Thanks to MIT open courseware I was able to get my entire freshman and sophomore math curricula out of the way for pennies on the dollar by using credit by exam... not to mention skipping ahead in my major (physics) by a full year. Thanks, MIT!
I took linear algebra years ago in college, but I thought I'd brush up on it in preparation for the Stanford AI free class in Oct 2011 (it's being taught by a director at Google). I've been working heavily in ado.net for the past couple of years, and it's surprising just how how applicable this is to the work I've been doing. Anyway, I'm thankful MIT decided to put these lectures online.
Not sure if I understand the cost approximation. I interpret it as: if row 1 of 99 entries multiplies row 2 of 99 entries in order to get the pivot entry 2,1 then this operation is equal to 99 multiplications. So in the end when he is estimating the cost of just column b then wouldn't the cost be 100+99+98...+1 instead of n^2.
is it right that he called a operation (subtraction and multipliaction)? Okay then 100 square operation is right. in other case, we have ~100^2 multiplication AND subtractions. thats 2*100^2?
Im not very got at linear algebra..which is why i watch these videos.. can someone explain to me how the first number for the approximation is 100^2. I understand he is counting the maximum number of multiplications and subtractions but i guessed the first number was 99^2 because i thought you always leave the first row unchanged
@adidasguy87 Notice that he said "about" 100^2 for the first set of operations. The actual number of operation is 100*99, and when dealing with complexity you always round up. Estimation of complexity is more about getting a general picture rather than seeing how exact you can be.
@raneboy13 He can of course, but at the time at this video again, back in 1999, there was no need for HD except by the movie industry, who had to project an image in a big screen. In fact, a majority of TV's and computer monitors can't even display HD. So there was no need back then. And they were probably happy with the quality of this video back then. Get it?
I can't believe people are complaining over a free lecture. Either go buy a book and learn it yourself, or be quiet. can't complain when they are offering it for free. I think these videos are awesome, all things considered. if you have trouble reading the numbers....pause the video when they zoom in. Problem solved.
This was recorded in early Spring, 2005. On the morning of January 14 (a Friday) of that year, the Huygens probe landed on Titan. That might explain, but not excuse, the rudeness of the MIT students in this lecture.
Don't be discouraged by this lecture. The rest of the series is excellent.
I don't understand why when he counts the total number of operations needed to tranform matrix A, namely the same of 1^2+2^2+...+n^2, he uses caculus method to approximate the total number, while we know that the discrete sum of squared natural numbers is equal to n*(n+1)*(n+2)/6....
If you read his book about Linear Algebra, you'll see why he is so interested in approximating the number operations needed to either solve a system, find a determinant, etc.
Basically it's because if you have a huge number of equations, you have to use a computer. But the technique you are going to use in order to perform your desired operation is based upon the number of operations needed. Less operations=faster computation.
This video helped me to break through some mental blocks in understanding the concept of LU decomposition and how to construct elementary matrices. Thank you, MIT, for making this material available at no cost to viewers. Gilbert Strang R-O-C-K-S!
wow what happened to this lecture its so bad quality and not only hard to see what he writes but hard to listen with the noise and everything... its still beats reading the book and my professors lecture but not what i'd expect from the qualities of all the other lectures i got from Linear Algebra from MIT
Ah, what Professor Strang offers on how many operations it'll take is a little strange. the n^2 and n^3 are very poor estimates. You could just imagine removing a triangle from the matrix, the area of that triangle would give the required operations at maximum. Or n(m-1)/2 = max ops. Since we're removing a triangle of dimensions (m-1) (since we do not touch the first row), times n. For a m by n matrix.
@rehxyz I agree with you, this n^2 approximation is quite poor. First, we don't know what will be the results after our operations. second, I guess he takes the max max operations.
@rehxyz , I'd tend to agree, except to point out that we're talking about an n x n matrix, so n(n-1)/2. Of course, I assume he knows something we don't, because he's lecturing at MIT and I'm watching videos on youtube 0_o
The compression on this video is too much. The letters on the chalkboard keep wiggling and dancing around. when the camera guy pulls back, it is completely illegible.
One of the reason is that after studying and proving results for row space of a matrix A, you can then easily generalise them for column space of A by looking at the row space of A^T.
