How to Calculate Empirical Formula from Mass Data | www.whitwellhigh.com

[GyasiB]

I refer to this video every time i have an exam and it always helps. who ever this teacher is he is much more helpful than my teachers in london.

[TURK2010]

this helped me, im a bio major and my chem teacher goes through things a little too fast, and he has a bit of an accent, so ill just go on ahead and subscribe lol

[lewis4566]

This is incredibly helpful, I have an exam tomorrow, and really needed help! Lewis, UK

[dakanister23]

ITS WALTER WHITE!

[rdelangel82]

thank you sooooooooooooooooooooooooo much, my chem teacher sucks, for now on, your my chem. teacher!!!

[IPwn4You]

Thanks, I have a chemistry exam in 2 weeks and this helped alot

[Saville2341]

Thanks so much. From knowing nothing about this stuff at all I'm gonna have a crack at a few my own. ;)

[MADHURAJ999]

its a great harm for the tution culture of dirty indians'

[discoj1010]

i wish you spoke faster....sorry....im from new york...what do you expect?

[whitwellhigh]

@discoj1010 - i apologize....we just take things slow here in Tennessee :)...it is a southern thing lol

[jadeempoisonne]

@discoj1010 Oh get over it. That is just the way he talks. You can always speed up the video.

[DJ1TWITCH1]

@discoj1010 I was thinking the exact same thing....

[DJ1TWITCH1]

@DJ1TWITCH1 Great for clarity though



[HDxZ0mBIE]

@discoj1010 hey man i understand ya im on long island but i need it about this speed to understand this haha

[snowboardrock7]

@discoj1010 I agree with you, but his explanation was great though

[youswearifylmfao]

this really helped me...a lot...but can you do an example by using these problems- What is the empirical formula of the following- "vanadium oxide which is 56.0% vanadium and 44.0% oxygen" and " a compound contains 10.52g of Ni, 4.38g of C, and 5.10g N?"

[whitwellhigh]

@youswearifylmfao - i will try to do one ASAP :)

[Samuraikidd271]

@youswearifylmfao for the first one pretend the compound is 100 grams, so you have 56 g of vanadium and 44 grams oxygen.

[Superfresh602]

thanks bro! i was stuck on a problem with 11.66 grams of iron and 5.01 grams of oxygen so it was kind of similar and i ended up with fe2o3 and i got 1.5 moles and i was stuck, i saw your graph and multiplied by 2 and i got it. the teacher didn't tell me but you did so thanks. also i was going to ask if fe3o4 existed but apparently its Iron(II,III) oxide

[whitwellhigh]

@Superfresh602 - glad to see you made head way in your problem :)

[SH1LOB]

Thank you very much sire

[l0oserr]

youre so smart! thanks for enlighting my mind its been two years since i took chem

[Darkish04]

What would be the lowest boundary of values you would not times by?

[blueredpinkgreen1]

im in AP chem at my high school wanted a good refresher and your vids did me well thanks :D

[Sheba4taj1]

You and your sexy Southern accent have Really helped me. Thank you

[bcharris1990]

Very well done! This helped me out alot! Keep it up!

[potato11teen]

roll tide

[95siddarth]

But doesn't oxygen occur as a diatomic molecule?

[whitwellhigh]

@95siddarth - it sure does :).....when doing these problems....it is just easier to pretend that each atom is single even if it is diatomic.......Pretending in this way...will allow you not to have to think....now did I multiply that by two....besides if we got something like Na2CO3....notice here that we do not see a 2 on the oxygen....so just go ahead and PRETEND it is a single O-atom.

[Nrisagieri]

very good dude, and by the way I like your accent :) where are you from?

[whitwellhigh]

@Nrisagieri - Tennessee my man :)

[nealon14]

Helped alot thanks.

[HELLOOOOOSPPLZ]

dood thx so much fr these vids im learning hella XD

[watatatow]

Thank you very much for this!

[m180322]

I sell propane and propane accessories

[nickrohn93]

@m180322 That is incredibly interesting, I extend my gratitude for sharing that with us.

[radiacto]

1.12 g of iron reacted with chlorine to form 3.25 g of a compound.

What is the empirical formula of the compound?

(Relative atomic masses: Cl = 35.5; Fe = 56)

A FeCl2

B FeCl3

C Fe3Cl

If someone could please explain and give me the answer to this it would be much appreciated, thanks!

D Fe2Cl9

[maardyuteSW9]

1.12 g of iron reacted with chlorine to form 3.25 g of a compound.

What is the empirical formula of the compound?

(Relative atomic masses: Cl = 35.5; Fe = 56)

A FeCl2

B FeCl3

C Fe3Cl

D Fe2Cl9

If anyone could tell me the answer and explain it it would be really helpful thank you

[Pooxer]

thank you very much

[amithabajan2]

Really helpful. Thanks from the uk

[Dice3579]

Thx soooo much!!!!! This helpped soo much!!!

[Sochocguy]

Lol. When ever he talks too loud it sounds like he is farting really loud!!!!

[whitwellhigh]

@Sochocguy - LOL!!!

[CrazyRusak]

Wassup Bitches! Great Video.

[operation931]

Thank you + Merci

[RomeoBELONGStoME]

i feel like your from texaaas!

good video though!:)

[mirandajack]

I hope no one actually sat through the whole eight minutes without skipping parts.

[whitwellhigh]

@mirandajack - for real LOL

[siffles93]

this was very helpful, thanks alot!!!!!

[isha566]

AHHH! THANK YOU, THANK YOU, THANK YOU! I wish you would teach my AP chem class. Life would be so much easier for me, haha.

[katy86xx]

thanks! really easy to follow and that chart is a lifesaver!

[N1NJ4Racing]

i ow you big time thanks so much you. just got me an A* (cheers)

[beatriXkibo]

love your voice... besides its just what i need to know for my test

[staysafe84]

chemestry is good.. maths not so much but its what i'm looking for

[BMXlover93]

allow this guys ghetto calculator ahaha

[ltrizzle84]

.11? nice video. ty.

[whitwellhigh]

what do you mean .11?.....I looked and do not see.....11 LMAO....could you explain more...

[ltrizzle84]

@whitwellhigh yeah it was for a problem I was working on. silver sulfide. 2.00g Ag and 0.30g S. I ended up dividing the Ag m.m by S and ended up with 1 mol S and 2.11 mol Ag.

[AV917]

Thanks so much passed the midterm

[AV917]

Very nice thank you

[whats12345aa]

thnx for the video... learnt a good technique for the exam!!!!

[Keeponhuggin]

Thanks man, I needed a refresher.

[megziiee17]

Thanks, gr8 help :)

[DoubleAgent244]

thank you. perfect fore my upcoming midterm

[HarrisonVR]

Nice video, very informative and well explained. Thank you for the help.

[jallen090193]

I learned more in 8:11 seconds just now than I have in the last 5 months at college, we need people like you to teach in england haha, thanks very much, really helpful x

[Fevercow09]

This was actually very helpful, thankyou.

[davey1027]

thank you very much, this should help me on my hydrate lab

[Pianoguyjr]

Excellent video! This video has helped so much.

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[123genetic]

that chart just got me an A+

THANX!!!

[whitwellhigh]

I am very happy.....that you got an A+....be sure to tell all your friends that these videos helped you........Good Luck....

[whitwellhigh]

Thank you...I am glad I helped you....:)

[abdi5501boone]

Am guessing you are from down south :)!

thanks for all your help you are wonderful :) and are alot funner than reading the book lol