A bit confused about the first part where he says that "P Union L" is not a subspace. Does he mean that the Union is not a subspace of P and not a subspace of L or that the Union is not a subspace of R^3? Because in my brain everything in the chalkboard is a subspace of R^3 :S
@SynthMelody The union is not a subspace. The union is bigger than P or L so it definitely can't be a subspace of either of them. and by adding a vector from P with a vector from U you can get to a point that is neither in P nor in U or in other words by adding two points from P∪L you can get to points outside of P∪L (somewhere in R³). But to form a subspace you have to be able to add any vectors from that subspace and the result has to be in that subspace.
@SynthMelody Maybe a simpler example helps. We take the X axis as one subspace and the Y axis as another subspace. So the union of those two spaces is all vectors on either axis, but nowhere else. For example (1 0 0) is on the X axis and (0 1 0) is on the Y axis. But the sum of the (1 1 0) is not on either of those lines. It's outside of it, so the union can't be a subspace, as otherwise you'd stay inside it when you add two vectors.
I actually just took a formal linear algebra class at my university and it's crazy how the lectures are so similar. So I feel at least I'm getting a good education from my uni for a good price.
Oe knows a truly good mathematician just by looking at how he carelessly overwrites stuff licentiously because it doesn't really matter. In his own words: "this is not Rembrandt, we're in linear algebra.."
i like my math professor and he is really smart, but he doesn't explain like this. he expects us to get it just by him writing down theorems. I like Strang's intuitive approach to understanding vector spaces. I wish i went to MIT
Terrific, terrific lecture, esp his way of using linear combination / "column picture" to solve equations. I have never heard of it, but it is so much easier! Thank you Prof. Strang/MIT for posting these lectures!
Terrific, terrific lecture, esp his way of using linear combination / "column picture" to solve equations. I have never heard of it, but it is so much easier!
When he was talking about line L, i thought L was a subspace of P (also his diagram of L kind of looks like L is inside P) . If it was, than P U L=P & P itself is a subspace of P.So P U L is a subspace of P.
But if he was talking about L that passes through orgin but doesn't lies in plane P (so L penetrates P), than ofcourse P U L will not be subspace of P.
@Santakingkong Sorry, now i think i got what u were saying. i think u meant to write "I think P U L is a subspace only IF ( not 'in') line L lies in the plane." That makes completely sense. Thanks.
@DaWanderer he says the origin must be contained in any subspace because multiplying any vector by 0 will give you the origin.. and that is the scalar multiplication rule.
@khatmandu89 If it is a subspace then the scalar multiplication will hold therefore zero vector is contained.....If it is not a subspace then the scalar multiplication will NOT hold so you could not force the zero vector to be contained.
a vector space inside a vector space....INCEPTION o.O
michaela234 1 day ago
Great professor... His students are very lucky to have him... My professors (during engineering) sucked big time...
jojoejoe 1 week ago
Good, I like that you share this video, I wish success always Column Space and Nullspace.
AntoMelta 2 weeks ago
Comment removed
AntoMelta 2 weeks ago
Nice Video Column Space and Nullspace That You Share , So Very Nice Thanks You
willamricard 2 weeks ago
I Really Like The Video Column Space and Nullspace From Your
imegatrone 2 weeks ago
Your Video Column Space and Nullspace Is Very Useful Sharing
bundawartini 2 weeks ago
he emphasizes everything so good so that even the most idiots can understand... Great man !!
LnX53 3 weeks ago
this man deserves the money he get
LnX53 3 weeks ago
I'm studying linear algebra in my own to take the challenge exam so Thanks for the lectures.
very useful and understandable
hsnbk 3 weeks ago
This is really great and brilliant lecturer i never seen before. I like the methodology he is using and he knows how to engage his students.
I can see now how linear algebra is applied.
Thanks Gilbert Strang and MIT.
MrFili3333 1 month ago
mmh guckt mich an bin ein elch
SharylEloisrb704 1 month ago
Finally someone who can explain image/range/column space clearly!!!
aznpiccplayer123 1 month ago
He wears the same shirt and same pants every lecture.
awsomenesscaleb 3 months ago 2
@awsomenesscaleb just as steve jobs rite? It doesnt mean a thing.
mclaarson 2 months ago
Dont dislike these videos for heavens sake... what the heck is wrong with you ppl???