So far I am very impressed with the quality of these lectures. I attend a post-polytechnic university in the United Kingdom and my CS course offers very few Maths subjects, so these lecture videos are brilliant for someone looking to learn.
Much appreciated. I've missed a few lectures due to serious illnesses, and although I live in Sweden, this contribution from MIT make it possible to catch-up almost friction-free. Thanks.
Theese are great. I missed a large part of the education during linear algebra and with theese videos I don't have to wait untill next year to catch up but can do it as I have time.
Watching theese 35 videos is something you could do in a couple of days if you work fulltime with it.
why am i watching this
TheJacChannel 1 week ago
does anyone know the name of that algebra text?... or where can i find it?
jorginho1726 2 weeks ago
Good but I think it recorded by dean's mobile phone
sivrisinekk 2 weeks ago
I am very happy to see the vidoe after you give this Factorization into A = LU
NganaJHone 2 weeks ago
This has been flagged as spam show
I am very happy to see the vidoe Lecture 4: Factorization into A = LU after you give this
NganaJHone 2 weeks ago
Steady I Really Like This Video Factorization into A = LU
Ondelendo 2 weeks ago
Good, I like that you share this video Lecture 4: Factorization into A = LU, I wish success always
bebeheuy 2 weeks ago
Nice Video That You Share , So Very Nice Thanks You Factorization into A = LU
willamricard 2 weeks ago
I Really Like The Video Factorization into A = LU From Your
imegatrone 2 weeks ago
Your Video Factorization into A = LU Is Very Useful Sharing
bundawartini 2 weeks ago
after i watched this video Factorization into A = LU, my insight is very open because the video is very good to give information
anakmudajaman 2 weeks ago 2
240p? are you serious?
WhitEagle7 4 weeks ago
This has been flagged as spam show
iphone and ipad app for calculating matrices:
itunes.apple.com/us/app/matrix-multiplication/id477093471?mt=8
bebefore3 2 months ago
Thanks to MIT open courseware I was able to get my entire freshman and sophomore math curricula out of the way for pennies on the dollar by using credit by exam... not to mention skipping ahead in my major (physics) by a full year. Thanks, MIT!
QuantumMadcow 3 months ago
Das Bild ist nicht gut, ist die Klasse Englisch, aber es ist eine gute Lektion.
TheMingusjazz 3 months ago
thanks professor strang
akhil089 3 months ago in playlist b.linear algebra
Thank you MIT for embracing the true purpose of science and publishing these lectures!
SirZagga 4 months ago 6
I took linear algebra years ago in college, but I thought I'd brush up on it in preparation for the Stanford AI free class in Oct 2011 (it's being taught by a director at Google). I've been working heavily in ado.net for the past couple of years, and it's surprising just how how applicable this is to the work I've been doing. Anyway, I'm thankful MIT decided to put these lectures online.
bucky765 4 months ago
I hope that there are NO MORE video lectures in the series that are this low quality in sound and picture.
trese0000 5 months ago in playlist MIT 18.06 Linear Algebra, Spring 2005 4
Comment removed
Rakamonk 7 months ago
I realy need that lecture and, but image and sound hav bad quality !!
ricsurfpro 9 months ago 5
The video quality is absolutely not tolerable!
andywuu2002 9 months ago 4
Not sure if I understand the cost approximation. I interpret it as: if row 1 of 99 entries multiplies row 2 of 99 entries in order to get the pivot entry 2,1 then this operation is equal to 99 multiplications. So in the end when he is estimating the cost of just column b then wouldn't the cost be 100+99+98...+1 instead of n^2.
jdunn015 10 months ago
is it right that he called a operation (subtraction and multipliaction)? Okay then 100 square operation is right. in other case, we have ~100^2 multiplication AND subtractions. thats 2*100^2?
GoPila1989 10 months ago
where did he find -4 in the E(21) its not clear and also there is tooooo much noise.
xgokkusagix 10 months ago
If you are having trouble viewing this lecture, open up the interactive transcript...it helps.
