Cisco Training CCNA IP Addressing - Part 8

[MrGhaz12345]

hi can u please tell me y c.and d. are not network addresses and are host addresses thanks

[ilyanneDOTcom]

@MrGhaz12345 , network address have all all bits of the host part se to "0".

So, in the case of C and D, their network address are 172.16.64.0 and 172.16.32.0.

[khellozme]

i have a question plz!

ur magic-number trick.. works on all IP classes ?! if it does.. do we always start the table with 192 on the right and start jumping depending on the subtraction? thank you

[fuzzykatgti]

great vids!

Cheers

[kherysado]

many thanx

[dkniles1]

Many thank you for your excellent work!

greece

[XICMI]

/user/XICMI#g/u

[mztguitar]

well... quick question how much time per question you have when taking the CCNA exam?? and also total.. who knows and who has passed the exam??? Thanks

[mztguitar]

Que cagada que es esta nota.... pero al menos ya lo entiendo... ahora si a sacarme la chucha practicando!!! jajajajaja!!

[alfatourist]

.32 & .64 are subnet address, thanks

[Slamsonite2]

@alfatourist u sure about that?

[oceanofparadise]

Its a great job. I appreciate your hardworking.

[ryanensano]

yes you're all correct. . 64.255 and 32.255 are both networks. . don't be confused. . just review the past lessons they haD . . i think it was the part6. .

[abed83a]

I thought .32.255 and .64.255 are network addresses. Could u pl tell me if I am wrong and why? Bit confused.

[Kyo407]

You have to remember the third octet is what we are looking at. A valid subnet would be 172.16.32.0 and the broadcast of that would be 172.16.47.255 since 48.0 is the next subnet.

[Cloutar]

Don't want to confuse anyone, but isn't it true that the .32.255 and .64.255 adresses are the subnet adresses?

[AliAlHamad99]

@Cloutar NO it's like this

64.0 is subnet address , 64.1 is first host , 79.254 is last host , 79.255 is broadcast

32.0 is subnet address , 32.1 is first host , 63.254 is last host , 63.255 is broadcast

so 64.255 , 65.0 65.1 . . .... and 32.255 33.0 33.1 . . . ....... is HOSTS

[AliAlHamad99]

@AliAlHamad99 Correction

32.0 is subnet address , 32.1 is first host , 47.254 is last host , 47.255 is broadcast

sorry

[superjamiedotnet]

The 128, 192, etc table is probably the most useful piece of IP addressing help I've ever seen. Couple that with 256 "magic number" and subnetting becomes so much easier. Thankyou very much!

[JediTony81]

Alternative to finding the decimal subnet mask is to start with 32 - 20 = 12

then 12 - 8 = 4

So you know that you have four host bits in the third octet.

Therefore, the step size (magic number) is 2^4 = 16

From there continue the same way as described in the video.

[PCSJEFF]

Thanks !

I used to calculate the subnet mask for each address but with your method (the "256 magic number") it's much faster :)

[kohlnomad]

I like your methods better than Todd Lammle

[pilipk01]

superbly explained

[mursaleenshah]

thankx budy

these help me in teaching tcpip to my students

[flowbacks]

Please more!!!!

[xwarblade]

Thanks! this is great!

[agnoathe]

awesome i m your fan ! such a nice explanation. really thankful

[d8thangel]

It was educational !!! more upload sir

[rahmanrubel]

Very Gud