Lecture - 10 Frequency Response Bode Plot

[Hassanspy]

very helping lecture infact

[PunpzMusicVEVO]

I wish I was like him. He's ridiculously good...

Teach... YOU FUCKING ROCK!!!

Now I'm gonna fail if I may.

[kkorovesis]

Great lecture !!!

Very helpful for my exams

Thank you,

[Afr0Afr0]

oh jeez thanks.

[olinadolinad2]

it's like being teatched by Raj

[justincgs]

great video!

I'm learning so much!

smart class 43:34 !

[hefferbh]

Dear lord of the frequency domain , i salute you ! /o/

[strobe007]

I owe this man a pint

[jchristopher1054]

Wish my circuits professor was this good!

[wahedul]

fuck it



[IIXXBeastXXII]

im a boss! is this alrite?

[Pyroclasmic]

Great frequency response lecture, I was struggling with Bode plots and this pretty much cleared it up for me. I love how he constantly says "Is this all right?" Great prompt to get you thinking. My thermodynamics professor deliberately made 'mistakes' in lecture to keep us on our toes, this guy's queues help keep you active in the lecture (despite the lack of 'mistakes').

[juliannevillecorrea]

thanks a lot

[mrjforjoker]

thanq man for helping me to pass my xam

[TheNishnish1]

Are there any lectures on polar plots n nyquist plots?

[TheNishnish1]

this is so amazing

[monkeyneedsmoney]

FAKE! you fuckin bastards cant be serious about this shit!

[ssandar15]

this man is the boss... "is this allright???"

[gag747]

Thnks Alot Sir..

Got The Clear Idea!!!

[johncenashah]

this video is not getting downloaded can any 1 give me another link of dis video or upload dis video.....plzzzzzzzzz.....

[wajdiplusraja]

God sent me this man to save my pathetic ass in the last fuckin Minute

[silverbullet761]

I have learned more in 59:39 than I have all semester... You are a great professor!

[silverbullet761]

I have learned more in 59:39 than I have all semester... You are a great professor!

[prohannan]

Astaaaad teacher :D

[prohannan]

where is the next lecture plz

[widdalightsout]

Thankyou very much Sir. You have been really helpful.

Greetings from Pakistan

[tamyboy1]

respect for this man!

[icompee]

ossum man. i am having my exam of cs tommorow, not knowint bode plaot, and now, i know it..wow... best lecture of cs. thanks sir.

[tranzoditty]

greetings from an Indian student studying in University College London, awesome professor!! Is it from IIT?

[YanbuCollege]

brilliant professor

[TahirAljazeera]

could you please upload the continuation lecture? thanks in advance...

[darknecromancer34]

arigato ^_^

[codywrite]

@jagiradaaku so what if he' indian?. are you trying to be racist ?

[CrittyWitty]

It IS all right! Thanks! Way better than my prof.

[AlHensem]

Nice explantion....i got a clearer picture..

[TacTiCOrc]

YOU SIR, ARE AWESOME! Thank you !

[asrm]

33:30 is not right, you either make the second and third addend -log something or log 1/something.

[asrm]

@asrm ok someone says it afterwards.

[jagiradaaku]

he is INDIAN and i proud to be INDIAN

[KhanSlayer]

At 26:03 shouldn't squaring j produce a (-1) so your magnitude is 1 over the square root of (1 - omega^2/100) instead of ( 1+ omega^2/100)?

[Braati]

@KhanSlayer absolute of a complex number a+jb is defined as sqrt(a^2+b^2) no matter in which quadrant of the complex plane it points. It hast to be positiv. think of the hypotenuse in a right-angled triangle

[KhanSlayer]

@Braati Actually my error results from improper calculation of the magnitude of a complex number.

|a + jb| is not sqrt((a + jb)*(a +jb)), as I was previously using, but instead I should have used (a +jb)*(a -jb), squaring the complex conjugate. That gets rid of the negative component of squaring j. Thanks anyway.

[TacTiCOrc]

@KhanSlayer Could you tell me why the j from s = j 10 @49:00 disappears when he puts it in for 5 s ?

