xp’(kx) = -p(x)/k^2 is the correct differential equation in the slide at 20:00. This is given in the transcript.
LeavingCertMaths 4 months ago
xp’(kx) = -p(x)/k^2 is the correct differential equation in the slide at 20:00. This is given in the transcript.
LeavingCertMaths 4 months ago