First of all you have to read your oponent and try to guess what is his hand... than you aply the odds and compare to see who (you or him) has the most probability to win, thats why its important besides it is really hard and boring for someones.
and why do we have to know this? lol.. and what are the chances of getting a four of a kind with a pocket, and what are the chances of getting royal flush with QK suited and what are the chances of getting a straight flush with 23 suited and what with A2 suited?? why don't you tell us that?
Pardon my ignorance, as I am new to the sport of poker, but how does knowing this actually help you? Is it supposed to help you decide when to fold or bet to the river?
the chance of getting two 9 is: 4/52 * 3/51 wich is approx: 0,5%.
the chance of getting two pairs, no matter what pair, is: 3/51 wich is approx: 5.9% or 1 every 16 hands. don't trust these videos if u want money, look for a course in mathematics.
Well, she referred to pocket pairs first, which has a fairly good percentile, but when she went on to the pocket aces, she said something like 1/222 hands you'll get it. She referred to it because it is the best possible pocket pair you can have, and because there are only 4 of those cards in the deck, the chances of you getting those SPECIFIC cards are that ratio. The first time she mentioned it, she was talking about pocket pairs in general.
1/17 chance of getting pockets, 13 different pocket hands 17*13=221, 1/221 of getting 1 certain pocket pair (example A's). But she said 1/222, so they obvioiusly rounded at once point when they put it to decimals, no biggie.
I don't get it. There are 13 types of cards in a deck, 4 of each number. So, the odds that you'd get a particular card, say a 9 is 1/13. The chances that you'd get two 9s is thus 1/26, which is 3.8% on a given deal. Where do they get 5.8%?
The change of getting two 9's is 1/221, lol, same as Aces. You can just double it to get your fraction right. The change of getting any pocket pair is 100% of getting any card (example a Jack), and then there's 3 Jacks left for the 2nd card, and 51 cards left in the deck. 3/51 = 1/17 change of any Pocket pair.
yeah, that's true. but you can't assume that players have or don't have the spade or club what ur drawing to.. It makes it to complicated, so best to play the odds like you're the only one in the game.
First of all you have to read your oponent and try to guess what is his hand... than you aply the odds and compare to see who (you or him) has the most probability to win, thats why its important besides it is really hard and boring for someones.
1segundo 1 year ago
and why do we have to know this? lol.. and what are the chances of getting a four of a kind with a pocket, and what are the chances of getting royal flush with QK suited and what are the chances of getting a straight flush with 23 suited and what with A2 suited?? why don't you tell us that?
Pomonoli 1 year ago
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sienipata 2 years ago
Pardon my ignorance, as I am new to the sport of poker, but how does knowing this actually help you? Is it supposed to help you decide when to fold or bet to the river?
DarkCloudedSoul 2 years ago
what are the odds od ROYAL FLUSH?
USERNAMEKLEMPTOR 2 years ago
1 in 649740 hands
bigzacaq 2 years ago
@bigzacaq actually the ODDS are 649739 to 1.
RussellsParadox 1 year ago
La probabilidad de sacar CUALQUIER PAR es la misma, no porque en la carta diga "A" en vez de "9" va a cambiar la probabilidad...
vaico 2 years ago
the chance of getting two 9 is: 4/52 * 3/51 wich is approx: 0,5%.
the chance of getting two pairs, no matter what pair, is: 3/51 wich is approx: 5.9% or 1 every 16 hands. don't trust these videos if u want money, look for a course in mathematics.
notengonickcojones 2 years ago
ANY pocket pair is 5.8..
chadkwong 2 years ago
what are u talking about? stupid, i'm physicist don't try to teach me anything.
notengonickcojones 2 years ago
Comment removed
chadkwong 2 years ago
Because a physicist clearly trumps any other field that would utilize math.
lostcause31 2 years ago
why u multiply there by 3/51?
MrLoouie86 2 years ago
dont worry i got it lol
MrLoouie86 2 years ago
chance, can't* sorry for the spelling
SuperChuck3 2 years ago
Yeah, I see you're right. It was just a quick reply at the time, I don't guess I actually stopped to think about it. Thanks man.
jmb765 2 years ago
Comment removed
SuperChuck3 2 years ago
OK... i get it. You are right :)
ganky6 3 years ago
I dont get it either.
Why is the chance higher to get two 9's than two Aces?
There are 4 Aces in a 52 deck and 4 9's in a 52 deck... so why are the odds different???
ganky6 3 years ago
no it meant any pocket pair, not necaserily a pair of 9's but they just used that as an example for a pocket pair
saintsrulethegay 3 years ago
Well, she referred to pocket pairs first, which has a fairly good percentile, but when she went on to the pocket aces, she said something like 1/222 hands you'll get it. She referred to it because it is the best possible pocket pair you can have, and because there are only 4 of those cards in the deck, the chances of you getting those SPECIFIC cards are that ratio. The first time she mentioned it, she was talking about pocket pairs in general.
jmb765 3 years ago
1/17 chance of getting pockets, 13 different pocket hands 17*13=221, 1/221 of getting 1 certain pocket pair (example A's). But she said 1/222, so they obvioiusly rounded at once point when they put it to decimals, no biggie.
SuperChuck3 2 years ago
First card doesn't matter. Second card is then 3 out of 51. So to hit a set: 1 x 3/51 = 5.88%.
jurgen1980 3 years ago
to hit a pair of course, not a set.
jurgen1980 3 years ago
I don't get it. There are 13 types of cards in a deck, 4 of each number. So, the odds that you'd get a particular card, say a 9 is 1/13. The chances that you'd get two 9s is thus 1/26, which is 3.8% on a given deal. Where do they get 5.8%?
dmed312 3 years ago
yeah but their is only 3 nines if u already have one.
djax4mvp 3 years ago
The change of getting two 9's is 1/221, lol, same as Aces. You can just double it to get your fraction right. The change of getting any pocket pair is 100% of getting any card (example a Jack), and then there's 3 Jacks left for the 2nd card, and 51 cards left in the deck. 3/51 = 1/17 change of any Pocket pair.
SuperChuck3 2 years ago
they say the chance of getting any pocket pair , not two 9`s.
hyppEreL 2 years ago
how come the chances of flopping a set or better are bigger than just flopping a set????
I think they messed up there, or there's some factor that I'm not counting...
miltonlandriel 3 years ago
yeah, that's true. but you can't assume that players have or don't have the spade or club what ur drawing to.. It makes it to complicated, so best to play the odds like you're the only one in the game.
KrazyKai101 3 years ago
Comment removed
osoverride 4 years ago
Yeh Its a good video for beginners, but it doesnt state the number of players in the game, which would obviously affect the odds shown in the video.
vrishie 4 years ago
no it wouldn't, if nobody had what u were looking for than ur odds would increase. the odds stay the same.
djax4mvp 3 years ago