I know that it disappears when putting into s^2 because of the ^2. but i dont get why he leaves the j there.

Would be really nice, if you could tell me. Thanks.

[taoridi]

@TacTiCOrc Don't know if you got the answer already, I am a little thrown off by it but my best guess would be that we always take the absolute value of G(jw) in the log... This should make it just 50, what do you think?

[KingDimDirim]

@Musictheman

Laplace Transformation...

[Musictheman]

at 9:43, he does not explain the relationship between I(s) and i(t). How does he jump from one to the other?

[u4707889]

This is amazing .....thanks for uploading this video ....it really helps me alot in understanding bode plot.....

[eriksven1]

Thank you sir, you are the greatest !

[asithakal]

An excellent Teacher.... Hats off to you Sir....... A job well done....

[blingg247]

Thank you proffesor for breaking down Frequency response bode plot...

[faddikhan]

Thank you from pakistan. 

[stefankalmar]

I have still not found an "Indian professor" on YouTube who gives a good internet lecture. That's sad....

[therash09]

@stefankalmar Who do you think the person in the video is? An Indian of course!

[vijaysuri]

@sephiroth671 7th dickhead...

[damasgate]

don't make fun

[BregyptianMuslim]

46:00 it is kind of confusing how they use ωn and ω to mean completely different things..

the video is an excellent step-by-step guide though, thank you

[6DesertAngel9]

Thank you! Thank you! Thank you!

Not only do I now understand but I understand 'WHY' the plot should look the way it does. I can't wait to view your lecture on plotting the phase response.

I am so very happy that I want to cry. I wish I had found you sooner. You are most wonderful!

[6DesertAngel9]

Thank you! Thank you! Thank you!

Not only do I now understand but I understand 'WHY' the plot should look the way it does. I can't wait to view your lecture on plotting the phase response.

I am so very happy that I want to cry. I wish I had found you sooner. You are most wonderful!

[BpJN168]

all ur lecture are very interesting. fantastic job sir.

[Yereke]

At 10:30 what formula was used to find 5/(2)^2*sin(10t-45)?

[eerereps]

@Yereke I think he used the sin(a-b) and kept b=45 degrees. it simplifies to what he wrote. sin45=cos45=root(2)/2

[nishanthrajamani]

@Yereke sin(A-B)=(sinA*cosB)-(cosB*sin­A),so here B=45,where sin 45= cos 45 = (1/sqrt(2)). so he writes sin10t-cos10t=sqrt(2)*sin(10t-­45)

[xxx457081]

@nishanthrajamani the formula u said is wrong...

sin(A-B)=(sinA*cosB)-(cosA*sin­B)

[nishanthrajamani]

@xxx457081 thank you! i meant it, but guess i typed it wrong. thnx anyways :)

[Anirudh]

u r tooooooo good...

its OK...

[DigiTan000]

You know what happens to a bode when it's struck by lightning?

[mac3ksu11]

Thank you for explaining this. Greatly helped me to understand the concept. I liked how you started with the simple examples and slowly increased the difficulty.

[bj93081]

This is very helpful for my review. Thank you.

[kumaramit008]

thank you sir this lecture is most useful for me at this time!!!

[KaiInSydney]

GG

great class....kinda helped me a lot

thxx

[srdjanNS87]

this is VERY usefull, THANK you!!

...i just find it a bit hard to understand the profesors english :/

[kurdt]

die ni mesti makan kari ngan teh tarik lepas ni

[crockysam]

thx

[sunnyatglance]

the video played worth in my exam

[sunnyatglance]

superb but reciprocate a path to download

[Anirudh]

try Download helper. its a firefox addon that lets you dl videos from YT

[threelegduck]

praise you sir for this most wonderful video

[scr3wg00gl3]

This lecture saved my final exam. Thank you!!

[aseeeeeel]

thank you soo much for the video it's incredibly hepful

[eltamelta]

This is incredibly well done.

Every minute detail my teacher just mentioned in passing is given an easy explanation by Mr Basu.

[blackhole8746]

thank you so much for this video!

[chaown524]

this is wat im looking for