allanjoshua84 3 months ago in playlist MIT 18.06 Linear Algebra, Spring 2005
thanks professor strang
akhil089 3 months ago in playlist b.linear algebra
A bit confused about the first part where he says that "P Union L" is not a subspace. Does he mean that the Union is not a subspace of P and not a subspace of L or that the Union is not a subspace of R^3? Because in my brain everything in the chalkboard is a subspace of R^3 :S
SynthMelody 4 months ago
@SynthMelody The union is not a subspace. The union is bigger than P or L so it definitely can't be a subspace of either of them. and by adding a vector from P with a vector from U you can get to a point that is neither in P nor in U or in other words by adding two points from P∪L you can get to points outside of P∪L (somewhere in R³). But to form a subspace you have to be able to add any vectors from that subspace and the result has to be in that subspace.
he2he 3 months ago in playlist MIT 18.06 Linear Algebra, Spring 2005
@SynthMelody Maybe a simpler example helps. We take the X axis as one subspace and the Y axis as another subspace. So the union of those two spaces is all vectors on either axis, but nowhere else. For example (1 0 0) is on the X axis and (0 1 0) is on the Y axis. But the sum of the (1 1 0) is not on either of those lines. It's outside of it, so the union can't be a subspace, as otherwise you'd stay inside it when you add two vectors.
he2he 3 months ago in playlist MIT 18.06 Linear Algebra, Spring 2005
@he2he Thank you man! That was a very good explanation :)
pithikoulis 3 months ago
He's a famous mathematician. Feeling privileged after watching his lectures.
tensorbundle 5 months ago
I actually just took a formal linear algebra class at my university and it's crazy how the lectures are so similar. So I feel at least I'm getting a good education from my uni for a good price.
ClaytonOT 5 months ago
...what b turns out to b - lol
hypnoticpoisons 6 months ago 4
i should jus tranfer to MIT...like right now...
jazzyb1030 7 months ago in playlist MIT 18.06 Linear Algebra, Spring 2005
@jazzyb1030 that would be great, the problem is how..:D
hypnoticpoisons 6 months ago
Oe knows a truly good mathematician just by looking at how he carelessly overwrites stuff licentiously because it doesn't really matter. In his own words: "this is not Rembrandt, we're in linear algebra.."
pedroissler 8 months ago
gosh. i want him to be my new lecturer.
i need an explanation using blackboard not projector
ChoEugene 8 months ago
intuitive
WestWindBlowing 8 months ago
i like my math professor and he is really smart, but he doesn't explain like this. he expects us to get it just by him writing down theorems. I like Strang's intuitive approach to understanding vector spaces. I wish i went to MIT
SpoiledLogic 11 months ago 2
I like how he calls vectors or columns "this guy" and "that guy"
Heretic3030 11 months ago 11
17:10 "you can see from the way I am speaking what the answer is going to be..."
--wish my profs spoke like him...
cool4skull 1 year ago 2
what a don! i wish my lecturer was this guy, he makes it so simple
UncleBards2 1 year ago
Terrific, terrific lecture, esp his way of using linear combination / "column picture" to solve equations. I have never heard of it, but it is so much easier! Thank you Prof. Strang/MIT for posting these lectures!
sdcororaton 1 year ago
Terrific, terrific lecture, esp his way of using linear combination / "column picture" to solve equations. I have never heard of it, but it is so much easier!
sdcororaton 1 year ago
i finally learn something
KaLNFoRc3R 1 year ago
those MIT blackboards are like Hogwarts...secret boards out of nowhere
MADLmaan 1 year ago
HELP! I think Strang might have got WRONG around 05:40. I think P U L is a SUBSPACE of P as P & L itself is a subspace of P.
Think like this: let p & l be a vector from P & L respectively. than u=p+l belongs to
P U L and u lies within P as p is within P and l is also within P.
Also c*p & c*l belongs to P & L respectively where c is scalar as P&L are subspace. so c*u=(c*p + c*l) belongs to P U L.
Finally, zero vector lies in both P & L. so Zero vectors belongs to P U L.
So P U L is subspace.
subash3 1 year ago
@subash3 I think P U L is a subspace only in line L lies in the plane.
Santakingkong 1 year ago 2
@Santakingkong i don't get what ur saying but Thnx.
Anyway, i think i may have found the solution.
When he was talking about line L, i thought L was a subspace of P (also his diagram of L kind of looks like L is inside P) . If it was, than P U L=P & P itself is a subspace of P.So P U L is a subspace of P.
But if he was talking about L that passes through orgin but doesn't lies in plane P (so L penetrates P), than ofcourse P U L will not be subspace of P.
So my interpretation of L was wrong.lol
subash3 1 year ago
This has been flagged as spam show
@subash3 I said that P U L is a subspace only if the line L is in the plane
Santakingkong 1 year ago
Comment removed
adidasguy87 1 year ago
This has been flagged as spam show
@Santakingkong Sorry, now i think i got what u were saying. i think u meant to write "I think P U L is a subspace only IF ( not 'in') line L lies in the plane." That makes completely sense. Thanks.
subash3 1 year ago
This has been flagged as spam show
HELP! I think Strang might have got WRONG around 05:40. I think P U L is a SUBSPACE of P as P & L itself is a subspace of P.
