Problem involving angle derived from square and circle

[PmQable1]

how do u have such neat handwriting on a computer

[DeltaRazor]

@PmQable1 wacom, i guess...

[rhoadess]

Okay this is how I did it when I paused before the hint: It's the long way around. let the radius = 1 = mAB ; then mBG = 1/2 ⇒ ∆EBG is a 30-60-90 ⇒ m∠EBG = 60° ⇒ m∠EBA = 30° ⇒ ∆BAE is isosceles ⇒ m∠BAE = 75° = m∠BEA ⇒ m∠EAF = 15° Now mAE = mED ⇒ ∆ AED is isosceles so m∠EDF =15° ⇒ m∠AED = 180° - 30° = 150°; m∠AED + m∠BEA = 225°∴ 360-225= m∠BED = 135° Oy now i can go to BED.

[nodariel]

You are the best mathemagician I know.

[ggmm117]

Can you make a video about STAR TREK THEOREM and TANGENT CHORD THEOREM

[GetMeThere1]

I wonder what can be said, strictly from geometry (without trigonometry) about the maximum distance between line EC and the circle? Line EC, of course, is one side of a hexagon "fully" inscribed in circle B (i.e., the largest hexagon that can fit in circle B). I wonder what can be said about the maximum distances between regular polygons and circles they're inscribed in--without involving trig or calculus....

[PedroGynVibes]

@GetMeThere1 It's the same as asking the radius of the incircle... if I'm not mistaken there's a relation between polygon areas and the radius of the incircle.

[GetMeThere1]

Nice! Ain't life grand?!?!

[PmSolier]

math be so sexy.

[griftorifto2]

Gotta love the feeling when you solve one of these.

[saminm1]

Awesome. Couldn't do it from the beginning but now i understand it thanks to you.

[ro33han]

fourth, and it feels good.

[RockandRoll21395]

khan your the man btw

[WHIREAS]

@RockandRoll21395 you're*.

[RockandRoll21395]

first....again