Added: 3 years ago
From: TinselKoala
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  • I think you need to produce double the magnet strength in order to act on the magnet enough to separate them. My guess is that you would also nee to produce a magnetinc field in the separating metal part and reverse the poles. Example: -/+ -/+ -/+ -> -/+ +/- -/+ (-/+ = magnet). A simple way to do this would be a split iron core (a gap in the separator block) with two coils wrapped in opposite directions and just switch between the two.

  • Yes, that has been suggested. However, I am not trying to prove the LTLOT, I was testing a specific hypothesis involving a particular configuration, trying to show that under the conditions specified, no anomalous thrust was produced. So I did.

    I have recently constructed a suitable driver circuit and will be performing various experimental variations of the experiment. Watch this space (but be patient.)

    --Trust, but Verify--

  • Umm. I'll have to refer back to that when (if) I'm ever sober, er, not too busy.

    Seriously, it sounds like a good experiment to try, and I'll put it in the input buffer.

    Thanks.

  • The center of mass must be moving off center and then returning to that position on reset. This is because the magnet is pushing off the magnetic field which is coupled to the coil. If the magnet is thrust to right, then the coil must be thrust to the left. However, F=MA applies and the greater mass means a lower acceleration in the same time period. So it becomes possible to accelerate the magnet at a speed that prohibits coil movement. Lengthen the tube to one full wave length of the applied..

  • ...frequency. Increase the amplitude of the signal to afford moving the magnet to the end. Apply a positive going signal of F and a negative waveform of F/2 for each cycle. attach a laser pen to your coil perpendicular to the tube and mark its point where it strikes the wall across the room. Energize the system and mark the outside edges of the laser travel. Compare them to the center mark. See if they are lopsided in accordance with the time deviation of F/2 for the return path of the magnet.

  • So even though there is a conservation of momentum, there is a cumulative shift of reference due to a separation of time.

  • Note: The magnet should NOT strike the end in the experiment I outlined. :D

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