont remember which case is which :P

  • Dude i don't undertanded what you said

  • just do the algorithm for parity 3 or 5, they aare the same, it doesnt solve the cube for u but it lets u solve it like a 3x3 in under 3 mroe steps its a way shorter algorithm, u can do that for all parity cases except when the edges flip on one side. which i like to call buck teeth.

  • how do you do parity case number 4

  • @NITSOGOP

    an explain of how to fix each parity case can be found in the link posted in the description

  • what is parity case #4

  • @NITSOGOP

    I make reference to dan brown's video on how to solve a 4x4, so parity case #4 is i believe the one where two corners are switched, but im not 100% sure, either way you can check his video to see which case is #4, and he has all the algorithms for it, but as i explain in this video i found away to get around it.

  • I just take the pieces out and flip them in the right direction when I run into a parity.

  • @Hollandvancewright since making this video i kind of stopped a bit with the 4x4. and so i now do the same :P

  • Nice observations. For fun, here are some shorter algorithms for the two corner swap cases that I made myself. Unlike algorithms you have probably seen before for 2-corner swaps (PLL Parity+PLL), these are unified algorithms.

    Adjacent:

    z r2 U2 R' U2 R' U2 R x U2 Rw2 U2 B2 L U2 L' U2 Rw2 U2 z' y'

    Diagonal:

    Rw2 F2 U2 y Rw2 U' Rw2 U D Lw2' U' Lw2' y' r2 U2 F2 Rw2 U

    I have a video showing other unified algorithms for these cases as well, but these are the shortest that I have come up with.

  • Comment removed

  • pls i have a sound problem and i can't hear a thing.Can you give me the algorythm ?i really need this

  • Great short cut. Thanks.

  • When you hit your first parity or second parity error, you can do the following to remove the parity error without learning any new parity cases.

    r2, U2, r2, Uu2, r2, u2.  Now this steps you back two steps. This one is one you should already know for flipping opposing mids. However I'm using it to remove your shown parity errors and solve with existing cases.

  • From what I know, you really should only come across 2 parity cases. One when a dedge piece is flipped and one when the 2 corners are in the wrong places. Then you only need to know 2 algorithms. And when the 2 corners are in the wrong places, just do 2r, 2U, 2r, 2U*, 2r, 2u. You'll unsolve the cube to the point of edge lining, but it somehow puts the corners in the right places. So then you will only have to learn one beast.

  • i never get it

  • dude, that's not a parity. you just hold it so that you have a solved corner in the top left and bottom right and you do Ri F R Bi Ri Fi R B easy as hell!

  • What is more, you can do some plls in order to get opposite edges switching parity, which is the shortest one :D for examle, here you can do N perm and then opp. edges switching alg=)

  • u look like a guy from my school...

    r u in campion school in pallini greece?

  • haha no i'm from canada :P

  • lol ok

  • I'm a real lazy fucker so this has helped a lot

    thanks!

  • no problem!

    and i know, i don't understand how dan solves it so that he needs the other parity algs, i only ever need those 2

  • @davidodud You can solve it in an easier way, more advanced way, so that you won't come across all these long, horrible, stinky, beast-algorithems... EVER. Look up a 3x3x3 solution at the page of RobH. When you solve the last part of the 4x4 like that, you only need one algorithm: r2, U2, r2, U2*, r2, u2!

  • @Arriopolis yeah i have since moved on to a much better war of solving all cubes in general :P i switched over to two look pll and oll, which reduces parity problems. I might make a video explaining all of that at some point.

  • You can use the parody case 3 algorithm (2r 2U 2r 2U* 2r 2u) for parody cases 1, 4, and 5, then re-solve the top layer. This will not work with parody case 2 though. This means you only have to memorize parody case 2 and 3! simples

  • Cool!!! Thanks!!!

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