can you share the specs of your tubes and how they are wired up? they seem to produce alot of hho with little amp draw. what is the liters per. min. output of this set up?
As to juggernautxtr comment 'water is going t boil faster', under vacuum. Correct. However, when water boils under a low vacuum pressure. The steam isn't Hot per se, it could even be room temp or at a physcially lower temp if an ultra high vacuum were used.The main point is to allow the vacuum process aid in the electrolysis production. And why not, engine vacuum is a ready source not being used with bubbler hho cell configurations.
Dear sir, I love the vids, however our tests show that a completey submerged cell will not show a change in amps. Yes you get more HHo, but the amp change your seeing is from a lack of water in your tubes from expanded gas. Sink it real deep and you won't see that amp effect. Keep the tests coming.
Love the work, nice to see an experiment that confirms vacuum as an important factor on the production of gas. I'm sure you already know, but what scares me is seeing you so close to pressure bomb that could go off, and if your really unlucky then ignite..
the problem i see with this is your going to have a runaway event a lot faster cause the water will boil faster, though nothing wrong with experimentation, but i see a sooner runaway event occuring,because your boiling point is lower. i would like to see the results after running for 30-45 minutes. a typical drive to work.
problem is you don't want current in the circiut, currant flow will increase as well as heat but the more heat you have the more wasted energy you have. cause you really can't use the heat. the cooler the tank stays the more efficient it will be. you want the electricity to do the work, not the currant flow, thats why meyers put a step up transformer and chokes to kill the currant flow.his ran .5 amps and less
faraday's law is what you wanna apply to electrolosis.
The production rate of a cell using distilled water is very low (at least my cell) so I you would try it on yours using vacuum and distilled water ... see what happens.
Yeah, I think it's because the amount of vacuum in the cell was being reduced by the gas created, thus reducing the rate of water vapor formed at the cylinder surfaces (from boiling). Less water vapor bubbles means less resistance to current flow and increasing amperage.
problem is that if you put a vacuum on water it's going to boil faster. just like the cars cooling system, pressure is applied to keep the water from boiling. less pressure means lower boiling point, more pressure higher boiling point. and i think that might have been what part of meyers device was doing, he was preventing heat with pressure.heat means more resistance.
In the case of a liquid electrolyte solution, more heat would mean higher kinetic energy (motility) of the ions in solution and thus LESS resistance to current. This is why when hydroxy boosters heat up, the current also increases - runaway current phenomenon.
Look up "phase diagram of water" and "partial pressure of vapor" and "ideal gas law" to better understand why water boils at lower temperature at lower pressure.
It may be that by applying a vacuum you are helping release the gas bubbles from the cylinder walls. This would free up surface area for new gas formation and thus reduce the load or amperage required to produce the gas.
When you get your problem with the vacuum pump oil (contamination of HHO?) solved you could determine the gas production with the vacuum vs. with no vacuum using a good HHO meter. Then you could also fill and tie off a large balloon with vaccuum pump and weigh the balloon in water and in air. From this you could determine the density of gas inside. If you do this also without the vacuum pump, you'll be able to combine this with the volume measurements and determine which produces more H2.
Intuitively I can't really see why the rate of electrolysis should be increased when a vacuum is applied. Perhaps the fact that your amps is decreasing when under vaccuum is due to the fact that the water vapor bubbles forming on the nucleation sites presented by the tube's surfaces is actually inhibiting current flow. This would tend to imply that rate of electrolysis actually decreases since it is well known to be a function of amperage. Thanks for sharing this.
what are you useing for electrolite ?? at what volts / amps. im using 12 volts in 1 Litre of wtr, 6 amps. but volts drop to 8 & 8.5 after a few runs...
I have an idea. If we know the exact volume of the container and hose under full vacuum and the amount of time it takes to change pressure from say -30 to -20 then we can calculate the volume of gas. Right? Then we can calculate the watt/hour efficiency. Then we can compare to production at normal atmosphere pressure.
when you say the unit became more active...as you went on, well i have noticed this too, i tended to think the metal was aligning structurally some how, and after a few runs it did run better..
I was thinking the tubes were getting conditioned and the water was getting charged. But your idea does make sense. Did you noticed it with the same or new water?
i cant say i noticed with new water, as i am experimenting with different electrolite mixes, but i will check it out ok, and let you know... i tend to be systamatic with this sort of thing, please allow time for replys as i need to go to local library to gain "net" access... do you know why the vacume is acting this way,,,!!!. from thom.
