I don't quite follow why the morphism g : T' -> T composed with f : T -> T', g o f, must equal the identity morphism of T. Is this implied by the uniqueness of the morphisms to the terminal object T?
Assuming there was a morphism h : T -> T that was not the identity morphism of T then there is not a unique morphism from T to T. This contradicts the fact that T is a terminal object therefor any morphism from T -> T must be the identity. Something like that?
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gggeeesssuuu 3 years ago
Yes - there is a unique morphism T->T. g o f and the identity are both morphisms T->T so they must be equal.
TheCatsters 3 years ago
I don't quite follow why the morphism g : T' -> T composed with f : T -> T', g o f, must equal the identity morphism of T. Is this implied by the uniqueness of the morphisms to the terminal object T?
Assuming there was a morphism h : T -> T that was not the identity morphism of T then there is not a unique morphism from T to T. This contradicts the fact that T is a terminal object therefor any morphism from T -> T must be the identity. Something like that?
GoAwayStupidAI 3 years ago