Added: 3 years ago
From: MuchoMath
Views: 19,963
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  • thank youuu!!!!

  • This guy is so energetic.

    I like it. ahhaha

  • @ItsNoelDur Hope it helped! Charlie says hi!

  • @ItsNoelDur Hope it helped you with your logarithms! Charlie says hello!

  • do they make videos for understanding chemistry? if so, I will get straight A's with no hesitation!! :) thanks again!

  • @HNI4EVER Not yet. Sometime in the future :)

  • Great video, logarithm is easier now that I've watched this!

  • guido charlie

  • @xbox19691 Being that I play the role of Charlie myself, I guess that means me too! :)

  • The special effects and the acting skills keeps students keen to continue viewing. The simple but effecting teaching methods makes it easy for students to remember. If there is a category for YOUTUBE MATH videos at the Oscars. This video will win hands down

  • Oh my gosh, I didn't understand this in class; my teacher was making it so difficult and wouldn't explain the work clearly.

    You made this so easy to understand! Thank you so much! :)

  • U are the bomb... I love logs now...

  • Oh my, this was so helpful!

  • wow thanx that was a great explanation!

  • @Heatseaker19 Thanks!

  • THANK YOU SO MUCH! i have finals in a few days and this saved my life for math and chemistry! becuase i was having a hard time understanding logarithms but now i am saved! god bless you sir!

  • Thanx I understand how to do this...my professor was making it so difficult...hey I know Im 2yrs too late on this video bt this just saved my life!!!

  • @sexy2lvrn That's good to hear Sexy2lvrn! Best of luck to you and go for that "A".

  • ok wtf at this question in my book, I can't get any answers anywhere and I got like 4 days off school so I can't ask my teacher, can anyone help me with this question?

    2log(e^5t) = 75

    I try do log(75 equals... then what? answer divided by log(e^2? 2log(e? none of those get the right answer... how do I do this? help ;O

  • @super6plx I am assuming the log is referring to a base 10 logarithm. First divide both sides by 2. log(e^5t) = 75/2 . Next exponentiate using base 10. This gives you e^5t = 10^(75/2) . Next take the natural log of both sides. Now you have

    5t = ln[10^(75/2)]. Finally divide both sides by 5.

    t= { ln[10^(75/2)] } / 5 = 17.269388 Hope this helps.

  • I wish you taught in my High School at Australia...

  • This was great! Thanks!

  • Glad I could help!

  • wow! so awesomee!!! thanxxxx alotttttttt mr perezzzzzzzz! ==]]] wooo

  • I wish you would be teaching at my university, that way I would have understand how to do those log and ln.

    thx for the great video

  • thanks guys

  • WOW !!! u guys are amazing ... i finally get it!

  • THANKYOU

    i finally get this now :)

  • Glad to hear that! Good luck with your studies! Go for that "A"! MuchoMath

  • hey prof perez. dont know if you remember me. but i mthe name youll never forger i wanted to update you. i got an A in that elementary alg class, and am in intermediate alg/ trig/colleges algebra lol and getting an A plus so far. i looked ahead at the problems and theyre difficult like solving logaritmic equations mans.

  • WOW this is awesome! Professor Perez rocks! Would it be possible if you guys could make videos for other courses such as on infinite series, electricity and magnetism, physics or other higher level mathematics?

  • Someday....It's all a matter of time and funding! Thanks for you comment!

  • this video is sooo helpful, my precalc final exam is coming up and i think this was much better than my teacher's explanation.

    Thank u so much =D

  • Hope your final went well...glad I could help! Thanks for stopping by :) MuchoMath

  • thank you so much for this video i take my EOCs tomorrow lol

  • Hope your EOC's went well! Best of luck to you! MuchoMath

  • you SHOULD be my math tutor in my college! goodness,my current math tutor is making math concepts complicated & messy.

    thank you thank thank you for the video,totally useful for my own study guide.

  • No problem cxilelab, glad I could help. Thanks for stopping by! MuchoMath

  • This is great. You should number your videos just so I know which ones to watch next.

  • dan665, To see all the resources in an organized format use the website link on my home YouTube page. This log videos can be found in the Chemistry Prep section. Also, accessing the video through my faculty webapge will provide you with a higher quality video. Best of luck to you!

  • this was really easy to understand thank you

  • Thanks for your feedback! Best of luck to you!

  • boy, I needed this. I have finals tomorrow in college algebra.  Wish I had known about this earlier

  • Hope everything went well for you luv4shorty! Good luck with your studies! MuchoMath

  • Worked like a charm, Its amazing how things come to light when you have a good teacher. I got my results, and I PASSED!! I'm done with college! I OWE YOU ONE!

  • That's wonderful news! Your off to the Big Time now!

  • awesome! that clears up somemore vague concepts since im preparing for my math2 sat test in nov.. lol. thanks!

  • Hope everything goes well! Best of luck to you Ren520! MuchoMath

  • great videos muchomath and charlie. your teaching style makes it easy to understand. can u make videos on series and optimization problems or etc. cool stuff. besides im going to 7th grade after this summer guess im having head start for high school math. gracias amigos. keep up the good work.

  • Thanks for the comment turbold1. At the moment I am focusing on pre-algebra videos. In the future, by the time you get to high school, I should have some cool stuff up for you to use. Best of luck to you. Oh, and by the way, I am Charlie ;) MuchoMath

  • awesome video!

  • Thanks flatbshfinest! Best of luck to you. Go for the "A"! MuchoMath

  • dude you rock!

    and your crew(i.e CHARLIE) is also fantastic,

    though i had done logarithms in 8th grade, the video was awesome to get the basics back, anyways, i hope you keep making such rocking vids so i'll stay home all day lol!

  • hargun1011, Thanks for the comment. We wish you the best with your studies! We will try to keep rocking and you keep studying. Best of luck to you! MuchoMath and Charlie

  • Thanks. This was very informative for my project. :D Thanks for helping a 7th grader out.

  • No problem mattroom. I hope you get an "A" on your project. It's pretty cool that you are working on logarithms in the 7th grade. Keep up the good work!

  • Glad I could help woowiwoo. Hope you get an "A" in your math class! Good Luck!

  • Great vid! You saved my marks thanx!

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