SpoiledLogic 11 months ago 2
Im not very got at linear algebra..which is why i watch these videos.. can someone explain to me how the first number for the approximation is 100^2. I understand he is counting the maximum number of multiplications and subtractions but i guessed the first number was 99^2 because i thought you always leave the first row unchanged
adidasguy87 1 year ago
@adidasguy87 yeah but if you consider the special case where first pivot is 0, you would need 100^2 operations
feng264404 1 year ago
@adidasguy87 Notice that he said "about" 100^2 for the first set of operations. The actual number of operation is 100*99, and when dealing with complexity you always round up. Estimation of complexity is more about getting a general picture rather than seeing how exact you can be.
BlackMage1016 11 months ago
great job ... thanks
waqar0204 1 year ago
its shot in 2005Why does it look like its from the 80s..lol
mohinder3333 1 year ago
@mohinder3333 Actually it was shot it 1999. That explains why.
spectralblue 1 year ago
they're MIT and cant afford SUPER DUPER HD video recorders?
raneboy13 1 year ago
@raneboy13 HD recorders were very expensive and bulky and only used by the movie industry at the time of this video (1999).
spectralblue 1 year ago
@spectralblue mr. g strang cant buy hd recorders?
raneboy13 1 year ago
@raneboy13 He can of course, but at the time at this video again, back in 1999, there was no need for HD except by the movie industry, who had to project an image in a big screen. In fact, a majority of TV's and computer monitors can't even display HD. So there was no need back then. And they were probably happy with the quality of this video back then. Get it?
spectralblue 1 year ago
This is so nice. Free education, wow, i can't even believe it.
Thanks to the people who made this possible, they are great.
92sanxez 1 year ago 3
I can't believe people are complaining over a free lecture. Either go buy a book and learn it yourself, or be quiet. can't complain when they are offering it for free. I think these videos are awesome, all things considered. if you have trouble reading the numbers....pause the video when they zoom in. Problem solved.
ikanipo 1 year ago 5
@ikanipo +1
leegoldberg 1 year ago
the high definition on this video is amazing....
32docholiday 1 year ago
This looks like it's a rip of a rip og a rip that was taken with a 1 megapixel phone...why is their quality so bad so often?!
AleifrLeifrson 1 year ago
This was recorded in early Spring, 2005. On the morning of January 14 (a Friday) of that year, the Huygens probe landed on Titan. That might explain, but not excuse, the rudeness of the MIT students in this lecture.
Don't be discouraged by this lecture. The rest of the series is excellent.
- Ray Eston Smith Jr
thyorison 1 year ago
great explanation but very low quality((
iyalovecky 1 year ago
i bet he confused a lot of students with his explanation of A =LU
RingWarrior12 1 year ago
no HD makes this lecture hard to view...
klavierfan 1 year ago
Why is a MIT professor teaching high school math in an undergrad course? 2+2 = ?
trecedelemos 1 year ago
@trecedelemos
It is linear algebra...
KSH2006 1 year ago
If the subtitles were synchronized tese lectures would be just perfect
xploi 1 year ago
I don't understand why when he counts the total number of operations needed to tranform matrix A, namely the same of 1^2+2^2+...+n^2, he uses caculus method to approximate the total number, while we know that the discrete sum of squared natural numbers is equal to n*(n+1)*(n+2)/6....
gontrodestraat 1 year ago
@gontrodestraat
If you read his book about Linear Algebra, you'll see why he is so interested in approximating the number operations needed to either solve a system, find a determinant, etc.
Basically it's because if you have a huge number of equations, you have to use a computer. But the technique you are going to use in order to perform your desired operation is based upon the number of operations needed. Less operations=faster computation.
Diemedes 1 year ago
Thank You very much for these useful free courses!
Kyrgyzstudent 1 year ago
What happened to the video quality . Isn't a good version available . I mean it is sometimes hard to see what the professor is writing on the board.
earthday1988 1 year ago
This video helped me to break through some mental blocks in understanding the concept of LU decomposition and how to construct elementary matrices. Thank you, MIT, for making this material available at no cost to viewers. Gilbert Strang R-O-C-K-S!