Think like this: let p & l be a vector from P & L respectively. than u=p+l belongs to
P U L and u lies within P as p is within P and l is also within P.
Also c*p & c*l belongs to P & L respectively where c is scalar as P&L are subspace. so c*u=(c*p + c*l) belongs to P U L.
Finally, zero vector lies in both P & L. so Zero vectors belongs to P U L.
So P U L is subspace.
subash3 1 year ago
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subash3 1 year ago
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subash3 1 year ago
awful course!
reid300 1 year ago
@reid300 ya bur he teaches it well
Reggae4Triceratops 1 year ago
He's much better than my lecturer at the LSE.
Pranikki1 1 year ago
this guy is awesome the proffs at the university of toronto dont know shit abt math...
pcbjunkie 1 year ago
i would give this guy a standing ovation, these mit punks dont know how bad other professors can be
SHEMANROBOCOP 1 year ago 7
is this who kevin spacy was supposed to be in 21? haha
CBeerzy 1 year ago
He explained in 1 lecture what took my professor 3.... very good teacher
awesomeous20 1 year ago
lots of help!
Cherubinpri 1 year ago
great video!
gsmsteve 1 year ago
@Aerosion No one has any questions since Dr. Strang is that awesome
roombaba 1 year ago 3
Comment removed
geossj5 1 year ago
man. I finally understand it.
maxlyger 1 year ago
Shizzle! He forgot his neck tie!
KarlCrack 1 year ago 4
Finally the subtitles are on sync!!
This is great!!
xploi 1 year ago
Thank You very much for such marvellous courses!
Kyrgyzstudent 1 year ago
Why is it necessary that the subspace P or L of R^3 must go through the origin [0,0,0]???
What if this plane P doesn't go through the origin? Isn't it still a subspace???
DaWanderer 1 year ago
Any subspace must contain vector (0,0,0), otherwise, if you do w*0 the answer would not belong to the subspace.
If the plane doesn't go through the origin, it's not a subspace.
falcord 1 year ago
@DaWanderer he says the origin must be contained in any subspace because multiplying any vector by 0 will give you the origin.. and that is the scalar multiplication rule.
khatmandu89 1 year ago
@khatmandu89 If it is a subspace then the scalar multiplication will hold therefore zero vector is contained.....If it is not a subspace then the scalar multiplication will NOT hold so you could not force the zero vector to be contained.
mathgoddess64 1 year ago
22:49 - what b, turns out to b .. :-) Great lecture, occasional pokes of humor and self irony is great!
glentellefsen 2 years ago
AMAZING Lecturer! Easy steps to follow and talks slow enough to understand. Thank you MIT!
aleant 2 years ago 6
much better than my prof ! I like him
simonjiang12355 2 years ago 2
not one person has a question in any of these? wtf
Aerosion 2 years ago 6
I know--they're sitting there like bumps--I gave him a standing O at the end of Lecture 4. Bravo !!!
8cccpeevostokzempf 2 years ago
Oooops--I meant Lecture 5--get confused by all the Big Numbers s-times. Lecture 5Standing O--Lecture 4 Bad Sound.
8cccpeevostokzempf 2 years ago
maybe because of its simplicity... it's obvious!
osiumjrtosfyo5syerg 2 years ago
Ax =b, never understood this thing better than this before..
chandigarh47 2 years ago 3
39:36. haha... this guy is a genius
harish400 2 years ago 8
he is a great mathematician
cheers
positrongamma 2 years ago 30
Excellent lecture! Thanks!
MrSystemVI 2 years ago 4
Dr Strang that's a great lecture right here!
raymyster2 2 years ago 6
GILBERT STRANG FTW!
turcorox911 2 years ago 6
awesome...really helpful
nitheshp1985 2 years ago 19
This has been flagged as spam show
i hate vectors ^^
KaLNFoRc3R 2 years ago
I love the rating for this comment.
jcarol555 2 years ago
I think many of the videos has been updated recently to a better quality though. So the views of the previous video may not show anymore.
Laiquelleion 2 years ago
Lol i like how the number of views decreases with the lecture number.
Mathematics215 2 years ago 6
lol, that is so true
tondominguez 2 years ago 3
Its because people are in the middle of viewing the videos
Treesrule14 2 years ago
yeah... why do u think that happen?
lhaussmann 2 years ago
The audio is messed up on this one.
aaronarmstrongskomra 2 years ago 4
no kidding
126altf4 2 years ago 4