Do you mean that there's no variable left? If that's the case, when we end up with something that's not true, like 3 = 25, then there is no solution. If you end up with something that is true, like 3 = 3, then it's an identity and all numbers will work.
what is the correct terminology for the action of moving the numerator from a fraction on one side of an equation over a whole expression on the other side, such as A/P=1+rt TO P=A/1+rt?
You are awesome! I literally understood this more in 8 minutes hearing you explain this than hearing my teacher repeat it over and over to the class for about four days.
@MyScooby28 Start by combining like terms: 13x + 9 - 4 = 12x - 3 13x + 5 = 12x - 3 Then get all the variables on the same side. I'll subtract 12x from both sides. 13x - 12x + 5 = 12x - 12x - 3 x + 5 = -3 Finally, subtract five from both sides to get the x by itself. x + 5 - 5 = -3 - 5 x = -8 I hope that helps! :-)
I haz a question... im in algebra one and im doing the exact same stuff, but im wondering that you know how theres numbers with variables on each side? which one do you do first or does it not matter?
The 1/2 means that you multiply the (6-z) by 1/2. So you multiply everything inside the (6-z) by 1/2.
1/2(6-z) = z
1/2*6 + 1/2*-z =z
3 -1/2*z =z
Now we want the variables on one side and the number on the other. We already have a z on the right side so it is more helpful to leave it and change the left side so that zs stay on the right.
hey mbrandl11 this is a good video but i have a question, lets say i havea problem set up like this: 5x+20=4x+30
how would I get the x's on one side, would both the 5x and the 4x be considered as possitives? and if so would this mean that i have to subtract one from another instead of add??
I now know this...... YES! I better get an A for sure. x__x
superstarcity98 3 weeks ago
Thanks for the help
peterjgagnon 1 month ago
do you have a fractions version of this?
noobwerd 2 months ago
@noobwerd
Search my videos for "solving & fractions" and I think you might find some helpful things to check out.
I hope that helps! :-)
mbrandl11 2 months ago
What happens if the number cant divide?
So like what if was 3 = 25
What would you do?
frostybearx 3 months ago
@frostybearx
Do you mean that there's no variable left? If that's the case, when we end up with something that's not true, like 3 = 25, then there is no solution. If you end up with something that is true, like 3 = 3, then it's an identity and all numbers will work.
I hope that helps! :-)
mbrandl11 2 months ago
Seriously I know this but I need help with this one: -35-5(x-3)=x+2(x-2)
gerardo95062 3 months ago
@gerardo95062
Start by distributing the -5 and the 2 through on the left and right respectively.
-35 - 5x + 15 = x + 2x - 4
Then combine like terms
-20 - 5x = 3x - 4
I bet you can take it from there! I hope that helps! Keep working hard! :-)
mbrandl11 3 months ago
hello , i was wondering if you can help me with a probem ,? its 0.2(7+2t)=0.4t+1.4
i tried to follow the steps on this video but it kinda of confused me .
origMELSIEandGISA 3 months ago
@origMELSIEandGISA
Start by distributing on the left to get rid of the parenthesis.
1.4 + 0.4t = 0.4t + 1.4
Subtract 0.4t from both sides to get the variables to the same side.
1.4 + 0.4t - 0.4t = 0.4t - 0.4t + 1.4
1.4 = 1.4
The variable is gone! Since 1.4 is indeed equal to 1.4, the solution is all numbers, or an identity.
I hope that helps! I do have a video explaining more about this situation if you'd like to see more. :-)
mbrandl11 3 months ago
what about with fractions
spartanking32i 4 months ago
@spartanking32i
Check out my video "Solving Multi-Step Equations with Fractions" for a number of examples.
mbrandl11 4 months ago
I got it
A-P=Prt divide by P
A/P-P/P=Prt/P Solve
A/P-1=rt add 1 to both sides
A/P=1+rt transpose
P=A/1+rt
:-)
rugggus 1 year ago
@rugggus
Nice work! :-)
mbrandl11 1 year ago
@mbrandl11
what is the correct terminology for the action of moving the numerator from a fraction on one side of an equation over a whole expression on the other side, such as A/P=1+rt TO P=A/1+rt?
