@GingleGangle1 IIT is India's version of MIT. If you graduate from IIT, you're considered to be one of the top most engineers in the world. Its a very prestigious institute.
The fringes will ONLY appear if the source is coherent, such as from the spatially coherent Sun, or coherent in time and space like a laser. A flashlight would not show the fringes.
Time is a scalar, and x, y, z are vectors. A particle exists at a point in spacetime (t, x, y, z). A collection of coherent particles can then have a pattern in spacetime. Incoherent particles have no such pattern.
What one can do is write these with their basis vectors: (t e_0, x e_1, y e_2, z e_3), so that t, x, y, and z are scalars as you say. The combination of x e_1 does behave like a vector. While the norm of the basis vectors is 1 in flat spacetime, they can be greater or less than 1 in curved spacetime.
nice one
MrVishalmaan 5 months ago
i thought u never know where a particle is according to the heisenberg uncertainty principle...
legomyeggo123 6 months ago
sir, you really are a life saver... ! :)
conductance99 11 months ago
Is this in an university?
GingleGangle1 2 years ago
@GingleGangle1 IIT is India's version of MIT. If you graduate from IIT, you're considered to be one of the top most engineers in the world. Its a very prestigious institute.
davydany 1 year ago
@davydany of course
98327277 2 months ago
Eighdeen eighdees nuts
greasebird 2 years ago
This comment has received too many negative votes show
its maxwell not maxwells. idiot
ryanomaly84 2 years ago
The fringes will ONLY appear if the source is coherent, such as from the spatially coherent Sun, or coherent in time and space like a laser. A flashlight would not show the fringes.
Time is a scalar, and x, y, z are vectors. A particle exists at a point in spacetime (t, x, y, z). A collection of coherent particles can then have a pattern in spacetime. Incoherent particles have no such pattern.
sweetser 2 years ago
x,y and z are scalar, too. only (x,y,z) is a vector ;)
MCHelium 2 years ago
What one can do is write these with their basis vectors: (t e_0, x e_1, y e_2, z e_3), so that t, x, y, and z are scalars as you say. The combination of x e_1 does behave like a vector. While the norm of the basis vectors is 1 in flat spacetime, they can be greater or less than 1 in curved spacetime.
sweetser 2 years ago
no (x,y,z) is a co-ordinate, [x,y,z] is a vector.. nub
gunshin2 2 years ago
man, i was wanting to learn about waves, i have no idea what a 'vave' is or how it pertains to waves.
13houses 2 years ago
i was wanting?
Nes232 2 years ago
yes, at the time.
13houses 2 years ago
hah
rockerfrog25 2 years ago
too long clip just show me a link for a emp small bomb device for god sake :)
Hambidosvinet 2 years ago