鄭惟駿@我猜 魔術方塊表演 Vic's Rubik's Cube show on CTV "Guess"

[chukinghin36]

第二次應該是28.80左右,因為解完後他是放了魔術方塊才慢慢­地弄停計時器

[gundum5445]

the BLD 29 sec , with Fridrich system oO so fake

[weijiunn]

TV shows are just shows; what they want are just effect in the screens that astonish their audience, and they never care whether it's real or fake. I tried to communicate with them before the very first time I was on TV, but I realized that it's a waste of time talking to them about this. Since I was just one of the performers invited to the show, as well as to all the other shows, I compromised and gave them what they wanted.

There are a lot of shows with real BLD solves; you can take a look!

[dvtpgm]

In case anyone doesn't understand chinese, Vic Cheng has already memorized that BLD cube beforehand. I really wonder if he has already solved that same scramble many times and also memorized the solution.

They should have allowed the host to scramble the cube and solve it blindfolded.

[weijiunn]

Thanks for your comment.

it was the producer who wanted me to do a pre-memorized BLD solve, and that's why the host would never had scramble the cube because he knew it.

I have solved the same scramble for many times indeed and I did use CFOP to solve the cube.

[dvtpgm]

Yup definitely it's the producer who wanted you to perform a pre-memorized BLD solve. No worries I'm not doubting your cubing skills. I just thought it will be more impressive if they allow you to demonstrate the actual BLD solving by allowing the host to scramble the cube on the spot.

But one thing though. Pardon my ignorance, but if you were to perform a real BLD solve, is it really possible to do it using Fridrich? I'm asking because it seems most are either using Pochmann or 3 cycle.

[dragggggg]

He is obviously using Fridrich to complete the BLD solve.

[lovejesus160]

He can solve it using the BLD method, but because the TV station has a time limit, they wanted him to use the fridrich method.

[Bwilliam417]

WOW Yea Fun!

[morpheus3000]

thats what i call a genius

[mitchskater]

i would calla genius comeone that can solve a cube intuitively not without knowing the algorithyms