Added: 4 years ago
From: MIT
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  • also ich bin blond

  • Equations make me dizzy. Hahahah

  • Which lesson should I watch to learn how to "complexfy" as the professor does at 17:58. Thank you very much.

  • @RinaldiMeteoric It's the 6th. And by the way, you're the laziest folk i've ever seen !

  • can someone tell me if that is first or second semster or whatever..?

  • woot he's wearing my favorite jacket again!!!

  • the only reason i clicked on like on this video is when he mention it wants to be T but i make it X . lol funny. he is funny teacher.

  • @farzadaf No, +sin is correct. If you expand out the terms (1+i)(cos x + i*sin x), you get (cos x - sin x) + i*(cos x + sin x). The particular solution takes only the imaginary part, the term (cos x + sin x), discarding the real part (cos x - sin x).

    This is because the original ODE (y) became the imaginary part of the "complexified" ODE (y-tilde).

  • savior during finals

  • 23:40 should be -sin i think

  • @gorgolyt

    yes I got -sin(x) as well

  • @gorgolyt No, he has it right. We want the imaginary part, aka the part with factor i.

    The imaginary part of (1+i)(cos(x) + i sin(x)) is cos(x) + sin(x).

    If we were looking for the real part, then indeed it would be cos(x) - sin(x).

  • he has a great sense of humor.

    A huge thank you from Brazil.

  • Exelente!. Gracias, desde Perú.

  • Buenísimo. Gracias, también desde Argentina

  • Why is it that we can assume 'a' to be a root of p(D) in general?

  • @GirlyVoice it isn't. p(a) is normally nonzero, so a isn't a root. he covers the special case of when it is a root in the second half of the video.

  • Comment removed

  • )) Preps are all around vwry much alike. I had almost the same one of Physics ))

  • gracias de verdad uy este tipo es lo maximo jeje explica muy bien!!!

  • Muy lindo ! Gracias ,desde argentina.

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