Can you, PLEASE, tell me what the volume of gas produced is when you turn the vacuum on vs off? Stick a tube over the pump output or something. I know there will be some water vapor to add to volume, but still..
Joe of "Joe cell" found this out in their workings. Also the cell is more active probaably due to 1= the water is more negatively charged 2= you have more H4o in the water than H2o. This is due to the fact that H2o is used first in the process.
What are the size of the tubes that you are using and are you using a pwm on dc?
Did you find the harmonic Frequency of the tubes first??
very good info i found that more hydrogen is produced while running a vacuum directly from the intake manifild of my car, and a good compression engine only pulls about 15inches of vacuum, still is way better then a pressuruzed system.
Yes, The gas from the pump output is combustible (HHO). I'm gathering parts for a pulse system, plus I need to get new vacuum pump oil for more tests.
I think I know why the amps go down. If apply a Vac the bubble become bigger, as well as the bubbles between the gap of the 2 tubes. if more bubbles between the tubes then lesser water. lesser water means lower conductivity. lower conductivity means lower current amps. Thus my theory makes sence? correct me if im wrong..
yah I agree with you. the advantage of the vacume helps to take away the bubles from the tubes faster. If you could replace the water as fast as the bubles being drawn between the tube by forcing water between the tube. Good luck to you I do really hope you discover new improvement on the electrolysis process.
You have not mentioned the Cell temperature. This gas production was observed in many production cells under vaccum. But that was water evaporating at 65 to 70 Degrees under vaccum. It is not Hydrogen and Oxygen.
Again I thank you for showing that my theory on vacuum electrolysis works. The math can be found on overunity dot com in the magdrive section, look for h2opower's comments. Again thanks
Another thing I noticed the cell sat overnight, there was .7mv on the cell. Then I applied vacuum and the volts climbed to about 6.0mv and then started to drop. I removed the vacuum and it started to rise again above 11.0mv before it dropped again.
just regular tap water? or distilled?
sgtjasonshrout 2 years ago
if you are in the power band, would you get similar vacuum?
kdkinen 2 years ago
gd incredible man
kdkinen 2 years ago
can you share the specs of your tubes and how they are wired up? they seem to produce alot of hho with little amp draw. what is the liters per. min. output of this set up?
kirt660 3 years ago
SS 316L 1" and 3/4" dia 6" long connected to a 12 car batt. Nothing special. Don't know the output, never checked.
CarbideTip 3 years ago
just one 1" tube and one 3/4" tube? outer pos. or neg.?
kirt660 3 years ago
Yep, Just 1 of each. Outside tube was neg.
CarbideTip 3 years ago
thank you, its very interesting that a set up as simple as that can produce what looks to be alot of gas.
kirt660 3 years ago
Are you measuring Ma? Is that a Fluke MultMeter?
RisingSun350 3 years ago
Measuring amps with the red meter, around 5 amps. The gray meter is a fluke measuring the volts.
CarbideTip 3 years ago
As to juggernautxtr comment 'water is going t boil faster', under vacuum. Correct. However, when water boils under a low vacuum pressure. The steam isn't Hot per se, it could even be room temp or at a physcially lower temp if an ultra high vacuum were used.The main point is to allow the vacuum process aid in the electrolysis production. And why not, engine vacuum is a ready source not being used with bubbler hho cell configurations.
kunadude 3 years ago
Dear sir, I love the vids, however our tests show that a completey submerged cell will not show a change in amps. Yes you get more HHo, but the amp change your seeing is from a lack of water in your tubes from expanded gas. Sink it real deep and you won't see that amp effect. Keep the tests coming.
metalpresstv 3 years ago
Love the work, nice to see an experiment that confirms vacuum as an important factor on the production of gas. I'm sure you already know, but what scares me is seeing you so close to pressure bomb that could go off, and if your really unlucky then ignite..
kerpal2343 3 years ago
the problem i see with this is your going to have a runaway event a lot faster cause the water will boil faster, though nothing wrong with experimentation, but i see a sooner runaway event occuring,because your boiling point is lower. i would like to see the results after running for 30-45 minutes. a typical drive to work.
juggernautxtr 3 years ago
problem is you don't want current in the circiut, currant flow will increase as well as heat but the more heat you have the more wasted energy you have. cause you really can't use the heat. the cooler the tank stays the more efficient it will be. you want the electricity to do the work, not the currant flow, thats why meyers put a step up transformer and chokes to kill the currant flow.his ran .5 amps and less
faraday's law is what you wanna apply to electrolosis.