LutherSetzer 1 year ago
Why is everyone complaining? Free lectures? This is only one vid out of many. It's not that bad once the students are quiet. Love G. Strang.
thou9009 2 years ago 6
wow what happened to this lecture its so bad quality and not only hard to see what he writes but hard to listen with the noise and everything... its still beats reading the book and my professors lecture but not what i'd expect from the qualities of all the other lectures i got from Linear Algebra from MIT
trousien 2 years ago
Wahh, this free resource isn't what I paid for, wahh
eyeojo 1 year ago 3
Okay so i'm reading the textbook for this one.. can't watch this lecture without crying
Chubigans 2 years ago
the sub-titles are not exactly in sync with the video :(
nandinis7 2 years ago 5
Ah, what Professor Strang offers on how many operations it'll take is a little strange. the n^2 and n^3 are very poor estimates. You could just imagine removing a triangle from the matrix, the area of that triangle would give the required operations at maximum. Or n(m-1)/2 = max ops. Since we're removing a triangle of dimensions (m-1) (since we do not touch the first row), times n. For a m by n matrix.
Later,
rEhxyz
rehxyz 2 years ago
@rehxyz I agree with you, this n^2 approximation is quite poor. First, we don't know what will be the results after our operations. second, I guess he takes the max max operations.
gontrodestraat 1 year ago
@rehxyz , I'd tend to agree, except to point out that we're talking about an n x n matrix, so n(n-1)/2. Of course, I assume he knows something we don't, because he's lecturing at MIT and I'm watching videos on youtube 0_o
Yizashi 1 year ago
I loved the sock/shoe analogy!!! Math nerds ftw hehe :D!
nevertalk 2 years ago 5
i'm so sad, because there is no HD
duraduri 2 years ago 6
Why is so much noise in the class during the lecture?
rammps1982 2 years ago 54
@rammps1982
It's probably aliasing from the high compression of the sound. There's no higher quality version available anywhere.
metacarpi 1 year ago
@rammps1982 it aint germany
fullmooninu 1 year ago
@rammps1982 prob another ivy slacker pass/fail class
rryking 8 months ago
LOL @ comments from meet the spy
Xenxe777 2 years ago
I didn't see Gordon Freeman in the crowd.
Unless, he was a SPY.
chaohord 2 years ago 10
very easy...simple equation
tacxof 2 years ago
the thing i like about the MIT videos is the fact they include subtitles because sometimes you cannot quite understand what they are saying sometimes.
The video quality looks like it was recorded with a backup camera. =P
w1ngzer0 2 years ago 5
linear algebra is easy
seisdoesmatter 2 years ago
mit rocks
woserzing 2 years ago 3
I got "A" this course. i think it was the most fun math course.^^;
kyousukeX 2 years ago 4
go look at uc berkeley's webcasts! much better quality!
yoinkity 3 years ago
man thats an abundant class sarcastically speaking for a linear algebra class at a university.
omhat 3 years ago
The compression on this video is too much. The letters on the chalkboard keep wiggling and dancing around. when the camera guy pulls back, it is completely illegible.
xy9izzy 3 years ago 9
わかりやすい線形代数の講義だと思う。
勉強会のねたに使えそうだ。
AgileSooftware 3 years ago 6
This is the first time ive learned Matricies ... Why would you want to transpose a matrix what benefits swapping the columns for row etc?
JackMRich 3 years ago
One of the reason is that after studying and proving results for row space of a matrix A, you can then easily generalise them for column space of A by looking at the row space of A^T.
heocon19ca 3 years ago
So far I am very impressed with the quality of these lectures. I attend a post-polytechnic university in the United Kingdom and my CS course offers very few Maths subjects, so these lecture videos are brilliant for someone looking to learn.
EnderMB 3 years ago 9
This has been flagged as spam show
this lecture is not really essential because it is possible to work those out from the facts in lecture 3
MathMikie 3 years ago
Hey folks, this is the guy to learn it from, too!
jonahansen 3 years ago 9
Much appreciated. I've missed a few lectures due to serious illnesses, and although I live in Sweden, this contribution from MIT make it possible to catch-up almost friction-free. Thanks.
ljusorange 3 years ago 7
great refresh for a MA candidate, who missed a lot in BA.
214899 3 years ago 8
Theese are great. I missed a large part of the education during linear algebra and with theese videos I don't have to wait untill next year to catch up but can do it as I have time.
Watching theese 35 videos is something you could do in a couple of days if you work fulltime with it.
Also, you could do it whenever you want to :).
lyml 3 years ago 33