Thank You
rugggus 1 year ago
@rugggus
You're basically taking the cross products and then solving for P.
mbrandl11 1 year ago
@rugggus
test
rugggus 1 year ago
I am suppose to solve for P
the formula is A-P=Prt
I even know the answer is suppose to be P=A/1+rt but don't know how to get there
I get to P=A-Prt
How do I solve for P without canceling it out???
rugggus 1 year ago
please help me!!! 3(4x-2) = 12x
TheBeast2456 1 year ago
@TheBeast2456
Use the distributive property to get rid of the parenthesis.
3(4x - 2) = 12x
12x - 6 = 12x
Get all the variables on the same side by subtracting 12x and simplifying.
12x - 12x - 6 = 12x - 12x
-6 = 0
When the variables all cancel out and we're left with something that is not true, in this case, -6 is not equal to 0, the equation has no solution.
If the variables all cancel out and we're left with something that is true, like 3 = 3, then all numbers will work!
mbrandl11 1 year ago
mr. mbrandl11 can you help me solve this? -3+2y=y+10
chimpo80S 1 year ago
@chimpo80S
Start by getting all the variables on the same side by subtracting y from both sides.
-3 + 2y - y = y - y + 10
-3 + y = 10
Then get the y by itself by adding 3 to both sides.
-3 + 3 + y = 10 + 3
y = 13
I hope that helps! :-)
mbrandl11 1 year ago
You are awesome! I literally understood this more in 8 minutes hearing you explain this than hearing my teacher repeat it over and over to the class for about four days.
ThunderclanWarrior6 1 year ago
@ThunderclanWarrior6
I'm glad you found it helpful! :-)
mbrandl11 1 year ago
This has been flagged as spam show
Please help me with solving this problem
13x + 9 - 4= 12x-3
MyScooby28 1 year ago
Please help me with solving this problem
13x + 9 - 4= 12x-3
MyScooby28 1 year ago
mbrandl11 1 year ago
I haz a question... im in algebra one and im doing the exact same stuff, but im wondering that you know how theres numbers with variables on each side? which one do you do first or does it not matter?
apregnantbaby26 1 year ago
@apregnantbaby26
It doesn't matter. The key is getting all the variables on the same side of the equation.
mbrandl11 1 year ago
thanks for posting, its really easy to understand
aedododingdona 1 year ago
man i am passing all of my test because of u
blazingflame09 2 years ago
urm hey! cn u plz help mee? wat f i had da eq. 1/2(6-z)=z ? wat do i do ?
do i put a 1 nxt 2 da z on da right side then solve it?
aprilcute08 2 years ago
The 1/2 means that you multiply the (6-z) by 1/2. So you multiply everything inside the (6-z) by 1/2.
1/2(6-z) = z
1/2*6 + 1/2*-z =z
3 -1/2*z =z
Now we want the variables on one side and the number on the other. We already have a z on the right side so it is more helpful to leave it and change the left side so that zs stay on the right.
3 - 1/2*z = z + 1/2*z = +1/2*z
3= 1.5 z
3/1.5 = 1.5/1.5z
2 = 1z
2=z
aconblu 2 years ago
Thanks!!
Can u do a vid about the same thing but fractions?
weywey0407 2 years ago
you have a very clear style and it helped me - Thanks.
higher17 2 years ago
Could you show examples of how to do equations like this: 6(t-5)=2(t+5).
Please I need so serious help.
unleashed13579 3 years ago
Check out my video entitled:
Lesson 7-5: Solving Equations With Variables on Both Sides
mbrandl11 3 years ago
no responce to my question??>=(
gtoutofthawrld 3 years ago
Sorry, I've been a little under the weather.
mbrandl11 3 years ago
hey mbrandl11 this is a good video but i have a question, lets say i havea problem set up like this: 5x+20=4x+30
how would I get the x's on one side, would both the 5x and the 4x be considered as possitives? and if so would this mean that i have to subtract one from another instead of add??
gtoutofthawrld 3 years ago
Exactly! You could subtract 4x from both sides, or subtract 5x from both sides, either way.
mbrandl11 3 years ago
o.k, THANKYOU!, i just neede to confirm that, I hope you get better man!
gtoutofthawrld 3 years ago