juggernautxtr 3 years ago
The production rate of a cell using distilled water is very low (at least my cell) so I you would try it on yours using vacuum and distilled water ... see what happens.
nogarats 3 years ago
did anybody notice the amperage climbing back up as the cell ran
juggernautxtr 3 years ago
Yeah, I think it's because the amount of vacuum in the cell was being reduced by the gas created, thus reducing the rate of water vapor formed at the cylinder surfaces (from boiling). Less water vapor bubbles means less resistance to current flow and increasing amperage.
captainwho1 3 years ago
problem is that if you put a vacuum on water it's going to boil faster. just like the cars cooling system, pressure is applied to keep the water from boiling. less pressure means lower boiling point, more pressure higher boiling point. and i think that might have been what part of meyers device was doing, he was preventing heat with pressure.heat means more resistance.
juggernautxtr 3 years ago
In the case of a liquid electrolyte solution, more heat would mean higher kinetic energy (motility) of the ions in solution and thus LESS resistance to current. This is why when hydroxy boosters heat up, the current also increases - runaway current phenomenon.
Look up "phase diagram of water" and "partial pressure of vapor" and "ideal gas law" to better understand why water boils at lower temperature at lower pressure.
captainwho1 3 years ago
Tip,
It may be that by applying a vacuum you are helping release the gas bubbles from the cylinder walls. This would free up surface area for new gas formation and thus reduce the load or amperage required to produce the gas.
eweesauer 3 years ago
When you get your problem with the vacuum pump oil (contamination of HHO?) solved you could determine the gas production with the vacuum vs. with no vacuum using a good HHO meter. Then you could also fill and tie off a large balloon with vaccuum pump and weigh the balloon in water and in air. From this you could determine the density of gas inside. If you do this also without the vacuum pump, you'll be able to combine this with the volume measurements and determine which produces more H2.
captainwho1 3 years ago
Intuitively I can't really see why the rate of electrolysis should be increased when a vacuum is applied. Perhaps the fact that your amps is decreasing when under vaccuum is due to the fact that the water vapor bubbles forming on the nucleation sites presented by the tube's surfaces is actually inhibiting current flow. This would tend to imply that rate of electrolysis actually decreases since it is well known to be a function of amperage. Thanks for sharing this.
captainwho1 3 years ago
Depends on what your doing with it. Theirs lots of options and designs. Be careful.
CarbideTip 3 years ago
Copper will break down. Wont last very long.
316L Stainless works best. Don't overdrive the cell otherwise you will leach iron. 2-3 volts per gap.
CarbideTip 3 years ago
have you done tests increasing the pressure?
that way the density of the water is higher, and maybe splits more molecules an amp/volt.
Very weird that it reacts that way
nice work
bonnemichael 3 years ago
The idea was to lower the vapor pressure of the water. But yes, clearing the plates will produce more gas.
CarbideTip 4 years ago
i think i have an idea on clearing the plates and usung a vacumn could you give it a look and possibly a comment if you can help
crob227 4 years ago
what are you useing for electrolite ?? at what volts / amps. im using 12 volts in 1 Litre of wtr, 6 amps. but volts drop to 8 & 8.5 after a few runs...
NEON271156 4 years ago
Baking soda. The gray meter is volts and the red is amps.
CarbideTip 4 years ago
what sort of volums are you getting per minute on that ??
NEON271156 4 years ago
I have an idea. If we know the exact volume of the container and hose under full vacuum and the amount of time it takes to change pressure from say -30 to -20 then we can calculate the volume of gas. Right? Then we can calculate the watt/hour efficiency. Then we can compare to production at normal atmosphere pressure.
cheaphardwarez 4 years ago
Good idea.
I guess we could do that with just the cell under vacuum. I'll check it next time that cell is setup.
CarbideTip 4 years ago
when you say the unit became more active...as you went on, well i have noticed this too, i tended to think the metal was aligning structurally some how, and after a few runs it did run better..
NEON271156 4 years ago
I was thinking the tubes were getting conditioned and the water was getting charged. But your idea does make sense. Did you noticed it with the same or new water?
CarbideTip 4 years ago
hi, sort took so long to reply,
i cant say i noticed with new water, as i am experimenting with different electrolite mixes, but i will check it out ok, and let you know... i tend to be systamatic with this sort of thing, please allow time for replys as i need to go to local library to gain "net" access... do you know why the vacume is acting this way,,,!!!. from thom.
