Boolean algebra #23: DeMorgan's theorem - introduction

[lsucaleb]

COME TO LSU AND TEACH.

[rabakjack]

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[linkinms]

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[X02switchblade]

if we have NOT(A.B)= NOT (A) +NOT (B) from demorgan

can we do NOT(NOT(A.B))=NOT(NOT (A) +NOT (B)) ?

Like in algebra when you multiply both parts with -1?

[keleshevCOM]

@X02switchblade Sure we can! However to simplify not( not(A) + not(B) ) you need DeMorgan's theorem anyway.

[lilnizzel]

amazing explanation!! ive watched every single video and i understand everything

[JinGabrielleFoliente]

@lilnizzel yeah :) me too :D