Added: 3 years ago
From: physicsiscool
Views: 51,156
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  • Please right some numbers for the resistors!!!!

  • thank you!!!!!!!!

  • Fantastic summary.

  • tnk u so much

  • Nevermind, stupid me. I've got it now.

  • How does R + R + 3R/4 = 11R/4?

  • @hurrhurrmurr you multiply the R with 4 to share the same denominator. so, it becomes R + R + 3R/4 = (4R + 4R +3R)/4, and therefore, 11R/4. =)

  • @hurrhurrmurr By common dominator 4R/4 + 4R/4 + 3R/4 = 11R/4

  • slow the efff down

  • thxx so much.....i was stuckedd on dis...

  • wow i loved this!!! and i'm not even taking a physics class right now!!! :)

  • theres much easier ways to do this.

  • who are you talking to in the video?

  • thx

  • You are great ,

    :)

    :D I love u umwahhhhhh

  • Does anyone happen to know the name of the hardware used to produce this tutorial?

  • @Dajavoutube microsoft paint + camstudio

  • great!

    

  • great!

  • THANK YOU!

  • Lifesaver. I love physics入

  • thanx to the teacher..:)

  • Your explanation came straight to my attention. Thank you

  • omg thank you sooooo much.....i have a physics exam in like 2.5 hours today and i never understood these. this helped me alot. i learned more from you in those 2-ish minutes than i did from the book OR my teacher.

    hopefully this will help for my exam.

    thank you :D

  • I don't get where that 11R came from at 1:14 :-(

  • hooray lol

  • thanks teacher you help me a lot!

  • mental gymnastic

  • Nice!

  • jesus christ, you rock. I couldn't figure this problem out on my HW. You just taught me in 30 seconds what my book couldn't teach me in 3 hours. I love how you split the circuit up in different sections. I was doing the same thing, but you taught me how to do it right.

  • THANK YOU SOOOO MUCH!!!!!!!!!!!!!!!!!!! This is the exact question I am stuck on for HW!!

  • What about finding current?

  • @Nanaman12345

    Ohms Law.. I = V/R

  • @supraaman I know that. But I have problems knowing which Vs apply to which Rs.

  • @Nanaman12345 ahh ok well first of, V remains the same in a parallel circuits so I = V/ R1, V/R2, V/R3. Your confusing it with series circuit, where there is a voltage drop

  • Screw you all you lazy forum, this was hard when you are first introduced to it. But I assured it gets easier and if you stick to it... you may just understand it : )

  • too fast 4 me to understand; just a quick advice, try teaching as if you're talking to beginners, because most people who are actually interested in watching these videos ARE beginners. Thnx 4 trying n.e ways.

  • Comment removed

  • A little more elaboration with the calculations might help those who are not familiar with these questions or who are not proficient in mathematics.

  • thank you very much for the video. it was very easy to understand and it helped a lot.

  • what the hell? um, what are you accomplishing by doing this? i was expecting to see how you would more efficiently calculate total circiut resistance, current flow, voltage drop, etc... given that individual resistance values can vary.

  • Oh my god i didn't know it was THAT easy!!!!! That's what I get for choosing a physics teacher with a hardcore indian accent.

  • im getting close of understanding this whole resistance solving thing...i need to work on this or i'll fail on effing school..it's simply but math is not my kind of thing waaaaaaaaa

  • thats not maths, is it?

    exact same situation for me, parallel circuits are confusing as hell

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