NEON271156 4 years ago
Note someone pulled this math from my site, I just found out.
h2opower 4 years ago
Can you, PLEASE, tell me what the volume of gas produced is when you turn the vacuum on vs off? Stick a tube over the pump output or something. I know there will be some water vapor to add to volume, but still..
cheaphardwarez 4 years ago
I can't do it with this pump. The gas gets absorbed with the oil in the pump. So the test would be inconclusive.
H2opower did some tests and with math.
watch?v=GMYNiE-KOn4
CarbideTip 4 years ago
I too can't measure the true gas output, but I did put on some math that does help explane the process.
At 1 ATM 298k the energy requirments are W = PDV = (101.30 x 10^3 Pa)(1.5 moles)(22.4 x 10^-3 m^3/mol)(298K/273K) = 3.715 KJ
At .2 ATM and 298k the energy requirments are; W = PDV = (20.260 x 10^3 Pa)(1.5 moles)(22.4 x 10^-3 m^3/mol)(298K/273K) = 0.7431 KJ
At .1 ATM and 298k the energy requirments are; W = PDV = (10.130 x 10^3 Pa)(1.5 moles)(22.4 x 10^-3 m^3/mol)(298K/273K) = 0.3715 KJ
h2opower 4 years ago
Joe of "Joe cell" found this out in their workings. Also the cell is more active probaably due to 1= the water is more negatively charged 2= you have more H4o in the water than H2o. This is due to the fact that H2o is used first in the process.
What are the size of the tubes that you are using and are you using a pwm on dc?
Did you find the harmonic Frequency of the tubes first??
Great video Thanks
h2otohydrogen 4 years ago
3/4 inside 1" x 8" 316 SS. Straight DC, Tubes were not tuned.
CarbideTip 4 years ago
Thanks
h2otohydrogen 4 years ago
very good info i found that more hydrogen is produced while running a vacuum directly from the intake manifild of my car, and a good compression engine only pulls about 15inches of vacuum, still is way better then a pressuruzed system.
clackdwack 4 years ago
That is really cool. Just got to keep the bubbles from escaping the generator. Maybe a filter or a water trap? Nice work!
jboritzki 4 years ago
Yes, The gas from the pump output is combustible (HHO). I'm gathering parts for a pulse system, plus I need to get new vacuum pump oil for more tests.
CarbideTip 4 years ago
I think I know why the amps go down. If apply a Vac the bubble become bigger, as well as the bubbles between the gap of the 2 tubes. if more bubbles between the tubes then lesser water. lesser water means lower conductivity. lower conductivity means lower current amps. Thus my theory makes sence? correct me if im wrong..
JonsDman 4 years ago
I'm sure thats whats going on. One idea is to pull or push the gas away from the plates/tubes to keep the production up.
CarbideTip 4 years ago
yah I agree with you. the advantage of the vacume helps to take away the bubles from the tubes faster. If you could replace the water as fast as the bubles being drawn between the tube by forcing water between the tube. Good luck to you I do really hope you discover new improvement on the electrolysis process.
JonsDman 4 years ago
interesting. Thinking of an engine with a compressor... you'll end up having a 4-wheeled rocket!
samoht1977 4 years ago
The cell temp was between 75-80, 29in to boil.
CarbideTip 4 years ago
You have not mentioned the Cell temperature. This gas production was observed in many production cells under vaccum. But that was water evaporating at 65 to 70 Degrees under vaccum. It is not Hydrogen and Oxygen.
seshkanuri 4 years ago
I had long suspected a vacuum mixed with a wfc would be interesting.
j777777 4 years ago
Again I thank you for showing that my theory on vacuum electrolysis works. The math can be found on overunity dot com in the magdrive section, look for h2opower's comments. Again thanks
h2opower 4 years ago
OMG Thats the most bubbles i seen from Just one rod. HOLY COW he is on to somthing with the vacume
adam3176 4 years ago
Thx D. I thought it was 304.
CarbideTip 4 years ago
Another thing I noticed the cell sat overnight, there was .7mv on the cell. Then I applied vacuum and the volts climbed to about 6.0mv and then started to drop. I removed the vacuum and it started to rise again above 11.0mv before it dropped again.
CarbideTip 4 years ago
Good work!
It would be interesting to measure output (ml/min.)difference. Thanks.
gibs7 4 years ago
Thank you,
Yes, working on that now.
CarbideTip 4 years ago
Thank you hollywood. Yes, DC from car batt. 3/4 inside 1" 304 stainless.
CarbideTip 4 years ago
it is nice to see good work such as yours 5**** are you using strait DC and what kind of tubes are you useing.
holywdtughguy 4 years ago